28.28. Visualize:Solve:The current density through the cube is J =σE, and the actual current is I =AJ. Combining these equations,the conductivity is==()×=×−−IAE9.0 Am N/Cm2105 01018 1043711..ΩIf allquantities entering the calculation are in SI units then the result for
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This note was uploaded on 03/14/2009 for the course PHY PHYA22 taught by Professor Abbas during the Spring '09 term at University of Toronto- Toronto.