EOC_Solution_28_31 - 28.31 Solve(a Let the new current be I...

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28.31. Solve: (a) Let the new current be I such that I = 2 I where I is the original current. The current density is JI A = . Since the area of cross section of the wire remains the same, we have A I J I J == ′ = = J I I JJ 2 That is, doubling the current doubles the current density. (b) Conduction-electron density is a material’s characteristic value, and does not depend on external factors. Thus n = n . (c)
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This note was uploaded on 03/14/2009 for the course PHY PHYA22 taught by Professor Abbas during the Spring '09 term at University of Toronto.

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