This preview shows page 1. Sign up to view the full content.
28.19. Set Up:
The wavelengths of the light for each line in one of the series is given by
where
for the Balmer series,
for the Lyman series and
for the Brackett series. The visible spectrum
extends from about 400 nm to 700 nm.
Solve: (a)
Balmer series
The longest wavelength is for
so
The shortest wavelength is for
so
Lyman series
The longest wavelength is for
so
The shortest wavelength is for
so
Brackett series
The longest wavelength is for
so
The shortest wavelength is for
so
(b)
The Balmer series is mostly in the visible. The Lyman series is in the ultraviolet and the Brackett series is in the
infrared.
Reflect:
From Problem 28.18, the wavelength range for the Paschen series
is 820 nm to 1875 nm. The
Lyman, Balmer and Paschen spectral series do not overlap in wavelength; the longest wavelength for one is shorter
than the shortest wavelength of the next. But, the Paschen series partially overlaps the Brackett series.
28.20. Set Up:
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.
 Spring '07
 Shoberg
 Photon

Click to edit the document details