EOC_Solution_28_06 - 28.6. Solve: For L = 1.0 cm = 1.0 10 2...

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28.6. Solve: For L == × 10 2 . cm 1.0 10 m , the surface area of the wire is A = (2 π r ) L = DL (1.0 × 10 3 m)(1.0 × 10 2 m) = (1.0 × 10 5 m 2 ) The surface charge density of the wire is
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