26_InstSolManual_PDF_Part2 - 26-2 Chapter 26 340.0 m s v 5...

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Solve: (a) Path difference is zero, so the interference is constructive. (b) Destructive interference, so the path difference equals and (c) Constructive interference, so path difference equals and 26.5. Set Up: When she is at the midpoint between the two speakers the path difference is zero. When she walks a distance d toward one speaker, increases by d and decreases by d , so the path difference changes by 2 d . Since the speakers are out of phase, gives destructive interference and gives constructive interference. Solve: (a) Path difference is zero, so the interference is destructive. (b) Destructive interference, so the path difference equals and (c) Constructive interference, so the path difference equals and Reflect: When she moves from a point of destructive interference to a point of constructive interference the path dif- ference changes by 26.6. Set Up: Since the values of m are rather large, don’t use Eq.(26.6). For bright fringes, For dark fringes, For the fifth bright fringe (not counting the central bright spot),
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  • Spring '07
  • Shoberg
  • Wavelength, path difference

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