Test__3_spring_2008_solution

Test__3_spring_2008_solution - Physics 211 Test 3 spring...

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The net work done equals the change in the object’s kinetic energy: Work = K Work = ½ (10 m)(60 N) = 300 J ½ (5 kg)v 2 – ½ (5 kg)(2 m/s) 2 = 300 J v = 11.1 m/s U (x) E 32 o 45 o V 1 V 2 Before Collision After Collision m m m m +y +x 2 m/s ? 165 m/s 5 m/s M m m M After Before Released from rest m horizontal 35 o A 2 m/s 6 m/s B Physics 211 Test 3 spring 2008 Name:____________________________ 1. The net force acting on a 5.00 kg object as it moves along the +x axis is in the + x direction and is shown on this graph of net force as a function of the object’s position. If the object was moving with a velocity of 2.00 m/s in the + x direction as it passes the origin, what is the object’s velocity as it passes the point x = 10.0 m? 2. An object moves on the x-axis while influenced only by the conservative force associated with the potential energy function shown in this graph. The total mechanical energy of the system is 0.800 kilojoule. Between what points does
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Test__3_spring_2008_solution - Physics 211 Test 3 spring...

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