Comprehensive+beam+problem

Comprehensive+beam+problem - Lecture8_problem.nb...

Info iconThis preview shows pages 1–21. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 12
Background image of page 13

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 14
Background image of page 15

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 16
Background image of page 17

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 18
Calculations for the problem worked out in lacture 8 In[1]:= Clear @ x D In[2]:= Clear @ y D Definition of loads and geometry In[3]:= Sy = - 1000 Out[3]= - 1000 In[4]:= h = 0.1 Out[4]= 0.1 In[5]:= t = 0.003 Out[5]= 0.003 In[6]:= Mx = 500 Out[6]= 500 Coordinates of the centroids of the two rectangular areas referred to the global centroidal reference system In[7]:= xc1 = - h ê 8 Out[7]= - 0.0125 In[8]:= yc1 = h ê 4 Out[8]= 0.025 In[9]:= xc2 = h ê 8 Out[9]= 0.0125 In[10]:= yc2 = - h ê 4 Out[10]= - 0.025 Moments of inertia with respect to the centroidal axes In[11]:= Ixx = h * t * yc1^2 + H 1 ê 12 L * t * h^3 + h * t * yc2^2 Out[11]= 6.25 μ 10 - 7 In[12]:= Iyy = H 1 ê 12 L * t * h^3 + h * t * xc1^2 + h * t * xc2^2 Out[12]= 3.4375 μ 10 - 7 Lecture8_problem.nb 1
Background image of page 19

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
In[13]:= Ixy = h * t * xc1 * yc1 + h * t * xc2 * yc2 Out[13]= - 1.875 μ 10 - 7 Calculation of the normal stress distribution In[14]:= sigmaz = - H Mx * Ixy ê H Ixx * Iyy - Ixy^2 LL * x + H Mx * Iyy ê H Ixx * Iyy - Ixy^2 LL * y Out[14]=
Background image of page 20
Image of page 21
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 03/10/2009 for the course MAE 157 taught by Professor Valdevit during the Winter '08 term at UC Irvine.

Page1 / 22

Comprehensive+beam+problem - Lecture8_problem.nb...

This preview shows document pages 1 - 21. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online