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Unformatted text preview: when ±u = [1 , 2 , 3] . Solution: For ±v we have  ±v  = √ ±v ◦ ±v, so for ±v = [ v 1 , v 2 , v 3 ] ,  ±v  = p v 2 1 + v 2 1 + v 2 1 . so  ±u  = √ ±u ◦ ±u = √ 1 + 4 + 9 = √ 14 . Then the unit vector in the direction of ±u is 1 √ 14 [1 , 2 , 3] = [ 1 √ 14 , 2 √ 14 , 3 √ 14 ] . continued from week 1: 5. linear combinations, standard coordinates and new coordinates. We also covered 1.1  #11, 20, pg. 14 6. dot product, right angles and orthogonal vectors. We also started Section 1.2 and covered 1.2  #1....
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 Spring '08
 Dodson
 Math, Linear Algebra, Dot Product, Mon, regularly scheduled class

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