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Unformatted text preview: If A and B are the points A = (1 ,1) , B = (4 , 2) draw the vector→ AB then compute and redraw→ AB as a vector in standard position. Solution:→ AB =→ OB→ OA, where O = (0 , 0) is the origin. Sketch! (continued . . . ) 4→ AB =→ OB→ OA = [4 , 2][1 ,1] = [41 , 2(1)] = [3 , 3] . (Sketch of→ AB =→ OC for C = (3 , 3) . ) 5. linear combinations, standard cordinates and new coordinates. We also covered 1.1  #11, 20, pg. 14 6. dot product, right angles and orthogonal vectors. We also started Section 1.2 and covered 1.2  #1....
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This note was uploaded on 02/29/2008 for the course MATH 43 taught by Professor Dodson during the Spring '08 term at Lehigh University .
 Spring '08
 Dodson
 Linear Algebra, Algebra

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