Rec_9_key - _L/13MPAD fa 1&ch W 21 21 May —Zw7 é...

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Unformatted text preview: ,; _L/13MPAD fa. 1&ch W 21/ 21- May —Zw7 é flung» " FM: 7M! wwssmv 49mm: Seed 4 $9!” ____—__. ‘EFf 4 —2 ~— V4= {5 ,- v,,= 2w - 5250le 32A,: M, +(z»<~)(o.«m\- mm -= {A M)“. 3ZN’“ '3 ZZIO H'TUO “r. Zéfisoih b 5‘ WM!“ t' [600 1 <%,§50ik— ”9) Yum: 6am ’ F“ I.» FWD GONCA'E/Istow 0/11 WMIQD £1064 Sharr- \\ 29¢“ 6} {we 2/; 26 may» 2507 P2060211 Z. fill”) “17’! L' idr “A WScVE Suzi-fax. —' -—. FHfls?’ F/Nb / _ __ EEK/l" ’ )’ : 5.4a Tm use Waik) «90‘s {laud-‘4» FM 1;. (1 IX. : 'g-c' 1' 01/; I46 {_L_. A IMP/1 D 52L {#4 cu 49mm) «276:4 SW {gnmmn fecJ 67062 Z” 26 —W— 24w 4' , Fawn Z. '71.. [4412‘ Ex «w 7/6 (4610' is- an) 77:13 V813! 0F $031052. an 7:01;!) W 4/1/6245— (X- FED WW“ f a,» : X1 (74) TH Zlé-If'fa 77% #56649 W malt ZF‘XI = “T + 5:): 301mb —[email protected] 30°(200fl) :g)’ 50 7": No" 48-5 " 57.5%: wh’db I5 *‘R E _Wuas 7' cumzw 0”“ Z1530 -— 57.5 IL. * 55W (’wn‘Q’J‘M“ “00”) 19¢ 50/ ammo») + amps») 1 57.319- 514}? ms fig/ gm“ ijfm m 30°Wroum {éw- 3 /G§o m1: 32 63 92-6 51.54. ‘ZD' \ 2:" (306456 _ Zn _. ‘2 67062 2// u — w w 2997 PM. a! k 5 , M» {4m 75% ' ugh: 3: M [54 741? pwr 4‘30““ ' L 19*" 3'» 4:3 73 I W.» m-fl (I 7‘7 —- o Imam; 1 (/i625 m) _. H {M6 ‘ /7..3w W360 {L5 2411’” all t ax 'lzu‘m 50 .. 048 I 6‘ 256:0 LQX-IMP/ID ‘1 Earn. ‘i Q'mz 2/2 24 Jaw 2:07 Pm 5' "fit: M955 op 77!:- auom: 2‘: %/m. 1'; 41mm“: 95. -- 3m Fm: "7.1%W Cm” .442 147% :F 64131,! 443 _ ' J. 11.4: ab Zégfiaig‘): Midi»? , = 06 " . zi.4m-' A” in,“ Q 0' 67... / 5° 75" macaw: 300° 7- - 600910) 003‘ (2'0“?) 30 ‘ goéOU m ' ~.__,_..._ kgwfl- 30.2...“ ? $9 ,éogfl, 01L fl‘Dtg/h 5-. w WM aw; s’flzzJ-r Fog Wm;vmw 0P do é ENGR 21 1 Recitation 9 1 1!26I2007 Problem 1. Bridge Beam Size Moment ymaxil of Inertia in” in'” M = 2210 ft-lb 26520 in-lb Siressalm 1900 psi | Ymax” l0.071644| in” l 98 9 0 04675 Column value must be smaller than calculated, so Choose: 2 x 10 Ai ybari ybanAi dy lo inch inch2 inch inch3 inch inch‘ m 4.00 ————————-a _——a_—__—-m _—smm_ Ycanmu = 4.0 inches Problem 5. Power line analysis Catenary Equation For x: 30 m let's plot y vs. a y vs. a for x=30 m “- 0.0001 0.045 0.0067 3.025164 4.533851 01 90.57662 _ 0.450034 _ .m- 0.002 0.004 0.005 0.01 a, m" ...
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