24_InstSolManual_PDF_Part22

24_InstSolManual_PDF_Part22 - 2 R . s S ` . y r 5 m y 5 1...

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Solve: (a) (b) 24.61. Set Up: Use to find R . For this calculation, and Then repeat the calculation with Solve: gives Then gives The image is 72.1 cm to the left of the surface vertex. Reflect: With the rod in air the image is real and with the rod in water the image is virtual. 24.62. Set Up: The mirror surface is convex so Solve: The image is 1.40 cm behind the surface so it is from the center of the ornament, on the same side as the object. 24.63. Set Up: (glass). Solve: and 24.64. Set Up: The positions of the object, lens and screen are sketched in Figure 24.64. Since the image is projected onto a screen, the image is real and The figure shows that and Figure 24.64 Object 18.0cm s 9 s Lens Screen s r 5 18.0 cm 2 s . s r 1 s 5 18.0 cm s r . 0. f 51 3.00 cm. n 5 2.00. 1 R 5 n 2 R n 2 R 5 n 2 1 R . n a s 1 n b s r 5 n b 2 n a R . n b 5 n n a 5 1.00. s r 51
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Unformatted text preview: 2 R . s S ` . y r 5 m y 5 1 0.0667 21 3.80 mm 2 5 0.253 mm. m 5 2 s r s 5 2 2 1.40 cm 21.0 cm 5 1 0.0667. 3.00 cm 2 1.40 cm 5 1.60 cm s r 5 sf s 2 f 5 1 21.0 cm 21 2 1.50 cm 2 21.0 cm 2 1 2 1.50 cm 2 5 2 1.40 cm. 1 s 1 1 s r 5 1 f . f 5 R 2 5 2 1.50 cm. s 5 24.0 cm 2 3.00 cm 5 21.0 cm. R 5 2 3.00 cm. s r 5 2 72.1 cm. 1.55 2 1.33 2.50 cm 1.33 20.0 cm 1 1.55 s r 5 R 5 2.50 cm. 1.00 20.0 cm 1 1.55 9.12 cm 5 1.55 2 1.00 R . n a s 1 n b s r 5 n b 2 n a R n a 5 1.33. n b 5 1.55. n a 5 1.00 s r 5 1 9.12 cm R . 0. s 5 20.0 cm. R 5 26.2 cm. 1 13.3 cm 1 1 800 cm 5 2 R . 1 s 1 1 s r 5 2 R . s 5 s r 60.0 5 800 cm 60.0 5 13.3 cm. s r 5 60.0 s . m 5 2 60.0 5 2 s r s . 24-22 Chapter 24...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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