PHYS
24_InstSolManual_PDF_Part7

# 24_InstSolManual_PDF_Part7 - Geometric Optics 24-7 Solve(a...

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Solve: (a) and The image is 10.0 cm to the left of the shell vertex and is 2.20 mm tall. (b) The image is 4.29 cm to the right of the shell vertex and is 0.944 mm tall. Reflect: In (a), and the mirror is concave, so the image is real. In (b) the image is virtual because a convex mirror always forms a virtual image. 24.18. Set Up: and and An erect image must be virtual. Solve: (a) and For a concave mirror, m can be larger than 1.00. For a convex mirror, so and m is always less than 1.00. The mirror must be concave (b) and The principal ray diagram is drawn in Figure 24.18. Figure 24.18 24.19. Set Up: For a convex surface, Solve: (a) The image is 8.00 cm to the right of the vertex. (b) The image is 13.7 cm to the right of the vertex. (c) The image is 5.33 cm to the left of the vertex. s r 5 2 5.33 cm. 1.00 2.00 cm 1 1.60 s r 5 1.60 2 1.00 3.00 cm . s 5 2.00 cm. s r 5 1 13.7 cm. 1.00 12.0 cm 1 1.60 s r 5 1.60 2 1.00 3.00 cm . s 5 12.0 cm. s r 5 1 n b n b 2 n a 2 R 5 1 1.60
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Unformatted text preview: 1.60 2 1.00 2 1 1 3.00 cm 2 5 1 8.00 cm. n b s r 5 n b 2 n a R . s S ` . n a s 1 n b s r 5 n b 2 n a R . n b 5 1.60. n a 5 1.00, R 5 1 3.00 cm. R . 0. Object Image F C 1 3 4 2 R 5 2 f 5 1 5.00 cm. f 5 s 1 2 2.00 s 2 s 2 2.00 s 5 1 2.00 s 5 1 2.50 cm. s r 5 2 2.00 s . m 5 2 s r s 5 1 2.00 f 5 ss r s 1 s r . 1 f 5 s r 1 s ss r . 1 f . 2 . m 5 1 f s 1 f f 5 2 f m 5 2 f s 2 f . s r 5 sf s 2 f s 5 1.25 cm. m 5 1 2.00 m 5 y r y 5 2 s r s . 1 s 1 1 s r 5 1 f s . R / 2 y r 5 my 5 0.944 mm. m 5 2 2 4.29 cm 15.0 cm 5 1 0.286. s r 5 1 12.0 cm 21 15.0 cm 2 30.0 cm 1 12.0 cm 5 2 4.29 cm. R 5 2 12.0 cm. y r 5 my 5 2 2.20 mm. m 5 2 s r s 5 2 10.0 cm 15.0 cm 5 2 0.667. s r 5 Rs 2 s 2 R 5 1 12.0 cm 21 15.0 cm 2 30.0 cm 2 12.0 cm 5 1 10.0 cm. 1 s r 5 2 R 2 1 s 5 2 s 2 R Rs R 5 1 12.0 cm. Geometric Optics 24-7...
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• Spring '07
• Shoberg
• Trigraph, GEOMETRIC OPTICS

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