EOC_Solution_28_01 - current through this wire is 2.0 1019...

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28.1. Solve: The wire’s cross-sectional area is Ar == × () −− ππ 23 2 6 1 0 10 3 1415 10 .. m m 2 , and the electron current through this wire is 20 10 19 1 . × s . Using Table 28.1 for the electron density of iron and Equation 28.3, the
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This note was uploaded on 03/14/2009 for the course PHY PHYA22 taught by Professor Abbas during the Spring '09 term at University of Toronto.

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