Example_on_Seismic_including_Torsion - Example For the...

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5m 5m 5m 5m 5m 2.0m 0.25 0.2 0.2 0.25 1.0m 1.0m 2m 5m 5m 1 2 3 A B C D E F hs=180mm All columns (400*400)mm Example: For the shown plan: it’s required to get the lateral forces due to seismic loads according to NBCC 2005 requirements. Given: floor cover=1.5KPa, partitions=1 KPa, L.L=1.9KPa Storey height (h) =3.0m, No. of stories (n) = 8, γ c = 24KN/m 3 Snow load = 2 kPa , the building is located in Montréal. The soil class is ( C), ductile shear walls are constructed. Solution: ( ) a v E d o S T M I V W R R = a) Estimation of W : W=dead load +25% of snow loads =(0.18×24+1.0+1.5) ×(10×25) ×8 + 18×0.4×0.4×3×8×24 column weight +2×(0.25×2+0.2×1) ×3×8×24 +0.25×2×(25×10) Shear walls =16287.9KN b) Fundamental period ( Ta ): Cl . 3/4 3/ 4 0.05( ) 0.05(24) 0.542sec n Ta h = = = For Montreal: from Table (C-2) Appendix C Sa (0.2) =0.69, Sa (0.5) =0.34 Sa (1.0) =0.14 Sa (2.0) =0.048
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For soil class (C) : from Table (B&C) Fa=1, Fv=1 To get Mv : Table (0.2) 0.69 14.38 8 (2.0) 0.048 Sa Sa = = > Æ Mv =1.0 To get J : from linear interpolation J=0.9832 . To get R o ,R d : Table R d =3.5, Ro=1.6 (for ductile shear walls).
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  • Winter '07
  • DrGala
  • Torsion, Trigraph, shear wall, Karnataka

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