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# Lecture 03 - Lecture 3 Probability Independent Assortment...

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Lecture 3 Probability Independent Assortment Polygenic Inheritance Cytoplasmic Inheritance

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Probability # of times outcome is expected/ # of opportunities Given as a fraction, percentage, or proportion of 1 Product Rule: The probability that two independent events both occurring is the product of each event occurring separately. Using a fair die, the chance of rolling a 1 is 1/6, 16.7%, or .167 Using a pair of fair dice, the chance of rolling two 1s is 1/6 X 1/6 = 1/36 or 0.027 Sum Rule: The probability that either of two mutually exclusive events will occur is the sum of the probability of each event. Using a fair die, the chance of rolling either a 1 or a 2 1/6 + 1/6 = 1/3 or 0.333 and or
A/A A/a A/A a/a A/a ? ? A/A What is the probability that the second child (III) is heterozygous If the first child (III) is using Rogaine? I II III II-2 is either AA (1/2) or Aa (1/2) If II-2 is AA, then p(of III-2 being Aa) = 1/2 [ AA, Aa] If II-2 is Aa, then p(of III-2 being Aa) = 2/3 [ AA, Aa, aA] The p(of III-2 being Aa) is the sum of each probability = {AA (1/2) X 1/2 [ AA, Aa]} + { Aa (1/2) X 2/3 [ AA, Aa, aA]} = ¼ + 1/3= 7/12 p(of both father AA and child Aa) + p(of both father Aa and child Aa)

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Independent Assortment of Two or More Traits

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Figure 3-3 step4

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Figure 3-3 step 5

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Figure 3-3 step 5
χ 2 (chi-square) Test χ 2 = Σ

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Lecture 03 - Lecture 3 Probability Independent Assortment...

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