EOC_Solution_28_01 - current through this wire is 2.0 1019...

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28.1. Solve: The wire’s cross-sectional area is A r = = × ( ) = × π π 2 3 2 6 1 0 10 3 1415 10 . . m m 2 , and the electron current through this wire is 2 0 10 19 1 . × s . Using Table 28.1 for the electron density of iron and Equation 28.3, the drift velocity is
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