23_InstSolManual_PDF_Part21

23_InstSolManual_PDF_Part21 - glass g S 0° b S 90° A S...

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23.79. Set Up: Solve: is constant, so and Reflect: Increasing the refractive index decreases the angle of refraction and causes the ray to be bent more when it refracts into the glass. 23.80. Set Up: If is the critical angle then For air, For heart muscle, Solve: (a) gives and (b) gives 23.81. Set Up: The rays are incident on the prism in the normal direction so they do not change direction as they enter the prism. Apply Snell’s law to the refraction of the rays as they exit the prism. The rays are sketched in Fig- ure 23.81. The angle between the two rays after they emerge from the prism is Figure 23.81 Solve: The angle of incidence is gives so The angle between the emerging rays is Reflect: If and The rays remain parallel if the prism is replaced by a rectangular slab of glass.
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Unformatted text preview: glass. g S 0°. b S 90° A S 0°, 2 g 5 39.1°. 19.55°. g 5 90° 2 A 2 b 5 90° 2 25.0° 2 45.45° 5 g 1 b 1 A 5 90°, b 5 90° 2 u b 5 45.45°. u b 5 44.55°. 1 1.66 2 sin 1 25.0° 2 5 1 1.00 2 sin u b . n a sin u a 5 n b sin u b A 5 25.0°. A A A b g g u b 2 g . u crit 5 13.4°. 1 1.00 2 sin u crit 5 1 0.2324 2 sin 90° u b 5 46.7°. sin u b 5 sin 1 9.73° 2 0.2324 1 1.00 2 sin 1 9.73° 2 5 1 0.2324 2 sin u b . n a sin u a 5 n b sin u b n mus 5 344 m / s 1480 m / s 5 0.2324. n air 5 1.00. u b 5 90°. u a n a sin u a 5 n b sin u b . u b 2 5 25.7°. 1 2 sin 60.0°. sin u b 2 5 n b 1 n b 2 sin u b 1 5 n 2 n sin 60.0° 5 n b 2 5 2 n . n b 1 5 n n b 1 sin u b 1 5 n b 2 sin u b 2 . n a sin u a n a sin u a 5 n b sin u b Electromagnetic Waves 23-21...
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