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Unformatted text preview: * 2 1=(1.1) mod 2= 1 mod 2=1 The addition and the multiplication table ±or the + 2 , * 2 , respectively, are as ±ollows: + 2  0 1 * 2  0 1 0 1  0 1  1 1  0 1 (a) Give the tables ±or + 5 and * 5 + 5  0 1 2 3 4 * 5  0 1 2 3 4 0 1 2 3 4 0  0 1  1 2 3 4 1  0 1 2 3 4 2  2 3 4 1 2  0 2 4 1 3 3  3 4 1 2 3  0 3 1 4 2 4  4 1 2 3 4  0 4 3 2 1 (b) Give the following sum and product in base 5: 423 5 214 5 +240 5 * 334 5 ——— ———1213 5 1421 – 1202x – 1202x – —————– 134141 (c) Based on the above tables for + 5 and * 5 , solve the following equations for x in Z (5). 2 + 5 x = 1 + 5 3 + 5 3 x = 4 2 * 5 x = 3 * 5 3 * 5 3 x = 4 4. Make the following conversions between bases: (a) 743 A 11 = x 14 3832 14 (b) 11001100011010100 2 = x 8 314324 8...
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This note was uploaded on 04/28/2008 for the course CSE 260 taught by Professor Saktipramanik during the Fall '08 term at Michigan State University.
 Fall '08
 SaktiPramanik

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