24_InstSolManual_PDF_Part15

24_InstSolManual_PDF - Geometric Optics 24-15(c f1 5 240.0 cm f2 5 260.0 cm I1 is as calculated in part(b sr 5 2 1 322.2 cm 2 1 260.0 cm 2 s2 f2 5

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(c) is as calculated in part (b). The final image is 50.6 cm to the left of the second lens (249.4 cm to the right of the first lens), is upright and is 0.0837 cm tall. 24.47. Set Up: The image formed by the first lens serves as the object for the second lens. gives Solve: (a) Lens 1: Lens 2: The image of lens 1 is 7.5 cm to the left of lens 1 so is to the left of lens 2. The final image is 44.0 cm to the right of lens 2 so is 53.0 cm to the right of the first lens. (b) so the final image is real. (c) The image is 2.50 mm tall and is inverted. Reflect: The light travels through the lenses in the direction from left to right. A real image for the second lens is to the right of that lens and a virtual image is to the left of the second lens. 24.48. Set Up: The image formed by the first lens serves at the object for the second lens. gives Solve: (a) and Lens 1: The image of the first lens is 158 cm to the right of lens 1 and is 17.6 mm tall. (b)
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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