PHYSICS
ws10a

# ws10a - Worksheet 10a Center of Mass Collisions I Questions...

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Worksheet 10a: Center of Mass & Collisions I Questions 1. The center of mass of the diver will follow a simple parabolic arc. Since any twisting and turning is the result of an internal force in the diver, there is no change in the motion of the center of mass. 2. Bob wins, assuming the line between Bob and Jim is halfway between them. The reason being that since Bob is heavier, the center of mass is on his side of the line. Since no internal force between Bob and Jim can change the center of mass, when Bob and Jim draw closer to each other, they will approach the center of mass, and at some point Jim will cross the line. 3. The maximum possible displacement is 5 m . The way to get this is by putting all the bricks in the far left side of the car. Since the center of mass of the bricks will not change, the actual position of the car will change to compensate. 4. Nothing should happen to the center of mass of the snowball because all forces in-

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Unformatted text preview: volved in the explosion are internal to the snowball. 5. Two objects of equal mass are on a frictionless track. (a) The velocity of the center of mass is equal to v 2 . (b) The velocity of the center of mass is less than v 2 . Consider the limiting case of a ping-pong ball Fying towards a bowling ball; obviously in this case, the center of mass velocity is going to be very small. Problems 1. ±inding the center of mass: (a) Taking the center of the total square to be (0 , 0): x cm =-. 05 m and y cm =-. 14 m (b) Taking the center to be the center of the central square: x cm = 0 and y cm =-. 36 cm . 1 2. The center of mass is vx cm = + r 3 R 2-r 2 ˆ y 3. A man kicks a rock: V man =-m M V rock = . 07 m/s 4. A hockey puck explodes: V f =-V ˆ x + 4 V ˆ y 5. Two cars collide: vV c = (15 . 3 kph )ˆ x + (5 kph )ˆ y . In other words: V c = 16 kph and θ c = 18 . 2 o . 2...
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• Spring '08
• Lanzara

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