Unformatted text preview: cen84959_ch10.qxd 9/15/06 6:02 AM Page 565 Chapter 10
VAPOR AND COMBINED POWER CYCLES
n Chap. 9 we discussed gas power cycles for which the working fluid remains a gas throughout the entire cycle. In this chapter, we consider vapor power cycles in which the working fluid is alternatively vaporized and condensed. We also consider power generation coupled with process heating called cogeneration. The continued quest for higher thermal efficiencies has resulted in some innovative modifications to the basic vapor power cycle. Among these, we discuss the reheat and regenerative cycles, as well as combined gas–vapor power cycles. Steam is the most common working fluid used in vapor power cycles because of its many desirable characteristics, such as low cost, availability, and high enthalpy of vaporization. Therefore, this chapter is mostly devoted to the discussion of steam power plants. Steam power plants are commonly referred to as coal plants, nuclear plants, or natural gas plants, depending on the type of fuel used to supply heat to the steam. However, the steam goes through the same basic cycle in all of them. Therefore, all can be analyzed in the same manner. I Objectives
The objectives of Chapter 10 are to: • Analyze vapor power cycles in which the working fluid is alternately vaporized and condensed. • Analyze power generation coupled with process heating called cogeneration. • Investigate ways to modify the basic Rankine vapor power cycle to increase the cycle thermal efficiency. • Analyze the reheat and regenerative vapor power cycles. • Analyze power cycles that consist of two separate cycles known as combined cycles and binary cycles.  565 cen84959_ch10.qxd 9/15/06 6:02 AM Page 566 566  Thermodynamics 10–1 ■ THE CARNOT VAPOR CYCLE We have mentioned repeatedly that the Carnot cycle is the most efficient cycle operating between two specified temperature limits. Thus it is natural to look at the Carnot cycle first as a prospective ideal cycle for vapor power plants. If we could, we would certainly adopt it as the ideal cycle. As explained below, however, the Carnot cycle is not a suitable model for power cycles. Throughout the discussions, we assume steam to be the working fluid since it is the working fluid predominantly used in vapor power cycles. Consider a steadyflow Carnot cycle executed within the saturation dome of a pure substance, as shown in Fig. 101a. The fluid is heated reversibly and isothermally in a boiler (process 12), expanded isentropically in a turbine (process 23), condensed reversibly and isothermally in a condenser (process 34), and compressed isentropically by a compressor to the initial state (process 41). Several impracticalities are associated with this cycle: 1. Isothermal heat transfer to or from a twophase system is not difficult to achieve in practice since maintaining a constant pressure in the device automatically fixes the temperature at the saturation value. Therefore, processes 12 and 34 can be approached closely in actual boilers and condensers. Limiting the heat transfer processes to twophase systems, however, severely limits the maximum temperature that can be used in the cycle (it has to remain under the criticalpoint value, which is 374°C for water). Limiting the maximum temperature in the cycle also limits the thermal efficiency. Any attempt to raise the maximum temperature in the cycle involves heat transfer to the working fluid in a single phase, which is not easy to accomplish isothermally. 2. The isentropic expansion process (process 23) can be approximated closely by a welldesigned turbine. However, the quality of the steam decreases during this process, as shown on the Ts diagram in Fig. 10–1a. Thus the turbine has to handle steam with low quality, that is, steam with a high moisture content. The impingement of liquid droplets on the turbine blades causes erosion and is a major source of wear. Thus steam with qualities less than about 90 percent cannot be tolerated in the operation of power plants.
T T 1 2 1 2 4 3 4 3 FIGURE 10–1 Ts diagram of two Carnot vapor cycles. s (a) (b) s cen84959_ch10.qxd 9/15/06 6:02 AM Page 567 Chapter 10
This problem could be eliminated by using a working fluid with a very steep saturated vapor line. 3. The isentropic compression process (process 41) involves the compression of a liquid–vapor mixture to a saturated liquid. There are two difficulties associated with this process. First, it is not easy to control the condensation process so precisely as to end up with the desired quality at state 4. Second, it is not practical to design a compressor that handles two phases. Some of these problems could be eliminated by executing the Carnot cycle in a different way, as shown in Fig. 10–1b. This cycle, however, presents other problems such as isentropic compression to extremely high pressures and isothermal heat transfer at variable pressures. Thus we conclude that the Carnot cycle cannot be approximated in actual devices and is not a realistic model for vapor power cycles.  567 10–2 ■ RANKINE CYCLE: THE IDEAL CYCLE FOR VAPOR POWER CYCLES INTERACTIVE TUTORIAL SEE TUTORIAL CH. 10, SEC. 1 ON THE DVD. Many of the impracticalities associated with the Carnot cycle can be eliminated by superheating the steam in the boiler and condensing it completely in the condenser, as shown schematically on a Ts diagram in Fig. 10–2. The cycle that results is the Rankine cycle, which is the ideal cycle for vapor power plants. The ideal Rankine cycle does not involve any internal irreversibilities and consists of the following four processes: 12 23 34 41 Isentropic compression in a pump Constant pressure heat addition in a boiler Isentropic expansion in a turbine Constant pressure heat rejection in a condenser
q in Boiler T 2 3 wturb,out Turbine 3 Pump 4 q out 2 1 Condenser 1 wpump,in s q out 4 q in wturb,out wpump,in FIGURE 10–2 The simple ideal Rankine cycle. cen84959_ch10.qxd 9/15/06 6:02 AM Page 568 568  Thermodynamics
Water enters the pump at state 1 as saturated liquid and is compressed isentropically to the operating pressure of the boiler. The water temperature increases somewhat during this isentropic compression process due to a slight decrease in the specific volume of water. The vertical distance between states 1 and 2 on the Ts diagram is greatly exaggerated for clarity. (If water were truly incompressible, would there be a temperature change at all during this process?) Water enters the boiler as a compressed liquid at state 2 and leaves as a superheated vapor at state 3. The boiler is basically a large heat exchanger where the heat originating from combustion gases, nuclear reactors, or other sources is transferred to the water essentially at constant pressure. The boiler, together with the section where the steam is superheated (the superheater), is often called the steam generator. The superheated vapor at state 3 enters the turbine, where it expands isentropically and produces work by rotating the shaft connected to an electric generator. The pressure and the temperature of steam drop during this process to the values at state 4, where steam enters the condenser. At this state, steam is usually a saturated liquid–vapor mixture with a high quality. Steam is condensed at constant pressure in the condenser, which is basically a large heat exchanger, by rejecting heat to a cooling medium such as a lake, a river, or the atmosphere. Steam leaves the condenser as saturated liquid and enters the pump, completing the cycle. In areas where water is precious, the power plants are cooled by air instead of water. This method of cooling, which is also used in car engines, is called dry cooling. Several power plants in the world, including some in the United States, use dry cooling to conserve water. Remembering that the area under the process curve on a Ts diagram represents the heat transfer for internally reversible processes, we see that the area under process curve 23 represents the heat transferred to the water in the boiler and the area under the process curve 41 represents the heat rejected in the condenser. The difference between these two (the area enclosed by the cycle curve) is the net work produced during the cycle. Energy Analysis of the Ideal Rankine Cycle
All four components associated with the Rankine cycle (the pump, boiler, turbine, and condenser) are steadyflow devices, and thus all four processes that make up the Rankine cycle can be analyzed as steadyflow processes. The kinetic and potential energy changes of the steam are usually small relative to the work and heat transfer terms and are therefore usually neglected. Then the steadyflow energy equation per unit mass of steam reduces to
1 qin qout 2 1 win wout 2 he h i 1 kJ> kg 2
(10–1) The boiler and the condenser do not involve any work, and the pump and the turbine are assumed to be isentropic. Then the conservation of energy relation for each device can be expressed as follows:
Pump (q 0): wpump,in h2 h1
(10–2) cen84959_ch10.qxd 9/15/06 6:02 AM Page 569 Chapter 10
or,
wpump,in v 1 P2 v1 h2 h4 h1 P1 2 vf @ P1
(10–3)  569 where
h1 Boiler (w Turbine (q Condenser (w 0): 0): 0): hf @ P1 and v qin wturb,out qout h3 h3 h4
(10–4) (10–5) (10–6) (10–7) The thermal efficiency of the Rankine cycle is determined from
h th wnet qin qout 1 qout qin wpump,in
(10–8) where
wnet qin wturb,out The conversion efficiency of power plants in the United States is often expressed in terms of heat rate, which is the amount of heat supplied, in Btu’s, to generate 1 kWh of electricity. The smaller the heat rate, the greater the efficiency. Considering that 1 kWh 3412 Btu and disregarding the losses associated with the conversion of shaft power to electric power, the relation between the heat rate and the thermal efficiency can be expressed as
h th Heat rate 1 Btu> kWh 2 3412 1 Btu> kWh 2
(10–9) For example, a heat rate of 11,363 Btu/kWh is equivalent to 30 percent efficiency. The thermal efficiency can also be interpreted as the ratio of the area enclosed by the cycle on a Ts diagram to the area under the heataddition process. The use of these relations is illustrated in the following example.
EXAMPLE 10–1 The Simple Ideal Rankine Cycle Consider a steam power plant operating on the simple ideal Rankine cycle. Steam enters the turbine at 3 MPa and 350°C and is condensed in the condenser at a pressure of 75 kPa. Determine the thermal efficiency of this cycle. Solution A steam power plant operating on the simple ideal Rankine cycle
is considered. The thermal efficiency of the cycle is to be determined. Assumptions 1 Steady operating conditions exist. 2 Kinetic and potential energy changes are negligible. Analysis The schematic of the power plant and the Ts diagram of the cycle are shown in Fig. 10–3. We note that the power plant operates on the ideal Rankine cycle. Therefore, the pump and the turbine are isentropic, there are no pressure drops in the boiler and condenser, and steam leaves the condenser and enters the pump as saturated liquid at the condenser pressure. cen84959_ch10.qxd 9/15/06 6:02 AM Page 570 570  Thermodynamics
First we determine the enthalpies at various points in the cycle, using data from steam tables (Tables A–4, A–5, and A–6): State 1: State 2: P2 h P1 75 kPa f 1 Sat. liquid v1 3 MPa s2 v1 1 P2 P1 2 s1 hf @ 75 kPa vf @ 75 kPa 384.44 kJ> kg 0.001037 m3> kg wpump,in 1 0.001037 m3> kg 2 3 1 3000 1 384.44 3.03 2 kJ> kg 75 2 kPa 4 a 3.03 kJ> kg h2 State 3: State 4: h1 wpump,in P3 T3 P4 s4 x4 h4
Thus, 1 kJ b 1 kPa # m3 3 MPa h f 3 350°C s3 s3 s4 sfg sf 75 kPa 1 sat. mixture 2 3116.1 kJ> kg 6.7450 kJ> kg # K 387.47 kJ> kg 6.7450 1.2132 6.2426 0.8861 1 2278.0 2 387.47 2 kJ> kg 384.44 2 kJ> kg 2018.6 kJ> kg 0.8861 2403.0 kJ> kg 2728.6 kJ> kg 2018.6 kJ> kg hf h3 h4 x4hfg h2 h1 384.44 1 3116.1 1 2403.0 qout qin 1 3116.1 qin qout
and h th 1 1 2728.6 kJ> kg 0.260 or 26.0% 713.1 kJ> kg The thermal efficiency could also be determined from wturb,out wnet
or h3 h4 wturb,out wpump,in 1 713.1 2403.0 2 kJ> kg 3.03 2 kJ> kg 710.1 kJ> kg wnet
and qin qout wnet qin 1 2728.6 2018.6 2 kJ> kg 710.0 kJ> kg h th 2728.6 kJ> kg 710.0 kJ> kg 0.260 or 26.0% That is, this power plant converts 26 percent of the heat it receives in the boiler to net work. An actual power plant operating between the same temperature and pressure limits will have a lower efficiency because of the irreversibilities such as friction. Discussion Notice that the back work ratio (rbw win /wout) of this power plant is 0.004, and thus only 0.4 percent of the turbine work output is required to operate the pump. Having such low back work ratios is characteristic of vapor power cycles. This is in contrast to the gas power cycles, which typically involve very high back work ratios (about 40 to 80 percent). cen84959_ch10.qxd 9/15/06 6:02 AM Page 571 Chapter 10
qin  571 Boiler 3 2 3 MPa 3 MPa 350°C wturb,out Turbine T, °C wpump,in Pump 350 75 kPa 4 3 qout
75 kP 2 1 75 kPa Condenser 1 s1 = s2 4 3M
a 75 kPa s3 = s4 Pa
s FIGURE 10–3 Schematic and Ts diagram for Example 10–1. It is also interesting to note the thermal efficiency of a Carnot cycle operating between the same temperature limits hth,Carnot 1 Tmin Tmax 1 1 91.76 1 350 273 2 K 273 2 K 0.415 The difference between the two efficiencies is due to the large external irreversibility in Rankine cycle caused by the large temperature difference between steam and combustion gases in the furnace. 10–3 ■ DEVIATION OF ACTUAL VAPOR POWER CYCLES FROM IDEALIZED ONES INTERACTIVE TUTORIAL SEE TUTORIAL CH. 10, SEC. 2 ON THE DVD. The actual vapor power cycle differs from the ideal Rankine cycle, as illustrated in Fig. 10–4a, as a result of irreversibilities in various components. Fluid friction and heat loss to the surroundings are the two common sources of irreversibilities. Fluid friction causes pressure drops in the boiler, the condenser, and the piping between various components. As a result, steam leaves the boiler at a somewhat lower pressure. Also, the pressure at the turbine inlet is somewhat lower than that at the boiler exit due to the pressure drop in the connecting pipes. The pressure drop in the condenser is usually very small. To compensate for these pressure drops, the water must be pumped to a sufficiently higher pressure than the ideal cycle calls for. This requires a larger pump and larger work input to the pump. The other major source of irreversibility is the heat loss from the steam to the surroundings as the steam flows through various components. To maintain the same level of net work output, more heat needs to be transferred to cen84959_ch10.qxd 9/15/06 6:02 AM Page 572 572  Thermodynamics
T IDEAL CYCLE Irreversibility in the pump Pressure drop in the boiler 3 3 2 ACTUAL CYCLE 4 1 1 Pressure drop in the condenser s (a) (b) 4s 4a Irreversibility in the turbine 2a 2s T s FIGURE 10–4 (a) Deviation of actual vapor power cycle from the ideal Rankine cycle. (b) The effect of pump and turbine irreversibilities on the ideal Rankine cycle. the steam in the boiler to compensate for these undesired heat losses. As a result, cycle efficiency decreases. Of particular importance are the irreversibilities occurring within the pump and the turbine. A pump requires a greater work input, and a turbine produces a smaller work output as a result of irreversibilities. Under ideal conditions, the flow through these devices is isentropic. The deviation of actual pumps and turbines from the isentropic ones can be accounted for by utilizing isentropic efficiencies, defined as
hP ws wa h 2s h 2a h3 h3 h1 h1 h 4a h 4s
(10–10) and
hT wa ws
(10–11) where states 2a and 4a are the actual exit states of the pump and the turbine, respectively, and 2s and 4s are the corresponding states for the isentropic case (Fig. 10–4b). Other factors also need to be considered in the analysis of actual vapor power cycles. In actual condensers, for example, the liquid is usually subcooled to prevent the onset of cavitation, the rapid vaporization and condensation of the fluid at the lowpressure side of the pump impeller, which may damage it. Additional losses occur at the bearings between the moving parts as a result of friction. Steam that leaks out during the cycle and air that leaks into the condenser represent two other sources of loss. Finally, the power consumed by the auxiliary equipment such as fans that supply air to the furnace should also be considered in evaluating the overall performance of power plants. The effect of irreversibilities on the thermal efficiency of a steam power cycle is illustrated below with an example. cen84959_ch10.qxd 9/15/06 6:02 AM Page 573 Chapter 10
EXAMPLE 10–2 An Actual Steam Power Cycle  573 A steam power plant operates on the cycle shown in Fig. 10–5. If the isentropic efficiency of the turbine is 87 percent and the isentropic efficiency of the pump is 85 percent, determine (a) the thermal efficiency of the cycle and (b) the net power output of the plant for a mass flow rate of 15 kg/s. Solution A steam power cycle with specified turbine and pump efficiencies
is considered. The thermal efficiency and the net power output are to be determined. Assumptions 1 Steady operating conditions exist. 2 Kinetic and potential energy changes are negligible. Analysis The schematic of the power plant and the Ts diagram of the cycle are shown in Fig. 10–5. The temperatures and pressures of steam at various points are also indicated on the figure. We note that the power plant involves steadyflow components and operates on the Rankine cycle, but the imperfections at various components are accounted for. (a) The thermal efficiency of a cycle is the ratio of the net work output to the heat input, and it is determined as follows: Pump work input: wpump,in ws,pump,in hp v1 1 P2 P1 2 hp 0.85 9 2 kPa 4 a 1 kJ b 1 kPa # m3 1 0.001009 m3> kg 2 3 1 16,000 19.0 kJ> kg 15.9 MPa 35°C 3 Boiler 15.2 MPa 625°C 4 15 MPa 600°C wturb,out Turbine η T = 0.87 T 2 16 MPa 5 4 5 wpump,in Pump ηP = 0.85 6 10 kPa 2 2s 1 9 kPa 38°C Condenser 3 1 6s 6 s FIGURE 10–5 Schematic and Ts diagram for Example 10–2. cen84959_ch10.qxd 9/15/06 6:02 AM Page 574 574  Thermodynamics
Turbine work output: wturb,out hT 1 h 5 hTws,turb,out h 6s 2 0.87 1 3583.1 1 3647.6 2115.3 2 kJ> kg 3487.5 kJ> kg 1277.0 kJ> kg h4 h3 Boiler heat input:
Thus, qin 160.1 2 kJ> kg wnet h th wturb,out wnet qin # Wnet 1258.0 kJ> kg wpump,in 1 1277.0 19.0 2 kJ> kg 1258.0 kJ> kg 3487.5 kJ> kg 0.361 or 36.1% (b) The power produced by this power plant is # m 1 wnet 2 1 15 kg> s 2 1 1258.0 kJ> kg 2 18.9 MW Discussion Without the irreversibilities, the thermal efficiency of this cycle would be 43.0 percent (see Example 10–3c). 10–4 ■ HOW CAN WE INCREASE THE EFFICIENCY OF THE RANKINE CYCLE? T Steam power plants are responsible for the production of most electric power in the world, and even small increases in thermal efficiency can mean large savings from the fuel requirements. Therefore, every effort is made to improve the efficiency of the cycle on which steam power plants operate. The basic idea behind all the modifications to increase the thermal efficiency of a power cycle is the same: Increase the average temperature at which heat is transferred to the working fluid in the boiler, or decrease the average temperature at which heat is rejected from the working fluid in the condenser. That is, the average fluid temperature should be as high as possible during heat addition and as low as possible during heat rejection. Next we discuss three ways of accomplishing this for the simple ideal Rankine cycle.
3 Lowering the Condenser Pressure (Lowers Tlow,avg)
2 2' 1 1' Increase in wnet 4' 4
< P '4
P4 s FIGURE 10–6 The effect of lowering the condenser pressure on the ideal Rankine cycle. Steam exists as a saturated mixture in the condenser at the saturation temperature corresponding to the pressure inside the condenser. Therefore, lowering the operating pressure of the condenser automatically lowers the temperature of the steam, and thus the temperature at which heat is rejected. The effect of lowering the condenser pressure on the Rankine cycle efficiency is illustrated on a Ts diagram in Fig. 10–6. For comparison purposes, the turbine inlet state is maintained the same. The colored area on this diagram represents the increase in net work output as a result of lower¿ ing the condenser pressure from P4 to P4 . The heat input requirements also increase (represented by the area under curve 2 2), but this increase is very small. Thus the overall effect of lowering the condenser pressure is an increase in the thermal efficiency of the cycle. cen84959_ch10.qxd 9/15/06 6:02 AM Page 575 Chapter 10
To take advantage of the increased efficiencies at low pressures, the condensers of steam power plants usually operate well below the atmospheric pressure. This does not present a major problem since the vapor power cycles operate in a closed loop. However, there is a lower limit on the condenser pressure that can be used. It cannot be lower than the saturation pressure corresponding to the temperature of the cooling medium. Consider, for example, a condenser that is to be cooled by a nearby river at 15°C. Allowing a temperature difference of 10°C for effective heat transfer, the steam temperature in the condenser must be above 25°C; thus the condenser pressure must be above 3.2 kPa, which is the saturation pressure at 25°C. Lowering the condenser pressure is not without any side effects, however. For one thing, it creates the possibility of air leakage into the condenser. More importantly, it increases the moisture content of the steam at the final stages of the turbine, as can be seen from Fig. 10–6. The presence of large quantities of moisture is highly undesirable in turbines because it decreases the turbine efficiency and erodes the turbine blades. Fortunately, this problem can be corrected, as discussed next.  575 T Increase in wnet 3' 3 Superheating the Steam to High Temperatures (Increases Thigh,avg)
The average temperature at which heat is transferred to steam can be increased without increasing the boiler pressure by superheating the steam to high temperatures. The effect of superheating on the performance of vapor power cycles is illustrated on a Ts diagram in Fig. 10–7. The colored area on this diagram represents the increase in the net work. The total area under the process curve 33 represents the increase in the heat input. Thus both the net work and heat input increase as a result of superheating the steam to a higher temperature. The overall effect is an increase in thermal efficiency, however, since the average temperature at which heat is added increases. Superheating the steam to higher temperatures has another very desirable effect: It decreases the moisture content of the steam at the turbine exit, as can be seen from the Ts diagram (the quality at state 4 is higher than that at state 4). The temperature to which steam can be superheated is limited, however, by metallurgical considerations. Presently the highest steam temperature allowed at the turbine inlet is about 620°C (1150°F). Any increase in this value depends on improving the present materials or finding new ones that can withstand higher temperatures. Ceramics are very promising in this regard. 2 1 4 4' s FIGURE 10–7 The effect of superheating the steam to higher temperatures on the ideal Rankine cycle. T Increase in wnet 3' 3 T max Decrease in wnet Increasing the Boiler Pressure (Increases Thigh,avg)
Another way of increasing the average temperature during the heataddition process is to increase the operating pressure of the boiler, which automatically raises the temperature at which boiling takes place. This, in turn, raises the average temperature at which heat is transferred to the steam and thus raises the thermal efficiency of the cycle. The effect of increasing the boiler pressure on the performance of vapor power cycles is illustrated on a Ts diagram in Fig. 10–8. Notice that for a fixed turbine inlet temperature, the cycle shifts to the left and the moisture content of steam at the turbine exit increases. This undesirable side effect can be corrected, however, by reheating the steam, as discussed in the next section.
2' 2 1 4' 4 s FIGURE 10–8 The effect of increasing the boiler pressure on the ideal Rankine cycle. cen84959_ch10.qxd 9/15/06 6:02 AM Page 576 576
T  Thermodynamics
3 Critical point 2 1 4 Operating pressures of boilers have gradually increased over the years from about 2.7 MPa (400 psia) in 1922 to over 30 MPa (4500 psia) today, generating enough steam to produce a net power output of 1000 MW or more in a large power plant. Today many modern steam power plants operate at supercritical pressures (P 22.06 MPa) and have thermal efficiencies of about 40 percent for fossilfuel plants and 34 percent for nuclear plants. There are over 150 supercriticalpressure steam power plants in operation in the United States. The lower efficiencies of nuclear power plants are due to the lower maximum temperatures used in those plants for safety reasons. The Ts diagram of a supercritical Rankine cycle is shown in Fig. 10–9. The effects of lowering the condenser pressure, superheating to a higher temperature, and increasing the boiler pressure on the thermal efficiency of the Rankine cycle are illustrated below with an example.
s EXAMPLE 10–3 FIGURE 10–9 A supercritical Rankine cycle. Effect of Boiler Pressure and Temperature on Efficiency Consider a steam power plant operating on the ideal Rankine cycle. Steam enters the turbine at 3 MPa and 350°C and is condensed in the condenser at a pressure of 10 kPa. Determine (a) the thermal efficiency of this power plant, (b) the thermal efficiency if steam is superheated to 600°C instead of 350°C, and (c) the thermal efficiency if the boiler pressure is raised to 15 MPa while the turbine inlet temperature is maintained at 600°C. Solution A steam power plant operating on the ideal Rankine cycle is considered. The effects of superheating the steam to a higher temperature and raising the boiler pressure on thermal efficiency are to be investigated. Analysis The Ts diagrams of the cycle for all three cases are given in Fig. 10–10. T T T3 = 600°C 3 3 T = 350°C 3 T 3 15 MPa 3 MPa T3 = 600°C 3 MPa 2 10 kPa 1 4 s ( a) 2 10 kPa 1 4 s ( b) 2 10 kPa 1 4 s ( c) FIGURE 10–10 Ts diagrams of the three cycles discussed in Example 10–3. cen84959_ch10.qxd 9/15/06 6:02 AM Page 577 Chapter 10
(a) This is the steam power plant discussed in Example 10–1, except that the condenser pressure is lowered to 10 kPa. The thermal efficiency is determined in a similar manner:  577 State 1: P1 10 kPa h f 1 Sat. liquid v1 P2 s2 v1 1 P2 3 MPa s1 P1 2 hf @ 10 kPa vf @ 10 kPa 191.81 kJ> kg 0.00101 m3> kg State 2: wpump,in 1 0.00101 m3> kg 2 3 1 3000 1 191.81 3.02 2 kJ> kg 10 2 kPa 4 a 3.02 kJ> kg h2 State 3: h1 P3 T3 P4 s4 x4
Thus, 1 kJ b 1 kPa # m3 wpump,in 3 MPa h3 f s3 350°C State 4: 10 kPa 1 sat. mixture 2 s3 s4 sfg sf 3116.1 kJ> kg 6.7450 kJ> kg # K 194.83 kJ> kg 6.7450 0.6492 7.4996 0.8128 2136.1 kJ> kg h4 qin qout
and hf h3 h4 x4hfg h2 h1 qout qin 1 3116.1 1 2136.1 191.81 194.83 2 kJ> kg 191.81 2 kJ> kg 0.8128 1 2392.1 2 2921.3 kJ> kg 1944.3 kJ> kg h th 1 1 1944.3 kJ> kg 2921.3 kJ> kg 0.334 or 33.4% Therefore, the thermal efficiency increases from 26.0 to 33.4 percent as a result of lowering the condenser pressure from 75 to 10 kPa. At the same time, however, the quality of the steam decreases from 88.6 to 81.3 percent (in other words, the moisture content increases from 11.4 to 18.7 percent). (b) States 1 and 2 remain the same in this case, and the enthalpies at state 3 (3 MPa and 600°C) and state 4 (10 kPa and s4 s3) are determined to be h3 h4
Thus, 3682.8 kJ> kg 2380.3 kJ> kg 1 x4 h2 h1 qout qin 3682.8 2380.3 194.83 191.81 0.915 2 3488.0 kJ> kg 2188.5 kJ> kg 0.373 or 37.3% qin qout
and h3 h4 h th 1 1 2188.5 kJ> kg 3488.0 kJ> kg cen84959_ch10.qxd 9/15/06 6:02 AM Page 578 578  Thermodynamics
Therefore, the thermal efficiency increases from 33.4 to 37.3 percent as a result of superheating the steam from 350 to 600°C. At the same time, the quality of the steam increases from 81.3 to 91.5 percent (in other words, the moisture content decreases from 18.7 to 8.5 percent). (c) State 1 remains the same in this case, but the other states change. The enthalpies at state 2 (15 MPa and s2 s1), state 3 (15 MPa and 600°C), and state 4 (10 kPa and s4 s3) are determined in a similar manner to be h2 h3 h4
Thus, 206.95 kJ> kg 3583.1 kJ> kg 2115.3 kJ> kg 1 x4 h2 h1 qout qin 3583.1 2115.3 206.95 191.81 0.804 2 3376.2 kJ> kg qin qout
and h3 h4 1923.5 kJ> kg h th 1 1 1923.5 kJ> kg 3376.2 kJ> kg 0.430 or 43.0% Discussion The thermal efficiency increases from 37.3 to 43.0 percent as a result of raising the boiler pressure from 3 to 15 MPa while maintaining the turbine inlet temperature at 600°C. At the same time, however, the quality of the steam decreases from 91.5 to 80.4 percent (in other words, the moisture content increases from 8.5 to 19.6 percent). INTERACTIVE TUTORIAL SEE TUTORIAL CH. 10, SEC. 3 ON THE DVD. 10–5 ■ THE IDEAL REHEAT RANKINE CYCLE We noted in the last section that increasing the boiler pressure increases the thermal efficiency of the Rankine cycle, but it also increases the moisture content of the steam to unacceptable levels. Then it is natural to ask the following question:
How can we take advantage of the increased efficiencies at higher boiler pressures without facing the problem of excessive moisture at the final stages of the turbine? Two possibilities come to mind: 1. Superheat the steam to very high temperatures before it enters the turbine. This would be the desirable solution since the average temperature at which heat is added would also increase, thus increasing the cycle efficiency. This is not a viable solution, however, since it requires raising the steam temperature to metallurgically unsafe levels. 2. Expand the steam in the turbine in two stages, and reheat it in between. In other words, modify the simple ideal Rankine cycle with a reheat process. Reheating is a practical solution to the excessive moisture problem in turbines, and it is commonly used in modern steam power plants. The Ts diagram of the ideal reheat Rankine cycle and the schematic of the power plant operating on this cycle are shown in Fig. 10–11. The ideal reheat Rankine cycle differs from the simple ideal Rankine cycle in that the cen84959_ch10.qxd 9/15/06 6:02 AM Page 579 Chapter 10
expansion process takes place in two stages. In the first stage (the highpressure turbine), steam is expanded isentropically to an intermediate pressure and sent back to the boiler where it is reheated at constant pressure, usually to the inlet temperature of the first turbine stage. Steam then expands isentropically in the second stage (lowpressure turbine) to the condenser pressure. Thus the total heat input and the total turbine work output for a reheat cycle become
qin qprimary qreheat 1 h3 h2 2 1 h5 h4 2
(10–12)  579 and
wturb,out wturb,I wturb,II 1 h3 h4 2 1 h5 h6 2 (10–13) The incorporation of the single reheat in a modern power plant improves the cycle efficiency by 4 to 5 percent by increasing the average temperature at which heat is transferred to the steam. The average temperature during the reheat process can be increased by increasing the number of expansion and reheat stages. As the number of stages is increased, the expansion and reheat processes approach an isothermal process at the maximum temperature, as shown in Fig. 10–12. The use of more than two reheat stages, however, is not practical. The theoretical improvement in efficiency from the second reheat is about half of that which results from a single reheat. If the turbine inlet pressure is not high enough, double reheat would result in superheated exhaust. This is undesirable as it would cause the average temperature for heat rejection to increase and thus the cycle efficiency to decrease. Therefore, double reheat is used only on supercriticalpressure (P 22.06 MPa) power plants. A third reheat stage would increase the cycle efficiency by about half of the improvement attained by the second reheat. This gain is too small to justify the added cost and complexity. T Highpressure turbine Reheating 3 5 Lowpressure turbine Boiler Reheater 4 HighP turbine LowP turbine 4 3 P4 = P5 = Preheat 6 5 Condenser 2 Pump 1 s 1 6 2 FIGURE 10–11 The ideal reheat Rankine cycle. cen84959_ch10.qxd 9/15/06 6:02 AM Page 580 580
T  Thermodynamics
The reheat cycle was introduced in the mid1920s, but it was abandoned in the 1930s because of the operational difficulties. The steady increase in boiler pressures over the years made it necessary to reintroduce single reheat in the late 1940s and double reheat in the early 1950s. The reheat temperatures are very close or equal to the turbine inlet temperature. The optimum reheat pressure is about onefourth of the maximum cycle pressure. For example, the optimum reheat pressure for a cycle with a boiler pressure of 12 MPa is about 3 MPa. Remember that the sole purpose of the reheat cycle is to reduce the moisture content of the steam at the final stages of the expansion process. If we had materials that could withstand sufficiently high temperatures, there would be no need for the reheat cycle.
EXAMPLE 10–4 The Ideal Reheat Rankine Cycle Tavg,reheat s FIGURE 10–12 The average temperature at which heat is transferred during reheating increases as the number of reheat stages is increased. Consider a steam power plant operating on the ideal reheat Rankine cycle. Steam enters the highpressure turbine at 15 MPa and 600°C and is condensed in the condenser at a pressure of 10 kPa. If the moisture content of the steam at the exit of the lowpressure turbine is not to exceed 10.4 percent, determine (a) the pressure at which the steam should be reheated and (b) the thermal efficiency of the cycle. Assume the steam is reheated to the inlet temperature of the highpressure turbine. Solution A steam power plant operating on the ideal reheat Rankine cycle
is considered. For a specified moisture content at the turbine exit, the reheat pressure and the thermal efficiency are to be determined. Assumptions 1 Steady operating conditions exist. 2 Kinetic and potential energy changes are negligible. Analysis The schematic of the power plant and the Ts diagram of the cycle are shown in Fig. 10–13. We note that the power plant operates on the ideal reheat Rankine cycle. Therefore, the pump and the turbines are isentropic, there are no pressure drops in the boiler and condenser, and steam leaves the condenser and enters the pump as saturated liquid at the condenser pressure. (a) The reheat pressure is determined from the requirement that the entropies at states 5 and 6 be the same: State 6: P6 x6 s6 10 kPa 0.896 1 sat. mixture 2 sf x6sfg 0.6492 0.896 1 7.4996 2 0.896 1 2392.1 2 7.3688 kJ> kg # K 2335.1 kJ> kg Also, h6
Thus, hf x6hfg 191.81 State 5: T5 s5 600°C P f 5 s6 h5 4.0 MPa 3674.9 kJ> kg Therefore, steam should be reheated at a pressure of 4 MPa or lower to prevent a moisture content above 10.4 percent. cen84959_ch10.qxd 9/15/06 6:02 AM Page 581 Chapter 10
(b) To determine the thermal efficiency, we need to know the enthalpies at all other states:  581 State 1: h P1 10 kPa f 1 Sat. liquid v1 P2 s2 wpump,in 15 MPa s1 v1 1 P2 P1 2 h f @ 10 kPa vf @ 10 kPa 191.81 kJ> kg 0.00101 m3> kg State 2: 1 0.00101 m3> kg 2 10 2 kPa 4 a 1 191.81 1 kJ b 1 kPa # m3 15.14 2 kJ> kg 206.95 kJ> kg 3 1 15,000 15.14 kJ> kg h2 State 3: P3 T3 P4 s4 qin h1 wpump,in 15 MPa h3 f 600°C s3 3583.1 kJ> kg 6.6796 kJ> kg # K State 4:
Thus 4 MPa h 3155.0 kJ> kg f 4 s3 1 T4 375.5°C 2 1 h3 h2 2 1 h5 h4 2 3896.1 kJ> kg qout h6 h1 1 3583.1 206.95 2 kJ> kg 1 2335.1 1 3674.9 3155.0 2 kJ> kg 2143.3 kJ> kg 191.81 2 kJ> kg T, °C Reheating 15 MPa 3 15 MPa HighP turbine LowP turbine 15 MPa 600 3 5 Boiler Reheater 4 4 P4 = P5 = Preheat 5 15 MPa Pump 10 kPa 2 1 Condenser 6 10 kPa 2 10 kPa 1 6 s FIGURE 10–13 Schematic and Ts diagram for Example 10–4. cen84959_ch10.qxd 9/15/06 6:02 AM Page 582 582  Thermodynamics
and h th 1 qout qin 1 2143.3 kJ> kg 3896.1 kJ> kg 0.450 or 45.0% Discussion This problem was solved in Example 10–3c for the same pressure and temperature limits but without the reheat process. A comparison of the two results reveals that reheating reduces the moisture content from 19.6 to 10.4 percent while increasing the thermal efficiency from 43.0 to 45.0 percent. INTERACTIVE TUTORIAL SEE TUTORIAL CH. 10, SEC. 4 ON THE DVD. 10–6 ■ THE IDEAL REGENERATIVE RANKINE CYCLE T
Lowtemperature heat addition Steam exiting boiler 3 2'
Steam entering boiler 2 1 4 s FIGURE 10–14 The first part of the heataddition process in the boiler takes place at relatively low temperatures. A careful examination of the Ts diagram of the Rankine cycle redrawn in Fig. 10–14 reveals that heat is transferred to the working fluid during process 22 at a relatively low temperature. This lowers the average heataddition temperature and thus the cycle efficiency. To remedy this shortcoming, we look for ways to raise the temperature of the liquid leaving the pump (called the feedwater) before it enters the boiler. One such possibility is to transfer heat to the feedwater from the expanding steam in a counterflow heat exchanger built into the turbine, that is, to use regeneration. This solution is also impractical because it is difficult to design such a heat exchanger and because it would increase the moisture content of the steam at the final stages of the turbine. A practical regeneration process in steam power plants is accomplished by extracting, or “bleeding,” steam from the turbine at various points. This steam, which could have produced more work by expanding further in the turbine, is used to heat the feedwater instead. The device where the feedwater is heated by regeneration is called a regenerator, or a feedwater heater (FWH). Regeneration not only improves cycle efficiency, but also provides a convenient means of deaerating the feedwater (removing the air that leaks in at the condenser) to prevent corrosion in the boiler. It also helps control the large volume flow rate of the steam at the final stages of the turbine (due to the large specific volumes at low pressures). Therefore, regeneration has been used in all modern steam power plants since its introduction in the early 1920s. A feedwater heater is basically a heat exchanger where heat is transferred from the steam to the feedwater either by mixing the two fluid streams (open feedwater heaters) or without mixing them (closed feedwater heaters). Regeneration with both types of feedwater heaters is discussed below. Open Feedwater Heaters
An open (or directcontact) feedwater heater is basically a mixing chamber, where the steam extracted from the turbine mixes with the feedwater exiting the pump. Ideally, the mixture leaves the heater as a saturated liquid at the heater pressure. The schematic of a steam power plant with one open feedwater heater (also called singlestage regenerative cycle) and the Ts diagram of the cycle are shown in Fig. 10–15. In an ideal regenerative Rankine cycle, steam enters the turbine at the boiler pressure (state 5) and expands isentropically to an intermediate pres cen84959_ch10.qxd 9/15/06 6:02 AM Page 583 Chapter 10
sure (state 6). Some steam is extracted at this state and routed to the feedwater heater, while the remaining steam continues to expand isentropically to the condenser pressure (state 7). This steam leaves the condenser as a saturated liquid at the condenser pressure (state 1). The condensed water, which is also called the feedwater, then enters an isentropic pump, where it is compressed to the feedwater heater pressure (state 2) and is routed to the feedwater heater, where it mixes with the steam extracted from the turbine. The fraction of the steam extracted is such that the mixture leaves the heater as a saturated liquid at the heater pressure (state 3). A second pump raises the pressure of the water to the boiler pressure (state 4). The cycle is completed by heating the water in the boiler to the turbine inlet state (state 5). In the analysis of steam power plants, it is more convenient to work with quantities expressed per unit mass of the steam flowing through the boiler. For each 1 kg of steam leaving the boiler, y kg expands partially in the turbine and is extracted at state 6. The remaining (1 y) kg expands completely to the condenser pressure. Therefore, the mass flow rates are different in dif. ferent components. If the mass flow rate through the boiler is m , for exam. through the condenser. This aspect of the regenerative ple, it is (1 y)m Rankine cycle should be considered in the analysis of the cycle as well as in the interpretation of the areas on the Ts diagram. In light of Fig. 10–15, the heat and work interactions of a regenerative Rankine cycle with one feedwater heater can be expressed per unit mass of steam flowing through the boiler as follows:
qin qout wturb,out wpump,in h5 11 h4
(10–14)  583 11 1 h5 y 2 1 h7 h6 2 y 2 wpump I,in 11 h1 2 (10–15) y 2 1 h6 wpump II,in h7 2 (10–16) (10–17) 5 T Boiler y 6 4 Open FWH 3 2 Pump II 2 1 Pump I s Condenser 1 7 7 4 6 3 Turbine 5 1–y FIGURE 10–15 The ideal regenerative Rankine cycle with an open feedwater heater. cen84959_ch10.qxd 9/15/06 6:02 AM Page 584 584  Thermodynamics
where
y wpump I,in wpump II,in ## m6> m5 1 fraction of steam extracted 2 P1 2 P3 2 v1 1 P2 v3 1 P4 The thermal efficiency of the Rankine cycle increases as a result of regeneration. This is because regeneration raises the average temperature at which heat is transferred to the steam in the boiler by raising the temperature of the water before it enters the boiler. The cycle efficiency increases further as the number of feedwater heaters is increased. Many large plants in operation today use as many as eight feedwater heaters. The optimum number of feedwater heaters is determined from economical considerations. The use of an additional feedwater heater cannot be justified unless it saves more from the fuel costs than its own cost. Closed Feedwater Heaters
Another type of feedwater heater frequently used in steam power plants is the closed feedwater heater, in which heat is transferred from the extracted steam to the feedwater without any mixing taking place. The two streams now can be at different pressures, since they do not mix. The schematic of a steam power plant with one closed feedwater heater and the Ts diagram of the cycle are shown in Fig. 10–16. In an ideal closed feedwater heater, the feedwater is heated to the exit temperature of the extracted steam, which ideally leaves the heater as a saturated liquid at the extraction pressure. In actual power plants, the feedwater leaves the heater below the exit tempera T 6 Boiler Turbine 9 8 2 5 4 6 7 Mixing chamber 9 5 2 4 3 Closed FWH 7 3 1 8 Condenser 1 Pump II Pump I s FIGURE 10–16 The ideal regenerative Rankine cycle with a closed feedwater heater. cen84959_ch10.qxd 9/15/06 6:02 AM Page 585 Chapter 10  585 Turbine Boiler Condenser Deaerating Closed FWH Closed FWH Open FWH Closed FWH Pump Pump Trap Trap Trap FIGURE 10–17 A steam power plant with one open and three closed feedwater heaters. ture of the extracted steam because a temperature difference of at least a few degrees is required for any effective heat transfer to take place. The condensed steam is then either pumped to the feedwater line or routed to another heater or to the condenser through a device called a trap. A trap allows the liquid to be throttled to a lower pressure region but traps the vapor. The enthalpy of steam remains constant during this throttling process. The open and closed feedwater heaters can be compared as follows. Open feedwater heaters are simple and inexpensive and have good heat transfer characteristics. They also bring the feedwater to the saturation state. For each heater, however, a pump is required to handle the feedwater. The closed feedwater heaters are more complex because of the internal tubing network, and thus they are more expensive. Heat transfer in closed feedwater heaters is also less effective since the two streams are not allowed to be in direct contact. However, closed feedwater heaters do not require a separate pump for each heater since the extracted steam and the feedwater can be at different pressures. Most steam power plants use a combination of open and closed feedwater heaters, as shown in Fig. 10–17.
EXAMPLE 10–5 The Ideal Regenerative Rankine Cycle Consider a steam power plant operating on the ideal regenerative Rankine cycle with one open feedwater heater. Steam enters the turbine at 15 MPa and 600°C and is condensed in the condenser at a pressure of 10 kPa. cen84959_ch10.qxd 9/15/06 6:02 AM Page 586 586  Thermodynamics
Some steam leaves the turbine at a pressure of 1.2 MPa and enters the open feedwater heater. Determine the fraction of steam extracted from the turbine and the thermal efficiency of the cycle. Solution A steam power plant operates on the ideal regenerative Rankine
cycle with one open feedwater heater. The fraction of steam extracted from the turbine and the thermal efficiency are to be determined. Assumptions 1 Steady operating conditions exist. 2 Kinetic and potential energy changes are negligible. Analysis The schematic of the power plant and the Ts diagram of the cycle are shown in Fig. 10–18. We note that the power plant operates on the ideal regenerative Rankine cycle. Therefore, the pumps and the turbines are isentropic; there are no pressure drops in the boiler, condenser, and feedwater heater; and steam leaves the condenser and the feedwater heater as saturated liquid. First, we determine the enthalpies at various states: State 1: h1 P1 10 kPa f Sat. liquid v1 1.2 MPa s1
v1 1 P2 P1 2 hf @ 10 kPa vf @ 10 kPa 191.81 kJ> kg 0.00101 m3> kg State 2: P2 s2
wpump I,in 1 0.00101 m3> kg 2 3 1 1200 10 2 kPa 4 a 1.20 kJ> kg h2 h1 wpump I,in 1 kJ b 1 kPa # m3 1 191.81 1.20 2 kJ> kg 193.01 kJ> kg T 5 15 MPa 600°C Boiler q in Open FWH 4 15 MPa 3 1.2 MPa 1 10 kPa Pump II Pump I Condenser s 1.2 MPa 2 Turbine 4 1.2 MPa 6 7 10 kPa qout 2 1 7 6 3 5 wturb,out FIGURE 10–18 Schematic and Ts diagram for Example 10–5. cen84959_ch10.qxd 9/15/06 6:02 AM Page 587 Chapter 10
State 3: P3 1.2 MPa v f 3 Sat. liquid h3 State 4: P4 s4 wpump II,in 15 MPa s3 v3 1 P4 P3 2 1200 2 kPa 4 a 15.70 2 kJ> kg 1 kJ b 1 kPa # m3 814.03 kJ> kg vf @ 1.2 MPa h f @ 1.2 MPa 0.001138 m3> kg 798.33 kJ> kg  587 15.70 kJ> kg h4 State 5: P5 T5 State 6: P6 s6 State 7: P7 s7 h7 h3 1 0.001138 m3> kg 2 3 1 15,000 1 798.33 wpump II,in 15 MPa h f 5 600°C s5 1.2 MPa h f 6 s5 1 T6 10 kPa s5 hf x7 x7h fg s7 sfg sf 3583.1 kJ> kg 6.6796 kJ> kg # K 2860.2 kJ> kg 218.4°C 2 6.6796 0.6492 7.4996 0.8041 1 2392.1 2 0.8041 2115.3 kJ> kg 191.81 The energy analysis of open feedwater heaters is identical to the energy analysis. of mixing chambers. The feedwater heaters are generally well insu. lated (Q 0), and they do not involve any work interactions (W 0). By neglecting the kinetic and potential energies of the streams, the energy balance reduces for a feedwater heater to # E in
or # # E out S a mh
in # a mh
out yh 6 .. where y is the fraction of steam extracted from the turbine ( m 6 /m 5). Solving for y and substituting the enthalpy values, we find 11 y 2 h2 1 1 h3 2 y
Thus, h3 h6 h2 h2 798.33 2860.2 193.01 193.01 0.2270 2769.1 kJ> kg qin qout h5 1486.9 kJ> kg 11 h4 y 2 1 h7 1 3583.1 h1 2 11 814.03 2 kJ> kg 0.2270 2 1 2115.3 191.81 2 kJ> kg and h th 1 qout qin 1 1486.9 kJ> kg 2769.1 kJ> kg 0.463 or 46.3% cen84959_ch10.qxd 9/15/06 6:02 AM Page 588 588  Thermodynamics
Discussion This problem was worked out in Example 10–3c for the same pressure and temperature limits but without the regeneration process. A comparison of the two results reveals that the thermal efficiency of the cycle has increased from 43.0 to 46.3 percent as a result of regeneration. The net work output decreased by 171 kJ/kg, but the heat input decreased by 607 kJ/kg, which results in a net increase in the thermal efficiency. EXAMPLE 10–6 The Ideal Reheat–Regenerative Rankine Cycle Consider a steam power plant that operates on an ideal reheat–regenerative Rankine cycle with one open feedwater heater, one closed feedwater heater, and one reheater. Steam enters the turbine at 15 MPa and 600°C and is condensed in the condenser at a pressure of 10 kPa. Some steam is extracted from the turbine at 4 MPa for the closed feedwater heater, and the remaining steam is reheated at the same pressure to 600°C. The extracted steam is completely condensed in the heater and is pumped to 15 MPa before it mixes with the feedwater at the same pressure. Steam for the open feedwater heater is extracted from the lowpressure turbine at a pressure of 0.5 MPa. Determine the fractions of steam extracted from the turbine as well as the thermal efficiency of the cycle. Solution A steam power plant operates on the ideal reheat–regenerative
Rankine cycle with one open feedwater heater, one closed feedwater heater, and one reheater. The fractions of steam extracted from the turbine and the thermal efficiency are to be determined. Assumptions 1 Steady operating conditions exist. 2 Kinetic and potential energy changes are negligible. 3 In both open and closed feedwater heaters, feedwater is heated to the saturation temperature at the feedwater heater pressure. (Note that this is a conservative assumption since extracted steam enters the closed feedwater heater at 376°C and the saturation temperature at the closed feedwater pressure of 4 MPa is 250°C). Analysis The schematic of the power plant and the Ts diagram of the cycle are shown in Fig. 10–19. The power plant operates on the ideal reheat– regenerative Rankine cycle and thus the pumps and the turbines are isentropic; there are no pressure drops in the boiler, reheater, condenser, and feedwater heaters; and steam leaves the condenser and the feedwater heaters as saturated liquid. The enthalpies at the various states and the pump work per unit mass of fluid flowing through them are h1 h2 h3 h4 h5 h6 h7 h8 191.81 kJ> kg h 9 192.30 kJ> kg h10 640.09 kJ> kg h11 643.92 kJ> kg h12 1087.4 kJ> kg h13 1087.4 kJ> kg wpump I,in 1101.2 kJ> kg 1089.8 kJ> kg wpump III,in 3155.0 kJ> kg 3155.0 kJ> kg 3674.9 kJ> kg 3014.8 kJ> kg 2335.7 kJ> kg 0.49 kJ> kg 3.83 kJ> kg wpump II,in 13.77 kJ> kg cen84959_ch10.qxd 9/15/06 6:02 AM Page 589 Chapter 10
The fractions of steam extracted are determined from the mass and energy balances of the feedwater heaters: Closed feedwater heater:  589 yh10
y 1 h10 h5 h6 2 h4 1 h5 h4 2 11 y 2 h4 # Ein # Eout 11 y 2 h5 yh6
643.92 1 1087.4 643.92 2 0.1766 1 3155.0 1087.4 1087.4 2 Open feedwater heater: zh 12 z 11 11 h12 y 2 1 h3 y z 2 h2 h2 2 # E in # E out 11 11 h2 0.1766 2 1 640.09 3014.8 y 2 h3 192.30 192.30 2 0.1306 The enthalpy at state 8 is determined by applying the mass and energy equations to the mixing chamber, which is assumed to be insulated: 1 1 2 h8 h8 # E in # E out 11 11 y 2 h5 1089.8 kJ> kg 0.1766 2 1 1087.4 2 kJ> kg yh 7 0.1766 1 1101.2 2 kJ> kg 1 kg 9 15 MPa 600°C HighP turbine 10 15 MPa y P10 = P11 = 4 MPa 1–y 4 MPa 8 Mixing chamber 7 Closed FWH 5 6 4 3 Pump II Pump I Open FWH 2 600°C 11 0.5 MPa z 12 1–y –z 13 10 kPa 2 1 Condenser 1 4 8 5 7 6 0.5 MPa 3 10 kPa 13 s z 4 MPa
y 10 T 1k Boiler Reheater 1– g LowP turbine 9
y 11 1–y 12 1–y–z Pump III FIGURE 10–19 Schematic and Ts diagram for Example 10–6. cen84959_ch10.qxd 9/15/06 6:02 AM Page 590 590  Thermodynamics
Thus, qin 1 h9 2921.4 kJ> kg qout 11 11 y 0.1766 1 3583.1 h8 2 1089.8 2 kJ> kg h1 2 11 y 2 1 h 11 h 10 2 11 0.1766 2 1 3674.9 3155.0 2 kJ> kg z 2 1 h 13 1485.3 kJ> kg
and 0.1306 2 1 2335.7 191.81 2 kJ> kg h th 1 qout qin 1 1485.3 kJ> kg 2921.4 kJ> kg 0.492 or 49.2% Discussion This problem was worked out in Example 10–4 for the same pressure and temperature limits with reheat but without the regeneration process. A comparison of the two results reveals that the thermal efficiency of the cycle has increased from 45.0 to 49.2 percent as a result of regeneration. The thermal efficiency of this cycle could also be determined from hth
where wnet qin 11 wturb,out qin y 2 1 h 11 11 h 12 2 wpump,in wturb,out wpump,in 1 h9 11 h 10 2 y z 2 wpump I,in y 2 wpump II,in 11 y 1 y 2 wpump III,in z 2 1 h 12 h 13 2 Also, if we assume that the feedwater leaves the closed FWH as a saturated liquid at 15 MPa (and thus at T5 342°C and h5 1610.3 kJ/kg), it can be shown that the thermal efficiency would be 50.6. 10–7 ■ SECONDLAW ANALYSIS OF VAPOR POWER CYCLES The ideal Carnot cycle is a totally reversible cycle, and thus it does not involve any irreversibilities. The ideal Rankine cycles (simple, reheat, or regenerative), however, are only internally reversible, and they may involve irreversibilities external to the system, such as heat transfer through a finite temperature difference. A secondlaw analysis of these cycles reveals where the largest irreversibilities occur and what their magnitudes are. Relations for exergy and exergy destruction for steadyflow systems are developed in Chap. 8. The exergy destruction for a steadyflow system can be expressed, in the rate form, as
# X dest # T0 S gen # T0 1 S out # S in 2 # T0 a a m s
out # Q out Tb,out # a ms
in # Q in b 1 kW 2 Tb,in
(10–18) or on a unit mass basis for a oneinlet, oneexit, steadyflow device as
xdest T0sgen T0 a se si qout Tb,out qin b 1 kJ> kg 2 Tb,in
(10–19) cen84959_ch10.qxd 9/15/06 6:02 AM Page 591 Chapter 10
where Tb,in and Tb,out are the temperatures of the system boundary where heat is transferred into and out of the system, respectively. The exergy destruction associated with a cycle depends on the magnitude of the heat transfer with the high and lowtemperature reservoirs involved, and their temperatures. It can be expressed on a unit mass basis as
xdest T0 a a qout Tb,out qin a T b 1 kJ> kg 2
b,in  591 (10–20) For a cycle that involves heat transfer only with a source at TH and a sink at TL , the exergy destruction becomes
xdest T0 a qout TL qin b 1 kJ> kg 2 TH s0 2 V2 2 gz 1 kJ> kg 2
(10–21) The exergy of a fluid stream c at any state can be determined from
c 1h h0 2 T0 1 s
(10–22) where the subscript “0” denotes the state of the surroundings.
EXAMPLE 10–7 SecondLaw Analysis of an Ideal Rankine Cycle Determine the exergy destruction associated with the Rankine cycle (all four processes as well as the cycle) discussed in Example 10–1, assuming that heat is transferred to the steam in a furnace at 1600 K and heat is rejected to a cooling medium at 290 K and 100 kPa. Also, determine the exergy of the steam leaving the turbine. Solution The Rankine cycle analyzed in Example 10–1 is reconsidered. For
specified source and sink temperatures, the exergy destruction associated with the cycle and exergy of the steam at turbine exit are to be determined. Analysis In Example 10–1, the heat input was determined to be 2728.6 kJ/kg, and the heat rejected to be 2018.6 kJ/kg. Processes 12 and 34 are isentropic (s1 s2, s3 s4) and therefore do not involve any internal or external irreversibilities, that is, xdest,12 0 and xdest,34 0 Processes 23 and 41 are constantpressure heataddition and heatrejection processes, respectively, and they are internally reversible. But the heat transfer between the working fluid and the source or the sink takes place through a finite temperature difference, rendering both processes irreversible. The irreversibility associated with each process is determined from Eq. 10–19. The entropy of the steam at each state is determined from the steam tables: s2 s4
Thus, s1 s3 T0 a s3 sf @ 75 kPa 6.7450 kJ> kg # K 1 at 3 MPa, 350°C 2 qin,23 Tsource b 1.2132 2 kJ> kg # K 1.2132 kJ> kg # K xdest,23 s2 1 290 K 2 c 1 6.7450 1110 kJ/kg 2728.6 kJ> kg 1600 K d cen84959_ch10.qxd 9/15/06 6:02 AM Page 592 592  Thermodynamics
xdest,41 T0 a s1 s4 qout,41 Tsink b 6.7450 2 kJ> kg # K 1 290 K 2 c 1 1.2132 414 kJ/kg 2018.6 kJ> kg 290 K d Therefore, the irreversibility of the cycle is x dest,cycle xdest,12 0 1110 kJ> kg xdest,23 xdest,34 0 414 kJ> kg xdest,41 1524 kJ/kg
The total exergy destroyed during the cycle could also be determined from Eq. 10–21. Notice that the largest exergy destruction in the cycle occurs during the heataddition process. Therefore, any attempt to reduce the exergy destruction should start with this process. Raising the turbine inlet temperature of the steam, for example, would reduce the temperature difference and thus the exergy destruction. The exergy (work potential) of the steam leaving the turbine is determined from Eq. 10–22. Disregarding the kinetic and potential energies, it reduces to c4 1 h4 1 h4 h0 2 h0 2 T0 1 s4 T0 1 s4 s0 2 s0 2 0 0 V2 Q 4 gz4Q 2 where h0 s0
Thus, h @ 290 K,100 kPa [email protected] 290 K,100 kPa 71.355 2 kJ> kg h f @ 290 K sf @ 290 K 0.2533 kJ> kg # K 0.2533 2 kJ> kg # K 4 71.355 kJ> kg c4 1 2403.0 449 kJ/kg 1 290 K 2 3 1 6.7450 Discussion Note that 449 kJ/kg of work could be obtained from the steam leaving the turbine if it is brought to the state of the surroundings in a reversible manner. 10–8 ■ COGENERATION In all the cycles discussed so far, the sole purpose was to convert a portion of the heat transferred to the working fluid to work, which is the most valuable form of energy. The remaining portion of the heat is rejected to rivers, lakes, oceans, or the atmosphere as waste heat, because its quality (or grade) is too low to be of any practical use. Wasting a large amount of heat is a price we have to pay to produce work, because electrical or mechanical work is the only form of energy on which many engineering devices (such as a fan) can operate. Many systems or devices, however, require energy input in the form of heat, called process heat. Some industries that rely heavily on process heat are chemical, pulp and paper, oil production and refining, steel making, cen84959_ch10.qxd 9/15/06 6:02 AM Page 593 Chapter 10
food processing, and textile industries. Process heat in these industries is usually supplied by steam at 5 to 7 atm and 150 to 200°C (300 to 400°F). Energy is usually transferred to the steam by burning coal, oil, natural gas, or another fuel in a furnace. Now let us examine the operation of a processheating plant closely. Disregarding any heat losses in the piping, all the heat transferred to the steam in the boiler is used in the processheating units, as shown in Fig. 10–20. Therefore, process heating seems like a perfect operation with practically no waste of energy. From the secondlaw point of view, however, things do not look so perfect. The temperature in furnaces is typically very high (around 1400°C), and thus the energy in the furnace is of very high quality. This highquality energy is transferred to water to produce steam at about 200°C or below (a highly irreversible process). Associated with this irreversibility is, of course, a loss in exergy or work potential. It is simply not wise to use highquality energy to accomplish a task that could be accomplished with lowquality energy. Industries that use large amounts of process heat also consume a large amount of electric power. Therefore, it makes economical as well as engineering sense to use the alreadyexisting work potential to produce power instead of letting it go to waste. The result is a plant that produces electricity while meeting the processheat requirements of certain industrial processes. Such a plant is called a cogeneration plant. In general, cogeneration is the production of more than one useful form of energy (such as process heat and electric power) from the same energy source. Either a steamturbine (Rankine) cycle or a gasturbine (Brayton) cycle or even a combined cycle (discussed later) can be used as the power cycle in a cogeneration plant. The schematic of an ideal steamturbine cogeneration . plant is shown in Fig. 10–21. Let us say this plant is to supply process heat Qp at 500 kPa at a rate of 100 kW. To meet this demand, steam is expanded in the turbine to a pressure of 500 kPa, producing power at a rate of, say, 20 kW. The flow rate of the steam can be adjusted such that steam leaves the processheating section as a saturated liquid at 500 kPa. Steam is then pumped to the boiler pressure and is heated in the boiler to state 3. The pump work is usually very small and can be neglected. Disregarding any heat losses, the rate of heat input in the boiler is determined from an energy balance to be 120 kW. Probably the most striking feature of the ideal steamturbine cogeneration plant shown in Fig. 10–21 is the absence of a condenser. Thus no heat is rejected from this plant as waste heat. In other words, all the energy transferred to the steam in the boiler is utilized as either process heat or electric power. Thus it is appropriate to define a utilization factor u for a cogeneration plant as
u  593 Boiler Process heater Qp Pump Qin FIGURE 10–20 A simple processheating plant. 3 Boiler Turbine 20 kW 4 Process heater Pump 1 W pump ~ 0 = 100 kW 120 kW 2 FIGURE 10–21 An ideal cogeneration plant. Net work output Process heat delivered Total heat input # Q out # Q in # Wnet # Q in # Qp (10–23) or
u 1 (10–24) . where Qout represents the heat rejected in the condenser. Strictly speaking, . Qout also includes all the undesirable heat losses from the piping and other components, but they are usually small and thus neglected. It also includes combustion inefficiencies such as incomplete combustion and stack losses cen84959_ch10.qxd 9/15/06 6:02 AM Page 594 594  Thermodynamics
when the utilization factor is defined on the basis of the heating value of the fuel. The utilization factor of the ideal steamturbine cogeneration plant is obviously 100 percent. Actual cogeneration plants have utilization factors as high as 80 percent. Some recent cogeneration plants have even higher utilization factors. Notice that without the turbine, we would need to supply heat to the steam in the boiler at a rate of only 100 kW instead of at 120 kW. The additional 20 kW of heat supplied is converted to work. Therefore, a cogeneration power plant is equivalent to a processheating plant combined with a power plant that has a thermal efficiency of 100 percent. The ideal steamturbine cogeneration plant described above is not practical because it cannot adjust to the variations in power and processheat loads. The schematic of a more practical (but more complex) cogeneration plant is shown in Fig. 10–22. Under normal operation, some steam is extracted from the turbine at some predetermined intermediate pressure P6. The rest of the steam expands to the condenser pressure P7 and is then cooled at constant pressure. The heat rejected from the condenser represents the waste heat for the cycle. At times of high demand for process heat, all the steam is routed to the . processheating units and none to the condenser (m 7 0). The waste heat is zero in this mode. If this is not sufficient, some steam leaving the boiler is throttled by an expansion or pressurereducing valve (PRV) to the extraction pressure P6 and is directed to the processheating unit. Maximum process heating is realized when all the steam leaving the boiler passes through the . . m 4). No power is produced in this mode. When there is no PRV (m 5 demand for process heat, all the steam passes through the turbine and the . . m6 0), and the cogeneration plant operates as an ordicondenser (m 5 nary steam power plant. The rates of heat input, heat rejected, and process heat supply as well as the power produced for this cogeneration plant can be expressed as follows:
# Q in # Q out # Qp # Wturb # m3 1 h4 h3 2 # m7 1 h7 h1 2 # # m5 h5 m6 h6 # # 1 m4 m5 2 1 h4
(10–25) (10–26) 4 Expansion valve Boiler 5 Process heater 3 Pump II Condenser 8 1 2 Pump I Turbine 6 7 FIGURE 10–22 A cogeneration plant with adjustable loads. # m8 h8 h6 2 (10–27) # m7 1 h6 h7 2 (10–28) Under optimum conditions, a cogeneration plant simulates the ideal cogeneration plant discussed earlier. That is, all the steam expands in the turbine to the extraction pressure and continues to the processheating unit. No steam passes through the PRV or the condenser; thus, no waste heat is . . . . m 6 and m 5 m7 0). This condition may be difficult to rejected (m 4 achieve in practice because of the constant variations in the processheat and power loads. But the plant should be designed so that the optimum operating conditions are approximated most of the time. The use of cogeneration dates to the beginning of this century when power plants were integrated to a community to provide district heating, that is, space, hot water, and process heating for residential and commercial buildings. The district heating systems lost their popularity in the 1940s owing to low fuel prices. However, the rapid rise in fuel prices in the 1970s brought about renewed interest in district heating. cen84959_ch10.qxd 9/15/06 6:02 AM Page 595 Chapter 10
Cogeneration plants have proved to be economically very attractive. Consequently, more and more such plants have been installed in recent years, and more are being installed.
EXAMPLE 10–8 An Ideal Cogeneration Plant  595 Consider the cogeneration plant shown in Fig. 10–23. Steam enters the turbine at 7 MPa and 500°C. Some steam is extracted from the turbine at 500 kPa for process heating. The remaining steam continues to expand to 5 kPa. Steam is then condensed at constant pressure and pumped to the boiler pressure of 7 MPa. At times of high demand for process heat, some steam leaving the boiler is throttled to 500 kPa and is routed to the process heater. The extraction fractions are adjusted so that steam leaves the process heater as a saturated liquid at 500 kPa. It is subsequently pumped to 7 MPa. The mass flow rate of steam through the boiler is 15 kg/s. Disregarding any pressure drops and heat losses in the piping and assuming the turbine and the pump to be isentropic, determine (a) the maximum rate at which process heat can be supplied, (b) the power produced and the utilization factor when no process heat is supplied, and (c) the rate of process heat supply when 10 percent of the steam is extracted before it enters the turbine and 70 percent of the steam is extracted from the turbine at 500 kPa for process heating. Solution A cogeneration plant is considered. The maximum rate of process heat supply, the power produced and the utilization factor when no process heat is supplied, and the rate of process heat supply when steam is extracted from the steam line and turbine at specified ratios are to be determined. Assumptions 1 Steady operating conditions exist. 2 Pressure drops and heat losses in piping are negligible. 3 Kinetic and potential energy changes are negligible. Analysis The schematic of the cogeneration plant and the Ts diagram of the cycle are shown in Fig. 10–23. The power plant operates on an ideal 7 MPa 500°C 1 Boiler 2 Expansion valve 4 500 kPa 3 Turbine 5 Process heater 11 Mixing chamber 9 7 MPa 5 kPa 10 Pump II 7 Pump I 8 Condenser 500 kPa 6 5 kPa T 1, 2, 3 4 10 11 9 8 6 7 5 s FIGURE 10–23 Schematic and Ts diagram for Example 10–8. cen84959_ch10.qxd 9/15/06 6:02 AM Page 596 596  Thermodynamics
cycle and thus the pumps and the turbines are isentropic; there are no pressure drops in the boiler, process heater, and condenser; and steam leaves the condenser and the process heater as saturated liquid. The work inputs to the pumps and the enthalpies at various states are as follows: wpump I,in v8 1 P9 P8 2 1 0.001005 m3> kg 2 3 1 7000 5 2 kPa 4 a 7.03 kJ> kg wpump II,in v7 1 P10 P7 2 1 0.001093 m3> kg 2 3 17000 3411.4 kJ> kg 1 kJ b 1 kPa # m3 1 kJ b 1 kPa # m3 7.10 kJ> kg h1 h5 h6 h7 h8 h9 h 10 h2 h3 500 2 kPa 4 a 2739.3 kJ> kg 2073.0 kJ> kg h f @ 500 kPa h f @ 5 kPa h8 h7 h4 137.75 kJ> kg 640.09 kJ> kg 1 137.75 7.03 2 kJ> kg 144.78 kJ> kg wpump I,in wpump II,in 1 640.09 7.10 2 kJ> kg 647.19 kJ> kg (a) The maximum rate of process heat is achieved when all the steam leaving the boiler is throttled and sent to the process heater and none is sent to the . . . . . . turbine (that is, m 4 m7 m1 15 kg/s and m 3 m5 m6 0). Thus, # Q p,max # m1 1 h4 h7 2 1 15 kg> s 2 3 1 3411.4 640.09 2 kJ> kg 4 41,570 kW The utilization factor is 100 percent in this case since no heat is rejected in the condenser, heat losses from the piping and other components are assumed to be negligible, and combustion losses are not considered. (b) When no process heat is supplied, all the steam leaving the boiler passes through the turbine and expands to the condenser pressure of 5 kPa (that is, . . . . . m3 m6 m1 15 kg/s and m 2 m5 0). Maximum power is produced in this mode, which is determined to be # Wturb,out # Wpump,in # Wnet,out # Q in
Thus, 1 15 kg> s 2 1 7.03 kJ> kg 2 105 kW # # Wturb,out Wpump,in 1 20,076 105 2 kW 19,971 kW 20.0 MW # m 1 1 h1 h 11 2 1 15 kg> s 2 3 1 3411.4 144.78 2 kJ> kg 4 48,999 kW # Wnet
u # m 1 h3 h6 2 1 15 kg> s 2 3 1 3411.4 2073.0 2 kJ> kg 4 20,076 kW # Qp # Q in 1 19,971 48,999 kW 0 2 kW 0.408 or 40.8% That is, 40.8 percent of the energy is utilized for a useful purpose. Notice that the utilization factor is equivalent to the thermal efficiency in this case. (c) Neglecting any kinetic and potential energy changes, an energy balance on the process heater yields cen84959_ch10.qxd 9/15/06 6:02 AM Page 597 Chapter 10
# Ein # m 4h 4
or  597 # m5h5 # m 4h4 # Eout # Q p,out # m 5h 5 # m7h 7 # m 7h7 # Qp,out
where # m4 # m5 # m7
Thus 1 0.7 2 1 15 kg> s 2 # # m 4 m 5 1.5 1 0.1 2 1 15 kg> s 2 1.5 kg> s 10.5 10.5 kg> s 12 kg> s # Q p,out 1 1.5 kg> s 2 1 3411.4 kJ> kg 2 26.2 MW 1 12 kg> s 2 1 640.09 kJ> kg 2 1 10.5 kg> s 2 1 2739.3 kJ> kg 2 Discussion Note that 26.2 MW of the heat transferred will be utilized in the process heater. We could also show that 11.0 MW of power is produced in this case, and the rate of heat input in the boiler is 43.0 MW. Thus the utilization factor is 86.5 percent. 10–9 ■ COMBINED GAS–VAPOR POWER CYCLES The continued quest for higher thermal efficiencies has resulted in rather innovative modifications to conventional power plants. The binary vapor cycle discussed later is one such modification. A more popular modification involves a gas power cycle topping a vapor power cycle, which is called the combined gas–vapor cycle, or just the combined cycle. The combined cycle of greatest interest is the gasturbine (Brayton) cycle topping a steamturbine (Rankine) cycle, which has a higher thermal efficiency than either of the cycles executed individually. Gasturbine cycles typically operate at considerably higher temperatures than steam cycles. The maximum fluid temperature at the turbine inlet is about 620°C (1150°F) for modern steam power plants, but over 1425°C (2600°F) for gasturbine power plants. It is over 1500°C at the burner exit of turbojet engines. The use of higher temperatures in gas turbines is made possible by recent developments in cooling the turbine blades and coating the blades with hightemperatureresistant materials such as ceramics. Because of the higher average temperature at which heat is supplied, gasturbine cycles have a greater potential for higher thermal efficiencies. However, the gasturbine cycles have one inherent disadvantage: The gas leaves the gas turbine at very high temperatures (usually above 500°C), which erases any potential gains in the thermal efficiency. The situation can be improved somewhat by using regeneration, but the improvement is limited. It makes engineering sense to take advantage of the very desirable characteristics of the gasturbine cycle at high temperatures and to use the hightemperature exhaust gases as the energy source for the bottoming cycle such as a steam power cycle. The result is a combined gas–steam cycle, as shown cen84959_ch10.qxd 9/15/06 6:02 AM Page 598 598  Thermodynamics
in Fig. 10–24. In this cycle, energy is recovered from the exhaust gases by transferring it to the steam in a heat exchanger that serves as the boiler. In general, more than one gas turbine is needed to supply sufficient heat to the steam. Also, the steam cycle may involve regeneration as well as reheating. Energy for the reheating process can be supplied by burning some additional fuel in the oxygenrich exhaust gases. Recent developments in gasturbine technology have made the combined gas–steam cycle economically very attractive. The combined cycle increases the efficiency without increasing the initial cost greatly. Consequently, many new power plants operate on combined cycles, and many more existing steam or gasturbine plants are being converted to combinedcycle power plants. Thermal efficiencies well over 40 percent are reported as a result of conversion. A 1090MW Tohoku combined plant that was put in commercial operation in 1985 in Niigata, Japan, is reported to operate at a thermal efficiency of 44 percent. This plant has two 191MW steam turbines and six 118MW gas turbines. Hot combustion gases enter the gas turbines at 1154°C, and steam enters the steam turbines at 500°C. Steam is cooled in the condenser by cooling water at an average temperature of 15°C. The compressors have a pressure ratio of 14, and the mass flow rate of air through the compressors is 443 kg/s. Qin T Combustion chamber 6 GAS CYCLE Compressor Gas turbine GAS CYCLE 8 3 6 2 Pump Condenser STEAM CYCLE 3 9 Steam turbine 5 1 Qout 1 Qout 4 s 4 2 STEAM CYCLE 7 7 Air in 5 Exhaust gases 9 Heat exchanger 8 Qin FIGURE 10–24 Combined gas–steam power plant. cen84959_ch10.qxd 9/15/06 6:02 AM Page 599 Chapter 10
A 1350MW combinedcycle power plant built in Ambarli, Turkey, in 1988 by Siemens of Germany is the first commercially operating thermal plant in the world to attain an efficiency level as high as 52.5 percent at design operating conditions. This plant has six 150MW gas turbines and three 173MW steam turbines. Some recent combinedcycle power plants have achieved efficiencies above 60 percent.
EXAMPLE 10–9 A Combined Gas–Steam Power Cycle  599 Consider the combined gas–steam power cycle shown in Fig. 10–25. The topping cycle is a gasturbine cycle that has a pressure ratio of 8. Air enters the compressor at 300 K and the turbine at 1300 K. The isentropic efficiency of the compressor is 80 percent, and that of the gas turbine is 85 percent. The bottoming cycle is a simple ideal Rankine cycle operating between the pressure limits of 7 MPa and 5 kPa. Steam is heated in a heat exchanger by the exhaust gases to a temperature of 500°C. The exhaust gases leave the heat exchanger at 450 K. Determine (a) the ratio of the mass flow rates of the steam and the combustion gases and (b) the thermal efficiency of the combined cycle. Solution A combined gas–steam cycle is considered. The ratio of the mass
flow rates of the steam and the combustion gases and the thermal efficiency are to be determined. Analysis The Ts diagrams of both cycles are given in Fig. 10–25. The gasturbine cycle alone was analyzed in Example 9–6, and the steam cycle in Example 10–8b, with the following results: Gas cycle: ¿ h4 qin h5 ¿ 880.36 kJ> kg 1 T4 ¿ 790.58 kJ> kg wnet h @ 450 K 451.80 kJ> kg 210.41 kJ> kg h th 853 K 2 26.6% T, K 3' 1300 4' 3 2' 7 MPa 450 2 300 1' 1 5 kPa 4 5' 500°C 7 MPa s FIGURE 10–25 Ts diagram of the gas–steam combined cycle described in Example 10–9. cen84959_ch10.qxd 9/15/06 6:02 AM Page 600 600  Thermodynamics
Steam cycle: h2 h3 wnet 144.78 kJ> kg 1 T2 1331.4 kJ> kg hth 3411.4 kJ> kg 1 T3 33°C 2 500°C 2 40.8% (a) The ratio of mass flow rates is determined from an energy balance on the heat exchanger: # E in # # ¿ ms h3 mg h5 # ms 1 h3 h2 2 144.78 2 # ms # mg # m s 1 3411.4
Thus, # E out # # mg h4 ¿ ms h2 # mg 1 h ¿ h5 2 ¿ 4 # mg 1 880.36 451.80 2 0.131 y That is, 1 kg of exhaust gases can heat only 0.131 kg of steam from 33 to 500°C as they are cooled from 853 to 450 K. Then the total net work output per kilogram of combustion gases becomes wnet wnet,gas 384.8 kJ> kg gas 1 210.41 kJ> kg gas 2 ywnet,steam 1 0.131 kg steam> kg gas 2 1 1331.4 kJ> kg steam 2 Therefore, for each kg of combustion gases produced, the combined plant will deliver 384.8 kJ of work. The net power output of the plant is determined by multiplying this value by the mass flow rate of the working fluid in the gasturbine cycle. (b) The thermal efficiency of the combined cycle is determined from h th wnet qin 384.8 kJ> kg gas 790.6 kJ> kg gas 0.487 or 48.7% Discussion Note that this combined cycle converts to useful work 48.7 percent of the energy supplied to the gas in the combustion chamber. This value is considerably higher than the thermal efficiency of the gasturbine cycle (26.6 percent) or the steamturbine cycle (40.8 percent) operating alone. TOPIC OF SPECIAL INTEREST* Binary Vapor Cycles
With the exception of a few specialized applications, the working fluid predominantly used in vapor power cycles is water. Water is the best working fluid presently available, but it is far from being the ideal one. The binary cycle is an attempt to overcome some of the shortcomings of water and to approach the ideal working fluid by using two fluids. Before we discuss the binary cycle, let us list the characteristics of a working fluid most suitable for vapor power cycles:
*This section can be skipped without a loss in continuity. cen84959_ch10.qxd 9/15/06 6:02 AM Page 601 Chapter 10
1. A high critical temperature and a safe maximum pressure. A critical temperature above the metallurgically allowed maximum temperature (about 620°C) makes it possible to transfer a considerable portion of the heat isothermally at the maximum temperature as the fluid changes phase. This makes the cycle approach the Carnot cycle. Very high pressures at the maximum temperature are undesirable because they create materialstrength problems. 2. Low triplepoint temperature. A triplepoint temperature below the temperature of the cooling medium prevents any solidification problems. 3. A condenser pressure that is not too low. Condensers usually operate below atmospheric pressure. Pressures well below the atmospheric pressure create airleakage problems. Therefore, a substance whose saturation pressure at the ambient temperature is too low is not a good candidate. 4. A high enthalpy of vaporization (hfg) so that heat transfer to the working fluid is nearly isothermal and large mass flow rates are not needed. 5. A saturation dome that resembles an inverted U. This eliminates the formation of excessive moisture in the turbine and the need for reheating. 6. Good heat transfer characteristics (high thermal conductivity). 7. Other properties such as being inert, inexpensive, readily available, and nontoxic.
Not surprisingly, no fluid possesses all these characteristics. Water comes the closest, although it does not fare well with respect to characteristics 1, 3, and 5. We can cope with its subatmospheric condenser pressure by careful sealing, and with the inverted Vshaped saturation dome by reheating, but there is not much we can do about item 1. Water has a low critical temperature (374°C, well below the metallurgical limit) and very high saturation pressures at high temperatures (16.5 MPa at 350°C). Well, we cannot change the way water behaves during the hightemperature part of the cycle, but we certainly can replace it with a more suitable fluid. The result is a power cycle that is actually a combination of two cycles, one in the hightemperature region and the other in the lowtemperature region. Such a cycle is called a binary vapor cycle. In binary vapor cycles, the condenser of the hightemperature cycle (also called the topping cycle) serves as the boiler of the lowtemperature cycle (also called the bottoming cycle). That is, the heat output of the hightemperature cycle is used as the heat input to the lowtemperature one. Some working fluids found suitable for the hightemperature cycle are mercury, sodium, potassium, and sodium–potassium mixtures. The schematic and Ts diagram for a mercury–water binary vapor cycle are shown in Fig. 10–26. The critical temperature of mercury is 898°C (well above the current metallurgical limit), and its critical pressure is only about 18 MPa. This makes mercury a very suitable working fluid for the topping cycle. Mercury is not suitable as the sole working fluid for the entire cycle, however, since at a condenser temperature of 32°C its saturation pressure is 0.07 Pa. A power plant cannot operate at this vacuum because of airleakage problems. At an acceptable condenser pressure of 7 kPa, the saturation temperature of mercury is  601 cen84959_ch10.qxd 9/15/06 6:02 AM Page 602 602  Thermodynamics
T 2 Boiler 3 Saturation dome (mercury) 3 MERCURY CYCLE 7 2 4 6 STEAM CYCLE Superheater 7 Steam turbine 6 5 Condenser STEAM CYCLE 8 1 Saturation dome (steam) Mercury pump 1 MERCURY CYCLE Heat exchanger Q Mercury turbine 4 Steam pump 5 8 s FIGURE 10–26 Mercury–water binary vapor cycle. 237°C, which is too high as the minimum temperature in the cycle. Therefore, the use of mercury as a working fluid is limited to the hightemperature cycles. Other disadvantages of mercury are its toxicity and high cost. The mass flow rate of mercury in binary vapor cycles is several times that of water because of its low enthalpy of vaporization. It is evident from the Ts diagram in Fig. 10–26 that the binary vapor cycle approximates the Carnot cycle more closely than the steam cycle for the same temperature limits. Therefore, the thermal efficiency of a power plant can be increased by switching to binary cycles. The use of mercury–water binary cycles in the United States dates back to 1928. Several such plants have been built since then in the New England area, where fuel costs are typically higher. A small (40MW) mercury–steam power plant that was in service in New Hampshire in 1950 had a higher thermal efficiency than most of the large modern power plants in use at that time. Studies show that thermal efficiencies of 50 percent or higher are possible with binary vapor cycles. However, binary vapor cycles are not economically attractive because of their high initial cost and the competition offered by the combined gas–steam power plants. cen84959_ch10.qxd 9/15/06 6:02 AM Page 603 Chapter 10 SUMMARY
The Carnot cycle is not a suitable model for vapor power cycles because it cannot be approximated in practice. The model cycle for vapor power cycles is the Rankine cycle, which is composed of four internally reversible processes: constantpressure heat addition in a boiler, isentropic expansion in a turbine, constantpressure heat rejection in a condenser, and isentropic compression in a pump. Steam leaves the condenser as a saturated liquid at the condenser pressure. The thermal efficiency of the Rankine cycle can be increased by increasing the average temperature at which heat is transferred to the working fluid and/or by decreasing the average temperature at which heat is rejected to the cooling medium. The average temperature during heat rejection can be decreased by lowering the turbine exit pressure. Consequently, the condenser pressure of most vapor power plants is well below the atmospheric pressure. The average temperature during heat addition can be increased by raising the boiler pressure or by superheating the fluid to high temperatures. There is a limit to the degree of superheating, however, since the fluid temperature is not allowed to exceed a metallurgically safe value. Superheating has the added advantage of decreasing the moisture content of the steam at the turbine exit. Lowering the exhaust pressure or raising the boiler pressure, however, increases the moisture content. To take advantage of the improved efficiencies at higher boiler pressures and lower condenser pressures, steam is usually reheated after expanding partially in the highpressure turbine. This is done by extracting the steam after partial expansion in the highpressure turbine, sending it back to the boiler where it is reheated at constant pressure, and returning it to the lowpressure turbine for complete expansion to the condenser pressure. The average temperature during the  603 reheat process, and thus the thermal efficiency of the cycle, can be increased by increasing the number of expansion and reheat stages. As the number of stages is increased, the expansion and reheat processes approach an isothermal process at maximum temperature. Reheating also decreases the moisture content at the turbine exit. Another way of increasing the thermal efficiency of the Rankine cycle is regeneration. During a regeneration process, liquid water (feedwater) leaving the pump is heated by steam bled off the turbine at some intermediate pressure in devices called feedwater heaters. The two streams are mixed in open feedwater heaters, and the mixture leaves as a saturated liquid at the heater pressure. In closed feedwater heaters, heat is transferred from the steam to the feedwater without mixing. The production of more than one useful form of energy (such as process heat and electric power) from the same energy source is called cogeneration. Cogeneration plants produce electric power while meeting the process heat requirements of certain industrial processes. This way, more of the energy transferred to the fluid in the boiler is utilized for a useful purpose. The fraction of energy that is used for either process heat or power generation is called the utilization factor of the cogeneration plant. The overall thermal efficiency of a power plant can be increased by using a combined cycle. The most common combined cycle is the gas–steam combined cycle where a gasturbine cycle operates at the hightemperature range and a steamturbine cycle at the lowtemperature range. Steam is heated by the hightemperature exhaust gases leaving the gas turbine. Combined cycles have a higher thermal efficiency than the steam or gasturbine cycles operating alone. REFERENCES AND SUGGESTED READINGS
1. R. L. Bannister and G. J. Silvestri. “The Evolution of Central Station Steam Turbines.” Mechanical Engineering, February 1989, pp. 70–78. 2. R. L. Bannister, G. J. Silvestri, A. Hizume, and T. Fujikawa. “High Temperature Supercritical Steam Turbines.” Mechanical Engineering, February 1987, pp. 60–65. 3. M. M. ElWakil. Powerplant Technology. New York: McGrawHill, 1984. 4. K. W. Li and A. P. Priddy. Power Plant System Design. New York: John Wiley & Sons, 1985. 5. H. Sorensen. Energy Conversion Systems. New York: John Wiley & Sons, 1983. 6. Steam, Its Generation and Use. 39th ed. New York: Babcock and Wilcox Co., 1978. 7. Turbomachinery 28, no. 2 (March/April 1987). Norwalk, CT: Business Journals, Inc. 8. J. Weisman and R. Eckart. Modern Power Plant Engineering. Englewood Cliffs, NJ: PrenticeHall, 1985. cen84959_ch10.qxd 9/15/06 6:02 AM Page 604 604  Thermodynamics PROBLEMS*
Carnot Vapor Cycle
10–1C Why is excessive moisture in steam undesirable in steam turbines? What is the highest moisture content allowed? 10–2C Why is the Carnot cycle not a realistic model for steam power plants? 10–3E Water enters the boiler of a steadyflow Carnot engine as a saturated liquid at 180 psia and leaves with a quality of 0.90. Steam leaves the turbine at a pressure of 14.7 psia. Show the cycle on a Ts diagram relative to the saturation lines, and determine (a) the thermal efficiency, (b) the quality at the end of the isothermal heatrejection process, and (c) the net work output. Answers: (a) 19.3 percent,
(b) 0.153, (c) 148 Btu/lbm Pump work input: (a) increases, (b) decreases, (c) remains the same Turbine work (a) increases, (b) decreases, output: (c) remains the same Heat supplied: (a) increases, (b) decreases, (c) remains the same Heat rejected: (a) increases, (b) decreases, (c) remains the same Cycle efficiency: (a) increases, (b) decreases, (c) remains the same Moisture content (a) increases, (b) decreases, at turbine exit: (c) remains the same 10–4 A steadyflow Carnot cycle uses water as the working fluid. Water changes from saturated liquid to saturated vapor as heat is transferred to it from a source at 250°C. Heat rejection takes place at a pressure of 20 kPa. Show the cycle on a Ts diagram relative to the saturation lines, and determine (a) the thermal efficiency, (b) the amount of heat rejected, and (c) the net work output. 10–5 Repeat Prob. 10–4 for a heat rejection pressure of 10 kPa. 10–6 Consider a steadyflow Carnot cycle with water as the working fluid. The maximum and minimum temperatures in the cycle are 350 and 60°C. The quality of water is 0.891 at the beginning of the heatrejection process and 0.1 at the end. Show the cycle on a Ts diagram relative to the saturation lines, and determine (a) the thermal efficiency, (b) the pressure at the turbine inlet, and (c) the net work output.
Answers: (a) 0.465, (b) 1.40 MPa, (c) 1623 kJ/kg 10–9C Consider a simple ideal Rankine cycle with fixed turbine inlet temperature and condenser pressure. What is the effect of increasing the boiler pressure on
Pump work input: (a) increases, (b) decreases, (c) remains the same Turbine work (a) increases, (b) decreases, output: (c) remains the same Heat supplied: (a) increases, (b) decreases, (c) remains the same Heat rejected: (a) increases, (b) decreases, (c) remains the same Cycle efficiency: (a) increases, (b) decreases, (c) remains the same Moisture content (a) increases, (b) decreases, at turbine exit: (c) remains the same The Simple Rankine Cycle
10–7C What four processes make up the simple ideal Rankine cycle? 10–8C Consider a simple ideal Rankine cycle with fixed turbine inlet conditions. What is the effect of lowering the condenser pressure on 10–10C Consider a simple ideal Rankine cycle with fixed boiler and condenser pressures. What is the effect of superheating the steam to a higher temperature on
Pump work input: (a) increases, (b) decreases, (c) remains the same Turbine work (a) increases, (b) decreases, output: (c) remains the same Heat supplied: (a) increases, (b) decreases, (c) remains the same Heat rejected: (a) increases, (b) decreases, (c) remains the same Cycle efficiency: (a) increases, (b) decreases, (c) remains the same Moisture content (a) increases, (b) decreases, at turbine exit: (c) remains the same *Problems designated by a “C” are concept questions, and students are encouraged to answer them all. Problems designated by an “E” are in English units, and the SI users can ignore them. Problems with the icon are solved using EES, and complete solutions together with parametric studies are included on the enclosed DVD. Problems with the icon are comprehensive in nature, and are intended to be solved with a computer, preferably using the EES software that accompanies this text. 10–11C How do actual vapor power cycles differ from idealized ones? cen84959_ch10.qxd 9/15/06 6:02 AM Page 605 Chapter 10
10–12C Compare the pressures at the inlet and the exit of the boiler for (a) actual and (b) ideal cycles. 10–13C The entropy of steam increases in actual steam turbines as a result of irreversibilities. In an effort to control entropy increase, it is proposed to cool the steam in the turbine by running cooling water around the turbine casing. It is argued that this will reduce the entropy and the enthalpy of the steam at the turbine exit and thus increase the work output. How would you evaluate this proposal? 10–14C Is it possible to maintain a pressure of 10 kPa in a condenser that is being cooled by river water entering at 20°C?  605 10–18E A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 2500 psia in the boiler and 5 psia in the condenser. What is the minimum temperature required at the turbine inlet such that the quality of the steam leaving the turbine is not below 80 percent. When operated at this temperature, what is the thermal efficiency of this cycle? 10–19 A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 15 MPa in the boiler and 100 kPa in the condenser. Saturated steam enters the turbine. Determine the work produced by the turbine, the heat transferred in the boiler, and thermal efficiency of the cycle. Answer: 699 kJ/kg, 2178 kJ/kg, 31.4 percent 10–20 Reconsider Prob. 1019. Irreversibilities in the turbine cause the steam quality at the outlet of the turbine to be 70 percent. Determine the isentropic efficiency of the turbine and thermal efficiency of the cycle. Answers: 87.7 percent,
27.4 percent The Simple Rankine Cycle
10–15E The turbine of a steam power plant operating on a simple ideal Rankine cycle produces 500 kW of power when the boiler is operated at 500 psia, the condenser at 6 psia, and the temperature at the turbine entrance is 1200 F. Determine the rate of heat supply in the boiler, the rate of heat rejection in the condenser, and the thermal efficiency of the cycle. 10–16 A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 3 MPa in the boiler and 30 kPa in the condenser. If the quality at the exit of the turbine cannot be less than 85 percent, what is the maximum thermal efficiency this cycle can have? Answer:
29.7 percent 10–21E A steam Rankine cycle operates between the pressure limits of 2500 psia in the boiler and 1 psia in the condenser. The turbine inlet temperature is 800 F. The turbine isentropic efficiency is 90 percent, the pump losses are negligible, and the cycle is sized to produce 1000 kW of power. Calculate the mass flow rate through the boiler, the power produced by the turbine, the rate of heat supply in the boiler, and the thermal efficiency. 10–22E Reconsider Prob. 10–21E. How much error is caused in the thermal efficiency if the power required by the pump were completely neglected? 10–23 Consider a coalfired steam power plant that produces 300 MW of electric power. The power plant operates on a simple ideal Rankine cycle with turbine inlet conditions of 5 MPa and 450°C and a condenser pressure of 25 kPa. The coal has a heating value (energy released when the fuel is burned) of 29,300 kJ/kg. Assuming that 75 percent of this energy is transferred to the steam in the boiler and that the electric generator has an efficiency of 96 percent, determine (a) the overall plant efficiency (the ratio of net electric power output to the energy input as fuel) and (b) the required rate of coal supply. Answers: (a) 24.5 percent, (b) 150 t/h 10–24 Consider a solarpond power plant that operates on a simple ideal Rankine cycle with refrigerant134a as the working fluid. The refrigerant enters the turbine as a saturated vapor at 1.4 MPa and leaves at 0.7 MPa. The mass flow rate of the refrigerant is 3 kg/s. Show the cycle on a Ts diagram with respect to saturation lines, and determine (a) the thermal efficiency of the cycle and (b) the power output of this plant. 10–25 Consider a steam power plant that operates on a simple ideal Rankine cycle and has a net power output of 45 MW. Steam enters the turbine at 7 MPa and 500°C and is cooled in the condenser at a pressure of 10 kPa by running cooling water from a lake through the tubes of the condenser 10–17 A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 3 MPa in the boiler and 30 kPa in the condenser and a turbine inlet temperature of 700 C. The boiler is sized to provide a steam flow of 50 kg/s. Determine the power produced by the turbine and consumed by the pump. 3 m . Turbine Boiler Condenser 2 1 4 Feedwater pump FIGURE P10–17 cen84959_ch10.qxd 9/15/06 6:02 AM Page 606 606  Thermodynamics
10–29 Reconsider Prob. 10–28. Now, it is proposed that the liquid water coming out of the separator be routed through another flash chamber maintained at 150 kPa, and the steam produced be directed to a lower stage of the same turbine. Both streams of steam leave the turbine at the same state of 10 kPa and 90 percent quality. Determine (a) the temperature of steam at the outlet of the second flash chamber, (b) the power produced by the lower stage of the turbine, and (c) the thermal efficiency of the plant. at a rate of 2000 kg/s. Show the cycle on a Ts diagram with respect to saturation lines, and determine (a) the thermal efficiency of the cycle, (b) the mass flow rate of the steam, and (c) the temperature rise of the cooling water. Answers:
(a) 38.9 percent, (b) 36 kg/s, (c) 8.4°C 10–26 Repeat Prob. 10–25 assuming an isentropic efficiency of 87 percent for both the turbine and the pump.
Answers: (a) 33.8 percent, (b) 41.4 kg/s, (c) 10.5°C 10–27 The net work output and the thermal efficiency for the Carnot and the simple ideal Rankine cycles with steam as the working fluid are to be calculated and compared. Steam enters the turbine in both cases at 10 MPa as a saturated vapor, and the condenser pressure is 20 kPa. In the Rankine cycle, the condenser exit state is saturated liquid and in the Carnot cycle, the boiler inlet state is saturated liquid. Draw the Ts diagrams for both cycles. 10–28 The schematic of a singleflash geothermal power plant with state numbers is given in Fig. P10–28. Geothermal resource exists as saturated liquid at 230°C. The geothermal liquid is withdrawn from the production well at a rate of 230 kg/s, and is flashed to a pressure of 500 kPa by an essentially isenthalpic flashing process where the resulting vapor is separated from the liquid in a separator and directed to the turbine. The steam leaves the turbine at 10 kPa with a moisture content of 10 percent and enters the condenser where it is condensed and routed to a reinjection well along with the liquid coming off the separator. Determine (a) the mass flow rate of steam through the turbine, (b) the isentropic efficiency of the turbine, (c) the power output of the turbine, and (d ) the thermal efficiency of the plant (the ratio of the turbine work output to the energy of the geothermal fluid relative to standard ambient conditions). Answers: (a) 38.2 kg/s, (b) 0.686,
(c) 15.4 MW, (d) 7.6 percent 3 3 8 Separator I 2 6 Flash chamber 7 Flash chamber Condenser Separator II 5 9 Steam turbine 4 1 Production well Reinjection well FIGURE P10–29
10–30 Reconsider Prob. 10–28. Now, it is proposed that the liquid water coming out of the separator be used as the heat source in a binary cycle with isobutane as the working fluid. Geothermal liquid water leaves the heat exchanger at 90°C Steam turbine
Separator 3 Steam turbine 4 9 Condenser Aircooled condenser Separator 2 4 6
Isobutane turbine 5 Condenser Flash chamber 6 5 2 BINARY CYCLE 10 8
Heat exchanger Flash chamber Pump 11 7 1 Production well 1 Reinjection well
Production well Reinjection well FIGURE P10–28 FIGURE P10–30 cen84959_ch10.qxd 9/15/06 6:02 AM Page 607 Chapter 10
while isobutane enters the turbine at 3.25 MPa and 145°C and leaves at 80°C and 400 kPa. Isobutane is condensed in an aircooled condenser and then pumped to the heat exchanger pressure. Assuming an isentropic efficiency of 90 percent for the pump, determine (a) the mass flow rate of isobutane in the binary cycle, (b) the net power outputs of both the flashing and the binary sections of the plant, and (c) the thermal efficiencies of the binary cycle and the combined plant. The properties of isobutane may be obtained from EES. Answers:
(a) 105.5 kg/s, (b) 15.4 MW, 6.14 MW, (c) 12.2 percent, 10.6 percent  607 the highpressure turbine at 600 psia and 600 F, the inlet of the lowpressure turbine at 200 psia and 600 F, and the condenser at 10 psia. The net power produced by this plant is 5000 kW. Determine the rate of heat addition and rejection and the thermal efficiency of the cycle. 10–37E In Prob. 10–36E, is there any advantage to operating the reheat section of the boiler at 100 psia rather than 200 psia while maintaining the same lowpressure turbine inlet temperature? 10–38 Consider a steam power plant that operates on the ideal reheat Rankine cycle. The plant maintains the boiler at 4000 kPa, the reheat section at 500 kPa, and the condenser at 10 kPa. The mixture quality at the exit of both turbines is 90 percent. Determine the temperature at the inlet of each turbine and the cycle’s thermal efficiency. Answer: 292 C, 283 C,
33.5 percent The Reheat Rankine Cycle
10–31C How do the following quantities change when a simple ideal Rankine cycle is modified with reheating? Assume the mass flow rate is maintained the same.
Pump work input: (a) (c) Turbine work (a) output: (c) Heat supplied: (a) (c) Heat rejected: (a) (c) Moisture content (a) at turbine exit: (c) increases, (b) decreases, remains the same increases, (b) decreases, remains the same increases, (b) decreases, remains the same increases, (b) decreases, remains the same increases, (b) decreases, remains the same 3 m . Highpressure turbine Lowpressure turbine 4 6 5 Reheater 2 1 10–32C Is there an optimal pressure for reheating the steam of a Rankine cycle? Explain. 10–33C Consider a simple ideal Rankine cycle and an ideal Rankine cycle with three reheat stages. Both cycles operate between the same pressure limits. The maximum temperature is 700°C in the simple cycle and 450°C in the reheat cycle. Which cycle do you think will have a higher thermal efficiency? A steam power plant operates on the ideal reheat Rankine cycle. Steam enters the highpressure turbine at 8 MPa and 500°C and leaves at 3 MPa. Steam is then reheated at constant pressure to 500°C before it expands to 20 kPa in the lowpressure turbine. Determine the turbine work output, in kJ/kg, and the thermal efficiency of the cycle. Also, show the cycle on a Ts diagram with respect to saturation lines. 10–35 Reconsider Prob. 10–34. Using EES (or other) software, solve this problem by the diagram window data entry feature of EES. Include the effects of the turbine and pump efficiencies and also show the effects of reheat on the steam quality at the lowpressure turbine exit. Plot the cycle on a Ts diagram with respect to the saturation lines. Discuss the results of your parametric studies. 10–36E Consider a steam power plant that operates on the ideal reheat Rankine cycle. The plant maintains the inlet of 10–34 Feedwater pump FIGURE P10–38
10–39 Consider a steam power plant that operates on the ideal reheat Rankine cycle. The plant maintains the boiler at 17.5 MPa, the reheater at 2 MPa, and the condenser at 50 kPa. The temperature is 550 C at the entrance of the highpressure turbine, and 300 C at the entrance of the lowpressure turbine. Determine the thermal efficiency of this system. 10–40 How much does the thermal efficiency of the cycle in Prob. 10–39 change when the temperature at the entrance to the lowpressure turbine is increased to 550 C? 10–41 A steam power plant operates on an ideal reheat Rankine cycle between the pressure limits of 15 MPa and 10 kPa. The mass flow rate of steam through the cycle is 12 kg/s. Steam enters both stages of the turbine at 500°C. If the moisture content of the steam at the exit of the lowpressure turbine is not to cen84959_ch10.qxd 9/15/06 6:02 AM Page 608 608  Thermodynamics
since the extracted steam could produce some more work in the turbine. How do you justify this action? 10–45C How do open feedwater heaters differ from closed feedwater heaters? 10–46C Consider a simple ideal Rankine cycle and an ideal regenerative Rankine cycle with one open feedwater heater. The two cycles are very much alike, except the feedwater in the regenerative cycle is heated by extracting some steam just before it enters the turbine. How would you compare the efficiencies of these two cycles? 10–47C Devise an ideal regenerative Rankine cycle that has the same thermal efficiency as the Carnot cycle. Show the cycle on a Ts diagram. 10–48 Ten kilograms per second of cold feedwater enter a 200kPa open feedwater heater of a regenerative Rankine cycle at 70 C. Bleed steam is available from the turbine at 200 kPa and 160 C. At what rate must bleed steam be supplied to the open feedwater heater so the feedwater leaves this unit as a saturated liquid? 10–49E In a regenerative Rankine cycle, the closed feedwater heater with a pump as shown in the figure is arranged so that the water at state 5 is mixed with the water at state 2 to form a feedwater which is a saturated liquid at 200 psia. Feedwater enters this heater at 350 F and 200 psia with a flow rate of 2 lbm/s. Bleed steam is taken from the turbine at 160 psia and 400 F, and enters the pump as a saturated liquid at 160 psia. Determine the mass flow rate of bleed steam required to operate this unit. Answer: 0.0782 lbm/s
Bleed steam (from turbine) ˙ m3 3 2 Feedwater 1 ˙ m1 5 Forward to feedwater 4 exceed 10 percent, determine (a) the pressure at which reheating takes place, (b) the total rate of heat input in the boiler, and (c) the thermal efficiency of the cycle. Also, show the cycle on a Ts diagram with respect to saturation lines. 10–42 A steam power plant operates on the reheat Rankine cycle. Steam enters the highpressure turbine at 12.5 MPa and 550°C at a rate of 7.7 kg/s and leaves at 2 MPa. Steam is then reheated at constant pressure to 450°C before it expands in the lowpressure turbine. The isentropic efficiencies of the turbine and the pump are 85 percent and 90 percent, respectively. Steam leaves the condenser as a saturated liquid. If the moisture content of the steam at the exit of the turbine is not to exceed 5 percent, determine (a) the condenser pressure, (b) the net power output, and (c) the thermal efficiency.
Answers: (a) 9.73 kPa, (b) 10.2 MW, (c) 36.9 percent 3 Boiler 4 Turbine 6 5 2 Condenser Pump 1 FIGURE P10–42 Regenerative Rankine Cycle
10–43C How do the following quantities change when the simple ideal Rankine cycle is modified with regeneration? Assume the mass flow rate through the boiler is the same.
Turbine work output: Heat supplied: Heat rejected: Moisture content at turbine exit: (a) (c) (a) (c) (a) (c) (a) (c) increases, (b) decreases, remains the same increases, (b) decreases, remains the same increases, (b) decreases, remains the same increases, (b) decreases, remains the same FIGURE P10–49E
10–50E The closed feedwater heater of a regenerative Rankine cycle is to heat feedwater at 400 psia and 370 F to a saturated liquid at 400 psia. The turbine has bleed steam available at 300 psia and 500 F that will be condensed to a saturated liquid. How much bleed steam will be required to heat 1 lbm of feedwater in this unit? 10–44C During a regeneration process, some steam is extracted from the turbine and is used to heat the liquid water leaving the pump. This does not seem like a smart thing to do cen84959_ch10.qxd 9/15/06 6:02 AM Page 609 Chapter 10
10–51 Feedwater at 4000 kPa is heated at a rate of 6 kg/s from 200 C to 245 C in a closed feedwater heater of a regenerative Rankine cycle. Bleed steam enters this unit at 3000 kPa with a quality of 90 percent, and leaves as a saturated liquid. Calculate the rate at which bleed steam is required. 10–52 A steam power plant operates on an ideal regenerative Rankine cycle with two open feedwater heaters. Steam enters the turbine at 10 MPa and 600°C and exhausts to the condenser at 5 kPa. Steam is extracted from the turbine at 0.6 and 0.2 MPa. Water leaves both feedwater heaters as a saturated liquid. The mass flow rate of steam through the boiler is 22 kg/s. Show the cycle on a Ts diagram, and determine (a) the net power output of the power plant and (b) the thermal efficiency of the cycle. Answers: (a) 30.5 MW,
(b) 47.1 percent  609 bine efficiency for pump efficiencies of 70, 85, and 100 percent, and discuss the results. Also plot the Ts diagram for turbine and pump efficiencies of 85 percent. 10–55 Consider a steam power plant that operates on the ideal regenerative Rankine cycle with a closed feedwater heater as shown in the figure. The plant maintains the turbine inlet at 3000 kPa and 350 C; and operates the condenser at 20 kPa. Steam is extracted at 1000 kPa to serve the closed feedwater heater, which discharges into the condenser after being throttled to condenser pressure. Calculate the work produced by the turbine, the work consumed by the pump, and the heat supply in the boiler for this cycle per unit of boiler flow rate. Answer: 741 kJ/kg, 3.0 kJ/kg, 2353 kJ/kg
4 10–53 Consider an ideal steam regenerative Rankine cycle with two feedwater heaters, one closed and one open. Steam enters the turbine at 12.5 MPa and 550°C and exhausts to the condenser at 10 kPa. Steam is extracted from the turbine at 0.8 MPa for the closed feedwater heater and at 0.3 MPa for the open one. The feedwater is heated to the condensation temperature of the extracted steam in the closed feedwater heater. The extracted steam leaves the closed feedwater heater as a saturated liquid, which is subsequently throttled to the open feedwater heater. Show the cycle on a Ts diagram with respect to saturation lines, and determine (a) the mass flow rate of steam through the boiler for a net power output of 250 MW and (b) the thermal efficiency of the cycle. Boiler Turbine 6 5 3 2 7 Cond. 1 Closed FWH FIGURE P10–55
8 Turbine Boiler 9 Closed FWH y z 4 P II 5 6 3 7 Open FWH 2 1 PI 10 11 1–y –z 10–56 How much does the thermal efficiency of the cycle of Prob. 10–55 change when the steam serving the closed feedwater heater is extracted at 600 kPa rather than 1000 kPa? 10–57 Reconsider Prob. 10–55. Using EES (or other) software, determine the optimum bleed pressure for the closed feedwater heater that maximizes the thermal efficiency of the cycle. Answer: 220 kPa 10–58 Determine the thermal efficiency of the regenerative Rankine cycle of Prob. 10–55 when the isentropic efficiency of the turbine is 90 percent before and after steam extraction point. 10–59 Determine the thermal efficiency of the regenerative Rankine cycle of Prob. 10–55 when the isentropic efficiency of the turbine before and after steam extraction point is 90 percent and the condenser condensate is subcooled by 10 C. 10–60 Reconsider Prob. 10–55. Using EES (or other) software, determine how much additional heat must be supplied to the boiler when the turbine isentropic efficiency before and after the extraction point is 90 percent and there is a 10 kPa pressure drop across the boiler? Condenser FIGURE P10–53 10–54 Reconsider Prob. 10–53. Using EES (or other) software, investigate the effects of turbine and pump efficiencies as they are varied from 70 percent to 100 percent on the mass flow rate and thermal efficiency. Plot the mass flow rate and the thermal efficiency as a function of tur cen84959_ch10.qxd 9/15/06 6:02 AM Page 610 610  Thermodynamics
6 10–61E A steam power plant operates on an ideal reheat–regenerative Rankine cycle with one reheater and two open feedwater heaters. Steam enters the highpressure turbine at 1500 psia and 1100°F and leaves the lowpressure turbine at 1 psia. Steam is extracted from the turbine at 250 and 40 psia, and it is reheated to 1000°F at a pressure of 140 psia. Water leaves both feedwater heaters as a saturated liquid. Heat is transferred to the steam in the boiler at a rate of 4 105 Btu/s. Show the cycle on a Ts diagram with respect to saturation lines, and determine (a) the mass flow rate of steam through the boiler, (b) the net power output of the plant, and (c) the thermal efficiency of the cycle. Turbine Boiler 7 Process heater 5 9 8 FIGURE P10–62 SecondLaw Analysis of Vapor Power Cycles
7 Boiler Reheater HighP turbine 8 y 9 1–y y 6 Open FWH II 4 5 P III P II 3 PI Open FWH I 10 z Condenser 2 1 11 LowP turbine z 1–y–z 12 10–63C How can the secondlaw efficiency of a simple ideal Rankine cycle be improved? 10–64 Determine the exergy destruction associated with the heat rejection process in Prob. 10–25. Assume a source temperature of 1500 K and a sink temperature of 290 K. Also, determine the exergy of the steam at the boiler exit. Take P0 100 kPa. 10–65E Calculate the exergy destruction in each of the components of the simple ideal Rankine cycle of Prob. 10– 15E when heat is being rejected to a lake at 40 F, and heat is being supplied by a 1500 F energy reservoir. 10–66 Calculate the exergy destruction in each of the components of the simple ideal Rankine cycle of Prob. 10–17 when heat is being rejected to the atmospheric air at 15 C, and heat is supplied from an energy reservoir at 750 C.
Answer: 928 kJ/kg (boiler), 307 kJ/kg (condenser) FIGURE P10–61E 10–62 A steam power plant operates on the reheatregenerative Rankine cycle with a closed feedwater heater. Steam enters the turbine at 12.5 MPa and 550°C at a rate of 24 kg/s and is condensed in the condenser at a pressure of 20 kPa. Steam is reheated at 5 MPa to 550°C. Some steam is extracted from the lowpressure turbine at 1.0 MPa, is completely condensed in the closed feedwater heater, and pumped to 12.5 MPa before it mixes with the feedwater at the same pressure. Assuming an isentropic efficiency of 88 percent for both the turbine and the pump, determine (a) the temperature of the steam at the inlet of the closed feedwater heater, (b) the mass flow rate of the steam extracted from the turbine for the closed feedwater heater, (c) the net power output, and (d ) the thermal efficiency. Answers: (a) 328°C, (b) 4.29 kg/s,
(c) 28.6 MW, (d ) 39.3 percent 10–67E Calculate the exergy destruction in each of the components of the ideal reheat Rankine cycle of Prob. 10– 36E. The sink is at 77 F and the source is at 700 F. 10–68 Determine the exergy destruction associated with each of the processes of the reheat Rankine cycle described in Prob. 10–34. Assume a source temperature of 1800 K and a sink temperature of 300 K. 10–69 Reconsider Prob. 10–68. Using EES (or other) software, solve this problem by the diagram window data entry feature of EES. Include the effects of the turbine and pump efficiencies to evaluate the irreversibilities associated with each of the processes. Plot the cycle on a Ts diagram with respect to the saturation lines. Discuss the results of your parametric studies. 10–70 The schematic of a singleflash geothermal power plant with state numbers is given in Fig. P10–70. Geothermal cen84959_ch10.qxd 9/15/06 6:02 AM Page 611 Chapter 10
3 Steam turbine Separator 4 2 Flash chamber 6 Condenser 5 6  611 extracted steam is then condensed and mixed with feedwater at constant pressure and the mixture is pumped to the boiler pressure of 7 MPa. The mass flow rate of steam through the boiler is 30 kg/s. Disregarding any pressure drops and heat losses in the piping, and assuming the turbine and the pump to be isentropic, determine the net power produced and the utilization factor of the plant. 1 Production well Reinjection well Boiler · Q process
7 Turbine FIGURE P10–70
resource exists as saturated liquid at 230°C. The geothermal liquid is withdrawn from the production well at a rate of 230 kg/s and is flashed to a pressure of 500 kPa by an essentially isenthalpic flashing process where the resulting vapor is separated from the liquid in a separator and is directed to the turbine. The steam leaves the turbine at 10 kPa with a moisture content of 5 percent and enters the condenser where it is condensed; it is routed to a reinjection well along with the liquid coming off the separator. Determine (a) the power output of the turbine and the thermal efficiency of the plant, (b) the exergy of the geothermal liquid at the exit of the flash chamber, and the exergy destructions and the secondlaw (exergetic) efficiencies for (c) the flash chamber, (d) the turbine, and (e) the entire plant. Answers: (a) 10.8 MW, 0.053,
(b) 17.3 MW, (c) 5.1 MW, 0.898, (d) 10.9 MW, 0.500, (e) 39.0 MW, 0.218 5 8 Process heater 3 1 P II 4 2 PI Condenser FIGURE P10–75
10–76E A large foodprocessing plant requires 2 lbm/s of saturated or slightly superheated steam at 80 psia, which is extracted from the turbine of a cogeneration plant. The boiler generates steam at 1000 psia and 1000°F at a rate of 5 lbm/s, and the condenser pressure is 2 psia. Steam leaves the process heater as a saturated liquid. It is then mixed with the feedwater at the same pressure and this mixture is pumped to the boiler pressure. Assuming both the pumps and the turbine have isentropic efficiencies of 86 percent, determine (a) the rate of heat transfer to the boiler and (b) the power output of the cogeneration plant. Answers: (a) 6667 Btu/s, (b) 2026 kW 10–77 Steam is generated in the boiler of a cogeneration plant at 10 MPa and 450°C at a steady rate of 5 kg/s. In normal operation, steam expands in a turbine to a pressure of 0.5 MPa and is then routed to the process heater, where it supplies the process heat. Steam leaves the process heater as a saturated liquid and is pumped to the boiler pressure. In this mode, no steam passes through the condenser, which operates at 20 kPa. (a) Determine the power produced and the rate at which process heat is supplied in this mode. (b) Determine the power produced and the rate of process heat supplied if only 60 percent of the steam is routed to the process heater and the remainder is expanded to the condenser pressure. Cogeneration
10–71C How is the utilization factor Pu for cogeneration plants defined? Could Pu be unity for a cogeneration plant that does not produce any power? 10–72C Consider a cogeneration plant for which the utilization factor is 1. Is the irreversibility associated with this cycle necessarily zero? Explain. 10–73C Consider a cogeneration plant for which the utilization factor is 0.5. Can the exergy destruction associated with this plant be zero? If yes, under what conditions? 10–74C What is the difference between cogeneration and regeneration? 10–75 Steam enters the turbine of a cogeneration plant at 7 MPa and 500°C. Onefourth of the steam is extracted from the turbine at 600kPa pressure for process heating. The remaining steam continues to expand to 10 kPa. The cen84959_ch10.qxd 9/15/06 6:02 AM Page 612 612  Thermodynamics
10–81 An ideal cogeneration steam plant is to generate power and 8600 kJ/s of process heat. Steam enters the turbine from the boiler at 7 MPa and 500°C. Onefourth of the steam is extracted from the turbine at 600kPa pressure for process heating. The remainder of the steam continues to expand and exhausts to the condenser at 10 kPa. The steam extracted for the process heater is condensed in the heater and mixed with the feedwater at 600 kPa. The mixture is pumped to the boiler pressure of 7 MPa. Show the cycle on a Ts diagram with respect to saturation lines, and determine (a) the mass flow rate of steam that must be supplied by the boiler, (b) the net power produced by the plant, and (c) the utilization factor. 10–78 Consider a cogeneration power plant modified with regeneration. Steam enters the turbine at 6 MPa and 450°C and expands to a pressure of 0.4 MPa. At this pressure, 60 percent of the steam is extracted from the turbine, and the remainder expands to 10 kPa. Part of the extracted steam is used to heat the feedwater in an open feedwater heater. The rest of the extracted steam is used for process heating and leaves the process heater as a saturated liquid at 0.4 MPa. It is subsequently mixed with the feedwater leaving the feedwater heater, and the mixture is pumped to the boiler pressure. Assuming the turbines and the pumps to be isentropic, show the cycle on a Ts diagram with respect to saturation lines, and determine the mass flow rate of steam through the boiler for a net power output of 15 MW. Answer: 17.7 kg/s
6 6 Turbine Boiler 7 Boiler Turbine 5 Process heater 7 8 Process heater 5 9 8 P II PI 4 3 2 1 PI FWH 4 Condenser 3 2 PI Condenser 1 FIGURE P10–81 Combined Gas–Vapor Power Cycles
10–82C In combined gas–steam cycles, what is the energy source for the steam? 10–83C Why is the combined gas–steam cycle more efficient than either of the cycles operated alone? 10–84 Consider a combined gas–steam power plant that has a net power output of 450 MW. The pressure ratio of the gasturbine cycle is 14. Air enters the compressor at 300 K and the turbine at 1400 K. The combustion gases leaving the gas turbine are used to heat the steam at 8 MPa to 400°C in a heat exchanger. The combustion gases leave the heat exchanger at 460 K. An open feedwater heater incorporated with the steam cycle operates at a pressure of 0.6 MPa. The condenser pressure is 20 kPa. Assuming all the compression and expansion processes to be isentropic, determine (a) the mass flow rate ration of air to steam, (b) the required rate of heat input in the combustion chamber, and (c) thermal efficiency of the combined cycle. 10–85 Reconsider Prob. 10–84. Using EES (or other) software, study the effects of the gas cycle FIGURE P10–78
10–79 Reconsider Prob. 10–78. Using EES (or other) software, investigate the effect of the extraction pressure for removing steam from the turbine to be used for the process heater and open feedwater heater on the required mass flow rate. Plot the mass flow rate through the boiler as a function of the extraction pressure, and discuss the results. 10–80E Steam is generated in the boiler of a cogeneration plant at 600 psia and 800°F at a rate of 18 lbm/s. The plant is to produce power while meeting the process steam requirements for a certain industrial application. Onethird of the steam leaving the boiler is throttled to a pressure of 120 psia and is routed to the process heater. The rest of the steam is expanded in an isentropic turbine to a pressure of 120 psia and is also routed to the process heater. Steam leaves the process heater at 240°F. Neglecting the pump work, determine (a) the net power produced, (b) the rate of process heat supply, and (c) the utilization factor of this plant. cen84959_ch10.qxd 9/15/06 6:02 AM Page 613 Chapter 10
pressure ratio as it is varied from 10 to 20 on the ratio of gas flow rate to steam flow rate and cycle thermal efficiency. Plot your results as functions of gas cycle pressure ratio, and discuss the results. 10–86 A combined gas–steam power cycle uses a simple gas turbine for the topping cycle and simple Rankine cycle for the bottoming cycle. Atmospheric air enters the gas turbine at 101 kPa and 20 C, and the maximum gas cycle temperature is 1100 C. The compressor pressure ratio is 8; the compressor isentropic efficiency is 85 percent; and the gas turbine isentropic efficiency is 90 percent. The gas stream leaves the heat exchanger at the saturation temperature of the steam flowing through the heat exchanger. Steam flows through the heat exchanger with a pressure of 6000 kPa, and leaves at 320 C. The steamcycle condenser operates at 20 kPa, and the isentropic efficiency of the steam turbine is 90 percent. Determine the mass flow rate of air through the air compressor required for this system to produce 100 MW of power. Use constant specific heats for air at room temperature. Answer: 279 kg/s 10–87 An ideal regenerator is added to the gas cycle portion of the combined cycle in Prob. 10–86. How much does this change the efficiency of this combined cycle? 10–88 Determine which components of the combined cycle in Prob. 10–86 are the most wasteful of work potential. 10–89 Consider a combined gas–steam power plant that has a net power output of 450 MW. The pressure ratio of the gasturbine cycle is 14. Air enters the compressor at 300 K and the turbine at 1400 K. The combustion gases leaving the gas turbine are used to heat the steam at 8 MPa to 400°C in a heat exchanger. The combustion gases leave the heat exchanger at 460 K. An open feedwater heater incorporated with the steam cycle operates at a pressure of 0.6 MPa. The condenser pressure is 20 kPa. Assuming isentropic efficiences of 100 percent for the pump, 82 percent for the compressor, and 86 percent for the gas and steam turbines, determine (a) the mass flow rate ratio of air to steam, (b) the required rate of heat input in the combustion chamber, and (c) the thermal efficiency of the combined cycle. 10–90 Reconsider Prob. 10–89. Using EES (or other) software, study the effects of the gas cycle pressure ratio as it is varied from 10 to 20 on the ratio of gas flow rate to steam flow rate and cycle thermal efficiency. Plot your results as functions of gas cycle pressure ratio, and discuss the results. 10–91 Consider a combined gas–steam power cycle. The topping cycle is a simple Brayton cycle that has a pressure ratio of 7. Air enters the compressor at 15°C at a rate of 10 kg/s and the gas turbine at 950°C. The bottoming cycle is a reheat Rankine cycle between the pressure limits of 6 MPa and 10 kPa. Steam is heated in a heat exchanger at a rate of 1.15 kg/s by the exhaust gases leaving the gas turbine and the exhaust gases leave the heat exchanger at 200°C. Steam
Combustion chamber 8 9 Gas turbine  613 Compressor 7 11 Heat exchanger 10 3 Steam turbine 4 5 6 2 Condenser Pump 1 FIGURE P10–91
leaves the highpressure turbine at 1.0 MPa and is reheated to 400°C in the heat exchanger before it expands in the lowpressure turbine. Assuming 80 percent isentropic efficiency for all pumps and turbines, determine (a) the moisture content at the exit of the lowpressure turbine, (b) the steam temperature at the inlet of the highpressure turbine, (c) the net power output and the thermal efficiency of the combined plant. Special Topic: Binary Vapor Cycles
10–92C What is a binary power cycle? What is its purpose? 10–93C By writing an energy balance on the heat exchanger of a binary vapor power cycle, obtain a relation for the ratio of mass flow rates of two fluids in terms of their enthalpies. 10–94C Why is steam not an ideal working fluid for vapor power cycles? 10–95C Why is mercury a suitable working fluid for the topping portion of a binary vapor cycle but not for the bottoming cycle? 10–96C What is the difference between the binary vapor power cycle and the combined gas–steam power cycle? Review Problems
10–97 Show that the thermal efficiency of a combined gas–steam power plant hcc can be expressed as hcc hg hs hghs cen84959_ch10.qxd 9/15/06 6:02 AM Page 614 614  Thermodynamics
Vapor Condenser 9 8 Air 4 where hg Wg /Qin and hs Ws /Qg,out are the thermal efficiencies of the gas and steam cycles, respectively. Using this relation, determine the thermal efficiency of a combined power cycle that consists of a topping gasturbine cycle with an efficiency of 40 percent and a bottoming steamturbine cycle with an efficiency of 30 percent. 10–98 It can be shown that the thermal efficiency of a combined gas–steam power plant hcc can be expressed in terms of the thermal efficiencies of the gas and the steamturbine cycles as hcc hg hs hghs Prove that the value of hcc is greater than either of hg or hs. That is, the combined cycle is more efficient than either of the gasturbine or steamturbine cycles alone. 10–99 Consider a steam power plant operating on the ideal Rankine cycle with reheat between the pressure limits of 25 MPa and 10 kPa with a maximum cycle temperature of 600°C and a moisture content of 8 percent at the turbine exit. For a reheat temperature of 600°C, determine the reheat pressures of the cycle for the cases of (a) single and (b) double reheat. 10–100E The Stillwater geothermal power plant in Nevada, which started full commercial operation in 1986, is designed to operate with seven identical units. Each of these seven units consists of a pair of power cycles, labeled Level I and Level II, operating on the simple Rankine cycle using an organic fluid as the working fluid. The heat source for the plant is geothermal water (brine) entering the vaporizer (boiler) of Level I of each unit at 325°F at a rate of 384,286 lbm/h and delivering 22.79 MBtu/h (“M” stands for “million”). The organic fluid that enters the vaporizer at 202.2°F at a rate of 157,895 lbm/h leaves it at 282.4°F and 225.8 psia as saturated vapor. This saturated vapor expands in the turbine to 95.8°F and 19.0 psia and produces 1271 kW of electric power. About 200 kW of this power is used by the pumps, the auxiliaries, and the six fans of the condenser. Subsequently, the organic working fluid is condensed in an aircooled condenser by air that enters the condenser at 55°F at a rate of 4,195,100 lbm/h and leaves at 84.5°F. The working fluid is pumped and then preheated in a preheater to 202.2°F by absorbing 11.14 MBtu/h of heat from the geothermal water (coming from the vaporizer of Level II) entering the preheater at 211.8°F and leaving at 154.0°F. Taking the average specific heat of the geothermal water to be 1.03 Btu/lbm · °F, determine (a) the exit temperature of the geothermal water from the vaporizer, (b) the rate of heat rejection from the working fluid to the air in the condenser, (c) the mass flow rate of the geothermal water at the preheater, and (d ) the thermal efficiency of the Level I cycle of this geothermal power plant. Answers: (a) 267.4°F, (b) 29.7
MBtu/h, (c) 187,120 lbm/h, (d ) 10.8 percent Generator Turbine 5 Fluid pump 6 Preheater mgeo 3 Vaporizer Vapor Electricity 7 Working fluid 1 Land surface Production pump 2 Injection pump Cooler geothermal brine Hot geothermal brine FIGURE P10–100E Schematic of a binary geothermal power plant.
Courtesy of ORMAT Energy Systems, Inc. 10–101 A steam power plant operates on an ideal Rankine cycle with two stages of reheat and has a net power output of 120 MW. Steam enters all three stages of the turbine at 500°C. The maximum pressure in the cycle is 15 MPa, and the minimum pressure is 5 kPa. Steam is reheated at 5 MPa the first time and at 1 MPa the second time. Show the cycle on a Ts diagram with respect to saturation lines, and determine (a) the thermal efficiency of the cycle and (b) the mass flow rate of the steam. Answers: (a) 45.5 percent,
(b) 64.4 kg/s 10–102 A steam power plant operating on a simple ideal Rankine cycle maintains the boiler at 6000 kPa, the turbine inlet at 600 C, and the condenser at 50 kPa. Compare the thermal efficiency of this cycle when it is operated so that the liquid enters the pump as a saturated liquid against that when the liquid enters the pump 11.3 C cooler than a saturated liquid at the condenser pressure. cen84959_ch10.qxd 9/15/06 6:02 AM Page 615 Chapter 10
10–103 Consider a steam power plant that operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa and 500°C and the condenser at 10 kPa. The isentropic efficiency of the turbine is 80 percent, and that of the pumps is 95 percent. Steam is extracted from the turbine at 0.5 MPa to heat the feedwater in an open feedwater heater. Water leaves the feedwater heater as a saturated liquid. Show the cycle on a Ts diagram, and determine (a) the mass flow rate of steam through the boiler and (b) the thermal efficiency of the cycle. Also, determine the exergy destruction associated with the regeneration process. Assume a source temperature of 1300 K and a sink temperature of 303 K.  615 feedwater heater at 3500 kPa, and the open feedwater heater at 100 kPa. The temperature at the inlet of both turbines is 400 C. Determine the following quantities for this system per unit mass flow rate through the boiler. (a) The flow rate required to service the highpressure, closed feedwater heater. (b) The flow rate required to service the lowpressure, closed feedwater heater. (c) The flow rate required to service the open feedwater heater. (d) The flow through the condenser. (e) The work produced by the highpressure turbine. ( f ) The work produced by the lowpressure turbine. (g) The heat supplied in the boiler and reheater. (h) The heat rejected in the condenser. (i) The thermal efficiency. 6 Turbine Boiler 7 5 Process heater 3 P II 4 2 PI 1 10 11 Closed 8 FWH I 96 P IV 7 Conde 12 14 Boiler 16 13 HighP Turbine LowP Turbine 19 17 15 18 Condenser Closed FWH II 5 P III 4 P II 3 Open FWH 2 PI 1 FIGURE P10–103
10–104 Repeat Prob. 10–103 assuming both the pump and the turbine are isentropic. 10–105 Consider an ideal reheat–regenerative Rankine cycle with one open feedwater heater. The boiler pressure is 10 MPa, the condenser pressure is 15 kPa, the reheater pressure is 1 MPa, and the feedwater pressure is 0.6 MPa. Steam enters both the high and lowpressure turbines at 500°C. Show the cycle on a Ts diagram with respect to saturation lines, and determine (a) the fraction of steam extracted for regeneration and (b) the thermal efficiency of the cycle.
Answers: (a) 0.144, (b) 42.1 percent FIGURE P10–107
10–108 Reconsider Prob. 10–107. Using EES (or other) software, determine the optimum bleed pressure for the open feedwater heater that maximizes the thermal efficiency of the cycle. 10–109E Atmospheric air enters the air compressor of a simple combined gassteam power system at 14.7 psia and 80 F. The air compressor’s compression ratio is 10; the gas cycle’s maximum temperature is 2100 F; and the air compressor and turbine have an isentropic efficiency of 90 percent. The gas leaves the heat exchanger 50 F hotter than the saturation temperature of the steam in the heat exchanger. The steam pressure in the heat exchanger is 800 psia, and the steam leaves the heat exchanger at 600 F. The steamcondenser pressure is 5 psia and the isentropic efficiency of the steam turbine is 95 percent. Determine the overall thermal efficiency of this combined cycle. For air, use constant specific heats at room temperature. Answer: 46.4 percent 10–106 Repeat Prob. 10–105 assuming an isentropic efficiency of 84 percent for the turbines and 100 percent for the pumps. 10–107 A steam power plant operating on the ideal reheatregenerative Rankine cycle with three feedwater heaters as shown in the figure maintains the boiler at 8000 kPa, the condenser at 10 kPa, the reheater at 300 kPa, the highpressure, closed feedwater heater at 6000 kPa, the lowpressure, closed cen84959_ch10.qxd 9/15/06 6:02 AM Page 616 616  Thermodynamics
feedwater at constant pressure. The mixture is pumped to the boiler pressure. Assuming an isentropic efficiency of 88 percent for both the turbine and the pumps, determine (a) the rate of process heat supply, (b) the net power output, and (c) the utilization factor of the plant. Answers: (a) 8.56 MW,
(b) 8.60 MW, (c) 53.8 percent 6 10–110E It has been suggested that the steam passing through the condenser of the combined cycle in Prob. 10– 109E be routed to buildings during the winter to heat them. When this is done, the pressure in the heating system where the steam is now condensed will have to be increased to 10 psia. How does this change the overall thermal efficiency of the combined cycle? 10–111E During winter, the system of Prob. 10–110E must supply 2 10 6 Btu/h of heat to the buildings. What is the mass flow rate of air through the air compressor and the system’s total electrical power production in winter? Answers:
27,340 lbm/h, 1286 kW Turbine Boiler 7 5 Process heater 3 P II 4 2 PI 1 Condenser 8 10–112 The gasturbine cycle of a combined gas–steam power plant has a pressure ratio of 8. Air enters the compressor at 290 K and the turbine at 1400 K. The combustion gases leaving the gas turbine are used to heat the steam at 15 MPa to 450°C in a heat exchanger. The combustion gases leave the heat exchanger at 247°C. Steam expands in a highpressure turbine to a pressure of 3 MPa and is reheated in the combustion chamber to 500°C before it expands in a lowpressure turbine to 10 kPa. The mass flow rate of steam is 30 kg/s. Assuming all the compression and expansion processes to be isentropic, determine (a) the mass flow rate of air in the gasturbine cycle, (b) the rate of total heat input, and (c) the thermal efficiency of the combined cycle.
Answers: (a) 263 kg/s, (b) 2.80 105 kJ/s, (c) 55.6 percent FIGURE P10–116
10–117 A Rankine steam cycle modified for reheat, a closed feedwater heater, and an open feedwater heater is shown below. The highpressure turbine receives 100 kg/s of steam from the steam boiler. The feedwater heaters exit states for the boiler feedwater and the condensed steam are the normally assumed ideal states. The following data tables give the saturation data for the pressures and data for h and s at selected states. (a) Sketch the Ts diagram for the ideal cycle. (b) Determine the net power output of the cycle, in MW. (c) If cooling water is available at 25°C, what is the minimum flow rate of the cooling water required for the ideal cycle, in 4.18 kJ/kg # K. kg/s? Take cp, water
Process states and selected data State 1 2 3 4 5 6 7 8 9 10 11 P, kPa 20 1400 1400 1400 5000 5000 1400 1200 1200 245 20 T , °C h, kJ/kg s, kJ/kg # K 10–113 Repeat Prob. 10–112 assuming isentropic efficiencies of 100 percent for the pump, 80 percent for the compressor, and 85 percent for the gas and steam turbines. 10–114 Starting with Eq. 10–20, show that the exergy destruction associated with a simple ideal Rankine cycle can be expressed as i qin(hth,Carnot hth), where hth is efficiency of the Rankine cycle and hth,Carnot is the efficiency of the Carnot cycle operating between the same temperature limits. 10–115 Steam is to be supplied from a boiler to a highpressure turbine whose isentropic efficiency is 75 percent at conditions to be determined. The steam is to leave the highpressure turbine as a saturated vapor at 1.4 MPa, and the turbine is to produce 1 MW of power. Steam at the turbine exit is extracted at a rate of 1000 kg/min and routed to a process heater while the rest of the steam is supplied to a lowpressure turbine whose isentropic efficiency is 60 percent. The lowpressure turbine allows the steam to expand to 10 kPa pressure and produces 0.8 MW of power. Determine the temperature, pressure, and the flow rate of steam at the inlet of the highpressure turbine. 10–116 A textile plant requires 4 kg/s of saturated steam at 2 MPa, which is extracted from the turbine of a cogeneration plant. Steam enters the turbine at 8 MPa and 500°C at a rate of 11 kg/s and leaves at 20 kPa. The extracted steam leaves the process heater as a saturated liquid and mixes with the 700 600 3894 3400 3349 3692 3154 2620 7.504 7.504 7.504 7.938 7.938 7.938 cen84959_ch10.qxd 9/15/06 6:02 AM Page 617 Chapter 10
6  617 .
Qin Boiler 8 HighP Turbine LowP Turbine Wturb . 5 9 4 y z 7 10 11 Cooling Water inlet Condenser .
Wpump 3 2 Cooling Water outlet .1 Wpump
Steam trap 13 12 FIGURE P10–117 Saturation data P, kPa 20 245 1200 1400 5000 T, °C 60.1 126.7 188 195 264 vf , m 3/kg 0.00102 0.00106 0.00114 0.00115 0.00129 hf , kJ/kg 251.4 532 798 830 1154 sg, kJ/kg # K 7.791 7.061 6.519 6.519 5.979 10–118 A Rankine steam cycle modified for reheat and three closed feedwater heaters is shown below. The high pressure turbine receives 100 kg/s of steam from the steam boiler. The feedwater heaters exit states for the boiler feedwater and the condensed steam are the normally assumed ideal states. The following data tables give the saturation data for the pressures and data for h and s at selected states. (a) Sketch the Ts diagram for the ideal cycle. (b) Determine the net power output of the cycle, in MW. (c) If the cooling water is limited to a 10°C temperature rise, what is the flow rate of the cooling water required for the ideal cycle, in kg/s? Take 4.18 kJ/kg # K. cp,water 7 Qin Boiler 8 y 4 z 3 11 12 w . .
LowP Turbine Wturb 13 Cooling Water inlet Condenser Cooling Water outlet HighP Turbine 6 5 17 9 10 Steam trap Mixing Chamber 2 16 1 Wpump . 14 15 .
Wpump 18 19 FIGURE P10–118 cen84959_ch10.qxd 9/15/06 6:02 AM Page 618 618  Thermodynamics
s, kJ/kg # K Process states and selected data State 1 2 3 4 5 6 7 8 9 10 11 12 13 P, kPa 10 5000 5000 5000 5000 5000 5000 2500 2500 925 300 75 10 T, oC h, kJ/kg the performance of an ideal regenerative Rankine cycle. Steam enters the turbine at 15 MPa and 600°C and the condenser at 5 kPa. For each case, maintain about the same temperature difference between any two regeneration stages. Determine the thermal efficiency of the cycle, and plot it against the number of regeneration stages for 1, 2, 3, 4, 5, 6, 8, and 10 regeneration stages. Fundamentals of Engineering (FE) Exam Problems
700 600 3900 3615 3687 3330 3011 2716 2408 7.5136 7.5136 7.5979 7.5979 7.5979 7.5979 7.5979 10–123 Consider a steadyflow Carnot cycle with water as the working fluid executed under the saturation dome between the pressure limits of 8 MPa and 20 kPa. Water changes from saturated liquid to saturated vapor during the heat addition process. The net work output of this cycle is (a) 494 kJ/kg (d ) 845 kJ/kg (b) 975 kJ/kg (e) 1148 kJ/kg (c) 596 kJ/kg Saturation data P, kPa 10 75 300 925 2500 5000 T, oC 45.8 91.8 133.5 176.5 224.0 263.9 vf , m 3/kg 0.001010 0.001037 0.001073 0.001123 0.001197 0.001286 hf , kJ/kg 191.8 384.4 561.4 747.7 961.9 1154.5 sg, kJ/kg # K 8.149 7.456 6.992 6.612 6.256 5.974 10–124 A simple ideal Rankine cycle operates between the pressure limits of 10 kPa and 3 MPa, with a turbine inlet temperature of 600°C. Disregarding the pump work, the cycle efficiency is (a) 24 percent (d ) 63 percent (b) 37 percent (e) 71 percent (c) 52 percent 10–125 A simple ideal Rankine cycle operates between the pressure limits of 10 kPa and 5 MPa, with a turbine inlet temperature of 600°C. The mass fraction of steam that condenses at the turbine exit is (a) 6 percent (d ) 15 percent (b) 9 percent (e) 18 percent (c) 12 percent 10–119 Using EES (or other) software, investigate the effect of the condenser pressure on the performance of a simple ideal Rankine cycle. Turbine inlet conditions of steam are maintained constant at 5 MPa and 500°C while the condenser pressure is varied from 5 to 100 kPa. Determine the thermal efficiency of the cycle and plot it against the condenser pressure, and discuss the results. 10–120 Using EES (or other) software, investigate the effect of superheating the steam on the performance of a simple ideal Rankine cycle. Steam enters the turbine at 3 MPa and exits at 10 kPa. The turbine inlet temperature is varied from 250 to 1100°C. Determine the thermal efficiency of the cycle and plot it against the turbine inlet temperature, and discuss the results. 10–121 Using EES (or other) software, investigate the effect of number of reheat stages on the performance of an ideal Rankine cycle. The maximum and minimum pressures in the cycle are 15 MPa and 10 kPa, respectively, and steam enters all stages of the turbine at 500°C. For each case, maintain roughly the same pressure ratio across each turbine stage. Determine the thermal efficiency of the cycle and plot it against the number of reheat stages 1, 2, 4, and 8, and discuss the results. 10–122 Using EES (or other) software, investigate the effect of the number of regeneration stages on 10–126 A steam power plant operates on the simple ideal Rankine cycle between the pressure limits of 10 kPa and 10 MPa, with a turbine inlet temperature of 600°C. The rate of heat transfer in the boiler is 800 kJ/s. Disregarding the pump work, the power output of this plant is (a) 243 kW (d ) 335 kW (b) 284 kW (e) 800 kW (c) 508 kW 10–127 Consider a combined gassteam power plant. Water for the steam cycle is heated in a wellinsulated heat exchanger by the exhaust gases that enter at 800 K at a rate of 60 kg/s and leave at 400 K. Water enters the heat exchanger at 200°C and 8 MPa and leaves at 350°C and 8 MPa. If the exhaust gases are treated as air with constant specific heats at room temperature, the mass flow rate of water through the heat exchanger becomes (a) 11 kg/s (d ) 53 kg/s (b) 24 kg/s (e) 60 kg/s (c) 46 kg/s 10–128 An ideal reheat Rankine cycle operates between the pressure limits of 10 kPa and 8 MPa, with reheat occurring at 4 MPa. The temperature of steam at the inlets of both turbines is 500°C, and the enthalpy of steam is 3185 kJ/kg at the exit of the highpressure turbine, and 2247 kJ/kg at the exit cen84959_ch10.qxd 9/15/06 6:02 AM Page 619 Chapter 10
of the lowpressure turbine. Disregarding the pump work, the cycle efficiency is (a) 29 percent (d ) 41 percent (b) 32 percent (e) 49 percent (c) 36 percent (a) (b) (c) (d) (e)  619 the turbine work output will decrease. the amount of heat rejected will increase. the cycle thermal efficiency will decrease. the quality of steam at turbine exit will decrease. the amount of heat input will increase. 10–129 Pressurized feedwater in a steam power plant is to be heated in an ideal open feedwater heater that operates at a pressure of 0.5 MPa with steam extracted from the turbine. If the enthalpy of feedwater is 252 kJ/kg and the enthalpy of extracted steam is 2665 kJ/kg, the mass fraction of steam extracted from the turbine is (a) 4 percent (d ) 27 percent (b) 10 percent (e) 12 percent (c) 16 percent 10–130 Consider a steam power plant that operates on the regenerative Rankine cycle with one open feedwater heater. The enthalpy of the steam is 3374 kJ/kg at the turbine inlet, 2797 kJ/kg at the location of bleeding, and 2346 kJ/kg at the turbine exit. The net power output of the plant is 120 MW, and the fraction of steam bled off the turbine for regeneration is 0.172. If the pump work is negligible, the mass flow rate of steam at the turbine inlet is (a) 117 kg/s (d ) 268 kg/s (b) 126 kg/s (e) 679 kg/s (c) 219 kg/s 10–135 Consider a cogeneration power plant modified with regeneration. Steam enters the turbine at 6 MPa and 450°C at a rate of 20 kg/s and expands to a pressure of 0.4 MPa. At this pressure, 60 percent of the steam is extracted from the turbine, and the remainder expands to a pressure of 10 kPa. Part of the extracted steam is used to heat feedwater in an open feedwater heater. The rest of the extracted steam is used for process heating and leaves the process heater as a saturated liquid at 0.4 MPa. It is subsequently mixed with the feedwater leaving the feedwater heater, and the mixture is pumped to the boiler pressure. The steam in the condenser is cooled and condensed by the cooling water from a nearby river, which enters the adiabatic condenser at a rate of 463 kg/s. 1. The total power output of the turbine is (a) 17.0 MW (d ) 20.0 MW (b) 8.4 MW (e) 3.4 MW (c) 12.2 MW 10–131 Consider a simple ideal Rankine cycle. If the condenser pressure is lowered while keeping turbine inlet state the same, (a) the turbine work output will decrease. (b) the amount of heat rejected will decrease. (c) the cycle efficiency will decrease. (d ) the moisture content at turbine exit will decrease. (e) the pump work input will decrease. 10–132 Consider a simple ideal Rankine cycle with fixed boiler and condenser pressures. If the steam is superheated to a higher temperature, (a) the turbine work output will decrease. (b) the amount of heat rejected will decrease. (c) the cycle efficiency will decrease. (d ) the moisture content at turbine exit will decrease. (e) the amount of heat input will decrease. 10–133 Consider a simple ideal Rankine cycle with fixed boiler and condenser pressures. If the cycle is modified with reheating, (a) the turbine work output will decrease. (b) the amount of heat rejected will decrease. (c) the pump work input will decrease. (d ) the moisture content at turbine exit will decrease. (e) the amount of heat input will decrease. 10–134 Consider a simple ideal Rankine cycle with fixed boiler and condenser pressures. If the cycle is modified with regeneration that involves one open feedwater heater (select the correct statement per unit mass of steam flowing through the boiler), 2. The temperature rise of the cooling water from the river in the condenser is (a) 8.0°C (d ) 12.9°C (a) 1.6 kg/s (d ) 7.6 kg/s (b) 5.2°C (e) 16.2°C (b) 3.8 kg/s (e) 10.4 kg/s
h6 6 (c) 9.6°C 3. The mass flow rate of steam through the process heater is (c) 5.2 kg/s 3302.9 kJ/kg 20 kg/s Boiler h7 h8 h10 2665.6 kJ/kg 8 Process heater 7 10 Turbine h11 11 2128.8 5 h5 9 610.73 Condenser P II 4 h3 h4 3 h9 FWH 2 604.66 h2 PI 192.20 1 h1 ΔT 463 kg/s 191.81 FIGURE P10–135 cen84959_ch10.qxd 9/15/06 6:02 AM Page 620 620  Thermodynamics
tively. Highpressure flash chambers yield a small amount of steam with high exergy whereas lowerpressure flash chambers yield considerably more steam but at a lower exergy. By trying several pressures, determine the optimum pressure of the flash chamber to maximize the power production per unit mass of geothermal water withdrawn. Also, determine the thermal efficiency for each case assuming 10 percent of the power produced is used to drive the pumps and other auxiliary equipment. 10–139 A natural gas–fired furnace in a textile plant is used to provide steam at 130°C. At times of high demand, the furnace supplies heat to the steam at a rate of 30 MJ/s. The plant also uses up to 6 MW of electrical power purchased from the local power company. The plant management is considering converting the existing process plant into a cogeneration plant to meet both their processheat and power requirements. Your job is to come up with some designs. Designs based on a gas turbine or a steam turbine are to be considered. First decide whether a system based on a gas turbine or a steam turbine will best serve the purpose, considering the cost and the complexity. Then propose your design for the cogeneration plant complete with pressures and temperatures and the mass flow rates. Show that the proposed design meets the power and processheat requirements of the plant. 10–140 Design the condenser of a steam power plant that has a thermal efficiency of 40 percent and generates 10 MW of net electric power. Steam enters the condenser as saturated vapor at 10 kPa, and it is to be condensed outside horizontal tubes through which cooling water from a nearby river flows. The temperature rise of the cooling water is limited to 8°C, and the velocity of the cooling water in the pipes is limited to 6 m/s to keep the pressure drop at an acceptable level. From prior experience, the average heat flux based on the outer surface of the tubes can be taken to be 12,000 W/m2. Specify the pipe diameter, total pipe length, and the arrangement of the pipes to minimize the condenser volume. 10–141 Watercooled steam condensers are commonly used in steam power plants. Obtain information about watercooled steam condensers by doing a literature search on the topic and also by contacting some condenser manufacturers. In a report, describe the various types, the way they are designed, the limitation on each type, and the selection criteria. 10–142 The technology for power generation using geothermal energy is well established, and numerous geothermal power plants throughout the world are currently generating electricity economically. Binary geothermal plants utilize a volatile secondary fluid such as isobutane, npentane, and R114 in a closed loop. Consider a binary geothermal plant with R114 as the working fluid that is flowing at a rate of 600 kg/s. The R114 is vaporized in a boiler at 115°C by the geothermal fluid that enters at 165°C, and is condensed at 30°C outside the tubes by cooling water that enters the tubes at 4. The rate of heat supply from the process heater per unit mass of steam passing through it is (a) 246 kJ/kg (d ) 1891 kJ/kg (a) 26.0 MJ/s (d ) 62.8 MJ/s (b) 893 kJ/kg (e) 2060 kJ/kg (b) 53.8 MJ/s (e) 125.4 MJ/s (c) 1344 kJ/kg 5. The rate of heat transfer to the steam in the boiler is (c) 39.5 MJ/s Design and Essay Problems
10–136 Design a steam power cycle that can achieve a cycle thermal efficiency of at least 40 percent under the conditions that all turbines have isentropic efficiencies of 85 percent and all pumps have isentropic efficiencies of 60 percent. Prepare an engineering report describing your design. Your design report must include, but is not limited to, the following: (a) Discussion of various cycles attempted to meet the goal as well as the positive and negative aspects of your design. (b) System figures and Ts diagrams with labeled states and temperature, pressure, enthalpy, and entropy information for your design. (c) Sample calculations. 10–137 Contact your power company and obtain information on the thermodynamic aspects of their most recently built power plant. If it is a conventional power plant, find out why it is preferred over a highly efficient combined power plant. 10–138 A 10MW geothermal power plant is being considered at a site where geothermal water at 230°C is available. Geothermal water is to be flashed into a chamber to a lower pressure where part of the water evaporates. The liquid is returned to the ground while the vapor is used to drive the steam turbine. The pressures at the turbine inlet and the turbine exit are to remain above 200 kPa and 8 kPa, respec Turbine Flash chamber 230°C Geothermal water FIGURE P10–138 cen84959_ch10.qxd 9/15/06 6:02 AM Page 621 Chapter 10
18°C. Based on prior experience, the average heat flux based on the outer surface of the tubes can be taken to be 4600 W/m2. The enthalpy of vaporization of R114 at 30°C is hfg 121.5 kJ/kg. Specify (a) the length, diameter, and number of tubes and their arrangement in the condenser to minimize overall volume of the condenser; (b) the mass flow rate of cooling water; and (c) the flow rate of makeup water needed if a cooling tower is used to reject the waste heat from the cool  621 ing water. The liquid velocity is to remain under 6 m/s and the length of the tubes is limited to 8 m. 10–143 Stack gases exhausting from electrical power plants are at approximately 150 C. Design a basic Rankine cycle that uses water, refrigerant134a, or ammonia as the working fluid and that produces the maximum amount of work from this energy source while rejecting heat to the ambient air at 40 C. You are to use a turbine whose efficiency is 92 percent and whose exit quality cannot be less than 85 percent. cen84959_ch10.qxd 9/15/06 6:02 AM Page 622 ...
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