Quiz05_Solutions

# Quiz05_Solutions - Quiz 5 Solutions 1 Factor y =(3 x 2 x 2...

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Quiz 5 Solutions 1) Factor: ) 2 )( 2 3 ( + = x x y . So zeroes/x-intercepts are x=-2/3 and x=2 Vertex is at 3 / 16 ) 3 / 2 ( 3 / 2 ) 3 ( 2 / 4 2 / = = = = f a b x So vertex is at (2/3, -16/3). Since the lead term has a positive coefficient, the parabola opens upward. So given points (-2/3, 0), (2,0), and vertex (2/3, -16/3), we can graph as follows: 2) Factor denominator: ) 4 )( 3 ( + + x x . So vertical asymptotes are x=-3 and x=-4
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Unformatted text preview: x-intercept: Set numerator = 0. 3 , 2 ) 3 )( 2 ( = − = → = − + x x x x y-intercept: Set x=0, 5 . 12 / 6 ) ( − = − = f We want to find the horizontal asymptote, so we can multiply the numerator and denominator by 1/x^2: 2 2 2 2 2 2 12 7 1 6 1 1 12 7 6 1 1 x x x x x x x x x x + + − − = + + − − • . As x Æ ∞ ± f(x) Æ 1...
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• Fall '08
• WEY
• Division, horizontal asymptote, positive coefficient, Factor denominator, xx x2

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