This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Math 23 Sections 110-113 B. Dodson Week 3 Homework: 12.5 Lines, Planes 12.6 Quadratic Surfaces 12.7 Cylindrical and Spherical Coords Problem 12.5.3: Give vector and (scalar) parametric equations for the line through the point (-2,4,10) parallel to the vector < 3 , 1 , 8 > . Solution: The vector equation OP = OP + td, for when the position vector of the point P ( x, y, z ) puts P on the line through P ( x , y , z ) with direction vector d = < a, b, c > gives < x, y, z > = < x , y , z > + t < a, b, c > = <- 2 , 4 , 10 > + t < 3 , 1 , 8 >, which we can view as a “point-slope” equation, where P is the point, and d gives the direction of the line. (Here in the position vector OP, O = O (0 , , 0) is the Origin.) To get the scalar equations, we use scalar mult. and vector add to write the vector equation 2 . as < x, y, z > = <- 2 + 3 t, 4 + t, 10 + 8 t >, and simply read-off x =- 2 + 3 t, y = 4 + t, z = 10 + 8 t....
View Full Document