April 21 - 2 = 5.2 arrests =.5.39 = 1.28 = t calculated S 2...

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April 21, 2008 Significance testing for two population means (independent sample means) Example 1 = male 2 = female table E3 -> t critical = +/- 2.000 1 = 5.7 arrests t obtained (calc) = ( 1 - 2 )/ ( (s 1 2 / n 1 -1) + (s 2 2 / n 2 -1)) s 1 2 = 2.5 variance = (5.7 – 5.2) / ( (2.5 / 30 - 1) + (2.0 / 30 – 1)) n1 = 30 = .5 / (.08 +.07)
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Unformatted text preview: 2 = 5.2 arrests = .5/.39 = 1.28 = t calculated S 2 2 = 2.0 (variance) FAIL TO REJECT NULL HYPOTHESIS n2 = 30 α=.05 two tailed H = μ1=μ2 H 1 = μ1 ≠ μ2 Df = n1 + n2 – 2 = 30+30-2=58 1 Tailed H = μ1=μ2 H 1 = μ1>μ2 T critical = +1.671 T calc = 1.28 STILL FAIL TO REJECT...
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  • Spring '09
  • Kupchick
  • Null hypothesis, Statistical hypothesis testing, Statistical power, Ronald Fisher, reject null hypothesis, female table E3
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