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Physics 211 - Final Review Key

# Physics 211 - Final Review Key - Physics 211 Mechanics...

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A 28 o B 3.0m m m Physics 211: Mechanics Final Review Page 1 of 6 Summary of Equations, Constants, and Conversion Factors Motion = v drdt = a dvdt Linear Motion = + + r r0 v0t 12a0t2 = + v v0 at = + v2 v02 2ar Uniform Circular Motion = ac v2r = ac ω2r = T 2πrv Rotational Motion = + θ ω0t 12αt2 = + ω ω0 αt = + ω2 ω02 2αθ Simple Harmonic Motion = + x Acosωt ϕ =- ( + ) v ωA sin ωt ϕ =- ( + ) a ω2A cos ωt ϕ = ω 2πf = f 1T - v ωA2 x2 =- a ω2x Wave Motion ( , )= ( - ) y x t A sin kx ωt = k 2πλ = ω 2πT = v fλ = λn 2Ln = v FTμ Pendulum Motion Simple: = T 2πLg Physical: = T 2πImgh Linear Kinetics = P mv = F ma = F dPdt = fs μsFn = fk μkFn = D 12CρAv2 Rotational Kinetics = L Iω = × l r P = τ rF = × τ r F = τ dLdt = + I Icom mh2 = I mr2 Simple Harmonic Kinetics =- F kx = k ω2m Elasticity = FA EΔLL = FA GΔxL = p BΔVV Energy = + + + E Ue Ug Kr Kt = Ue 12kx2 = Ug mgh = Kr 12Iω2 = Kt 12mv2 Work = = = w x0x1Fxdx Fr τθ = = = = P dwdt dEdt Fv τω = + = wnet wnc wc ΔK =- wc ΔU = wnc ΔE =- Fx dUdx Gravity = = Fg W GmMR2 =- Ug GmMR Constants/Conversions = . × - G 6 67 10 11 = . / g 9 81 m s2 = . × / c 3 0 108m s = 1 rev 2π rad = . 1 hp 745 7 W

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Physics 211: Mechanics Final Review Page 2 of 6 Part I: Motion in One Dimension 1. At a certain time a particle had a speed of 18 m/s in the positive x direction, and 2.4 s later its speed was 30 m/s in the opposite direction. What is the average acceleration of the particle during this 2.4 s interval? Answer: -20 m/s 2 2. A key falls from a bridge that is 45 m above the water. It falls directly into a model boat, moving with constant velocity, that is 12 m from the point of impact when the key is released. What is the speed of the boat? Answer: 4.0 m/s 3. A shuffleboard disk is accelerated at a constant rate from rest to a speed of 6.0 m/s over a 1.8 m distance by a player using a cue. At this point the disk loses contact with the cue and slows at a constant rate of 2.5 m/s 2 until it stops. (a) How much time elapses from when the disk begins to accelerate until it stops? (b) What total distance does the disk travel? Answer: (a) 3.0 s (b) 9.0 m 4. A Chevy truck is cruising down the highway at a constant 66.0 f/s. At time t = 0 a BMW moving at 144 f/s is 301 feet behind the truck. If at that instant the BMW starts to slow down at a constant rate of magnitude 14.0 f/s 2 , at what time will the BMW be closest to the Chevy? The Chevy’s velocity does not change. Answer: 5.57 s Part II: Motion in Two Dimensions 5. A football player punts the football so that it will have a “hang time” (time of flight) of 4.5 s and land 46 m away. If the ball leaves the player’s foot 150 cm above the ground, what must be the (a) magnitude and (b) angle (relative to the horizontal) of the ball’s initial velocity? Answer: (a) 24 m/s (b) 65°
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Physics 211 - Final Review Key - Physics 211 Mechanics...

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