24_InstSolManual_PDF_Part21

24_InstSolManual_PDF_Part21 - Reflect The focal length of...

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24.57. Set Up: Rays that pass through the hole are undeflected. All other rays are blocked. Solve: (a) The ray diagram is drawn in Figure 24.57. The ray shown is the only ray from the top of the object that reaches the film, so this ray passes through the top of the image. An inverted image is formed on the far side of the box, no matter how far this side is from the pinhole and no matter how far the object is from the pinhole. Figure 24.57 (b) The image is 2.4 cm tall. Reflect: A defect of this camera is that not much light energy passes through the small hole each second, so long exposure times are required. 24.58. Set Up: Solve: and The object is a distance of in front of the mirror and the image is a distance of behind the mirror. 24.59. Set Up: Since the image is projected onto the wall it is real and so m is negative and The object, mirror and wall are sketched in Figure 24.59. The sketch shows that Figure 24.59 Solve: and and The mirror should be 7.20 m from the wall.
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Unformatted text preview: Reflect: The focal length of the mirror is as it must if the image is to be real. 24.60. Set Up: Since the image is projected onto a screen the image is real and so m is negative; m 5 2 36.0 cm 0.600 cm 5 2 60.0. m 5 2 s r s s r 5 800 cm. s r . 0. s . f , f 5 R / 2 5 222 cm. R 5 4.43 m. 1 320 cm 1 1 720 cm 5 2 R . 1 s 1 1 s r 5 2 R . 320 cm 5 720 cm. s r 5 400 cm 1 s 5 320 cm. s r 2 s 5 2.25 s 2 s 5 400 cm s r 5 2.25 s . m 5 2 2.25 5 2 s r s s 9 s Wall Object s r 2 s 5 400 cm. m 5 2 2.25. m 5 2 s r s s r . 0. 0.750 R 0.300 R 1 2 2.50 21 0.300 R 2 5 2 0.750 R . s r 5 2 2.50 s 5 s 5 0.300 R . 0.600 s 5 2 R 1 s 1 1 2 2.50 s 5 2 R . s r 5 2 2.50 s . m 5 2 s r s 5 1 2.50. R . 0. 1 s 1 1 s r 5 2 R . m 5 1 2.50. y r 5 my 5 1 2 0.133 21 18 cm 2 5 2 2.4 cm. m 5 2 s r s 5 2 20.0 cm 150 cm 5 2 0.133. s r 5 20.0 cm. s 5 1.5 m. s 9 s Object Image Geometric Optics 24-21...
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