24_InstSolManual_PDF_Part13

24_InstSolManual_PDF_Part13 - R 1 5 2 4.00 cm f c 5 2 4.44...

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Solve: (a) and The image is 107 cm to the right of the lens and is 17.8 mm tall. The image is real and inverted. (b) and The image is the same as in part (a). Reflect: Reversing a lens does not change the focal length of the lens (Problem 24.44). 24.42. Set Up: For a distant object the image is at the focal point of the lens. Therefore, For the double-convex lens, and where Solve: 24.43. Set Up: Each surface could have a positive or a negative radius of curvature, so there are four distinct shapes. The four possible shapes are sketched in Figure 24.43. Figure 24.43 Solve: lens a : lens b : lens c : lens d : Each lens could also be reversed, but that doesn’t change its focal length. 24.44. Set Up: When we reverse the lens, and Solve: If is the focal length with the lens reversed, as was to be shown. 1 f r 5 1 n 2 1 2 1 1 2 R 2 2 1 1 2 R 1 22 5 1 n 2 1 2 1 1 R 1 2 1 R 2 2 5 1 f , f r 1 f 5 1 n 2 1 2 1 1 R 1 2 1 R 2 2 . R 2 S 2 R 1 . R 1 S 2 R 2 f d 5 2 13.3 cm. R 2 5 2 8.00 cm. R
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Unformatted text preview: R 1 5 2 4.00 cm, f c 5 2 4.44 cm. R 2 5 1 8.00 cm. R 1 5 2 4.00 cm, f b 5 1 4.44 cm. R 2 5 2 8.00 cm. R 1 5 1 4.00 cm, f a 5 1 13.3 cm. R 2 5 1 8.00 cm. R 1 5 1 4.00 cm, (a) (b) (c) (d) 1 f 5 1 n 2 1 2 1 1 R 1 2 1 R 2 2 5 1 0.60 2 1 1 6 4.00 cm 2 1 6 8.00 cm 2 . n 5 R 2 f 1 1 5 2.50 cm 2 1 1.87 cm 2 1 1 5 1.67. 1 f 5 1 n 2 1 2 1 1 R 1 2 1 R 2 2 5 1 n 2 1 2 1 1 R 2 1 2 R 2 5 2 1 n 2 1 2 R . R 5 2.50 cm. R 2 5 2 R , R 1 5 1 R f 5 1.87 cm. f 5 18.6 cm. 1 f 5 1 n 2 1 2 1 1 13.0 cm 2 1 ` 2 y r 5 my 5 1 2 4.76 21 3.75 mm 2 5 2 17.8 mm. m 5 2 s r s 5 2 107 cm 22.5 cm 5 2 4.76. s r 5 sf s 2 f 5 1 22.5 cm 21 18.6 cm 2 22.5 cm 2 18.6 cm 5 107 cm. 1 s r 5 1 f 2 1 s 5 s 2 f sf . f 5 18.6 cm. 1 f 5 1 0.70 2 1 1 ` 2 1 2 13.0 cm 2 5 0.70 13.0 cm Geometric Optics 24-13...
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