This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: down the plane. a s = ±g Sin q Example of forumula: A skier’s speed at the bottom of a 100 m slope is 20 m/s. What is the angle of the slope? v 2s 2 = v 1s 2 +2 a s Dx = 2 g Sin q Dx, so Sin q = v 2s 2 /(2 g Dx) = (20 m/s) 2 /[2(9.80 m/s 2 )(100 m)] = 0.204 q = Sin1 (0.204) = 11.8 O VECTORS Forces A= F/m The force is directly proportional while the mass is inversely proportional M is always positive. W=mg Where W is weight, m is mass and g is gravitational force of 9.8m/s 2...
View
Full
Document
This note was uploaded on 04/28/2008 for the course PHY 132 taught by Professor Rijssenbeek during the Spring '04 term at SUNY Stony Brook.
 Spring '04
 Rijssenbeek
 Acceleration

Click to edit the document details