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28.28. Visualize:
Solve:
The current density through the cube is
J
=
σ
E
, and the actual current is
I
=
AJ
. Combining these equations,
the conductivity is
==
()
×
=×
−−
I
AE
9.0 A
m
N
/
C
m
2
10
5 0
10
18 10
43
71
1
.
.
Ω
If
all
quantities entering the calculation are in SI units then the result for
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This note was uploaded on 03/14/2009 for the course PHY PHYA22 taught by Professor Abbas during the Spring '09 term at University of Toronto Toronto.
 Spring '09
 Abbas
 Physics, Conductivity, Current

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