28.1.Solve:The wire’s cross-sectional area is Ar==×()=×−−ππ23261 0103 141510..m m2, and the electroncurrent through this wire is 20 10191.×−s. Using Table 28.1 for the electron density of iron and Equation 28.3, the
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 03/14/2009 for the course PHY PHYA22 taught by Professor Abbas during the Spring '09 term at University of Toronto.