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Unformatted text preview: This is what you want to maximize, so let a=-700, b=35000, so 25 $ 1400 35000 2 = = a b So the optimal ticket price is x=$25. (#1c) Using your model from part a, set s(x)=0 50 $ ) ( 700 35000 = = x x http://www.math.uri.edu/~bkaskosz/flashmo/fungraph/ As you can see, at x=25, the function has maximum value. Theoretically at x=50, no one would attend, and at x=0 you could sell 35,000 tickets but since price=0, revenue=0 #2:...
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This note was uploaded on 03/08/2009 for the course 640 115 taught by Professor Wey during the Fall '08 term at Rutgers.
- Fall '08