24.30. Set Up: Since the image is inverted, and Solve: gives gives and The object is 154 cm to the left of the lens. The image is 217 cm to the right of the lens and is real. 24.31. Set Up: Since the image is projected onto a wall, the image is real and and both s and are positive, so The height of the image is three times the height of the object, so and Solve: (a) so You are 0.60 m from the lens. (b) so the image is inverted. (c) and the lens is converging. Reflect: Since the image is real the lens must be converging and your distance from the lens must be greater than the focal length. 24.32. Set Up: The type of lens determines the sign of The sign of depends on whether the image is real or virtual. is positive because the image is on the side of the lens opposite to the object. Solve: (a) and is positive so the lens is converging. (b) The image is 1.88 mm tall. and the image is real. 24.33. Set Up:
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.