(b) Extrapolation of the graph to gives so (c) The slope of the graph in (a) is 28.15. Set Up: The stopping potential is related to the frequency of the light by The slope of versus is The value of when is related to by Solve: (a) From the graph, Therefore, with the value of h from part (b), (b) From the graph, the slope is (c) No photoelectrons are produced for (d) For a different metal and are different. The slope is so would be the same, but the graph would be shifted right or left so it has a different intercept with the horizontal axis. Reflect: As the frequency of the light is increased above the energy of the photons in the light increases and more energetic photons are produced. The work function we calculated is similar to that for gold or nickel. 28.16. Set Up: The photon energy must equal the bond strength. Solve: so 28.17. Set Up: Balmer’s formula is where The line corresponds to Solve: (a) (b) (c) 28.18. Set Up: For the Lyman series the final state is and the wavelengths are given by
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