# hw1 - Gu, Phillip Homework 1 Due: Sep 12 2007, 11:00 pm...

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Gu, Phillip – Homework 1 – Due: Sep 12 2007, 11:00 pm – Inst: Brodbelt 1 This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. Brodbelt CH301 Due Sept. 12, 2007, 11:00 pm 001 (part 1 oF 1) 10 points What is the symbol For the element copper? 1. Cp 2. Cr 3. Cu correct 4. Co Explanation: The symbol For copper is Cu. 002 (part 1 oF 1) 10 points A Factor oF 1 . 0 × 10 - 9 corresponds to the prefx 1. milli. 2. micro. 3. pico. 4. nano. correct Explanation: Nano reFers to 1 . 0 × 10 - 9 . 003 (part 1 oF 1) 10 points Express 0.0103240 in scientifc notation. 1. 1 . 03240 × 10 - 2 correct 2. 1 . 03240 × 10 2 3. 1 . 0324 × 10 - 3 4. 1 . 0324 × 10 - 2 5. 1 . 0324 × 10 - 1 6. 1 . 03240 × 10 - 3 Explanation: The number is a Fraction smaller than one, so the exponent is negative. The decimal must be moved 2 places, so the exponent on 10 must be - 2. 004 (part 1 oF 1) 10 points What is the proper solution to the Following equation? (150 + 2 . 5 + 36 . 75) ÷ (6 . 60 + 0 . 173) = 1. 30 2. 27.94183 3. 27.942 4. 27.9 5. 27.9418 6. 28 correct 7. 27.94 Explanation: The last position retained For the frst addi- tion problem will be the tens position giving it 2 sigfgs. The last position retained For the second addition problem will be the hun- dredths position giving it 3 sigfgs. ThereFore the fnal answer 27.94 needs to be rounded to 2 sigfgs: 28. 005 (part 1 oF 1) 10 points How many kg are in 10.0 mg? 1. 1 . 00 × 10 - 3 kg 2. 1 . 00 × 10 - 4 kg 3. 1 . 00 × 10 - 7 kg 4. 1 . 00 × 10 - 5 kg correct 5. 1 . 00 × 10 - 6 kg Explanation:

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Gu, Phillip – Homework 1 – Due: Sep 12 2007, 11:00 pm – Inst: Brodbelt 2 ? kg = 10 . 0 mg × 1 g 1000 mg × 1 kg 1000 g = 1 × 10 - 5 kg 006 (part 1 of 1) 10 points How many cubic inches (in 3 ) are in a 55.1 liter aquarium? 1. 162 in 3 2. 129 in 3 3. 3360 in 3 correct 4. 18,700 in 3 5. 23.3 in 3 Explanation: ? in 3 = 55 . 1 L × 1000 mL 1 L × 1 cm 3 1 mL × µ 1 in 2 . 54 cm 3 = 3360 in 3 007 (part 1 of 1) 10 points Calculate the density of methanol (CH 3 OH) if you know that there are 4.2 moles of methanol in 5.67L. 1.
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## This note was uploaded on 03/19/2009 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas at Austin.

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hw1 - Gu, Phillip Homework 1 Due: Sep 12 2007, 11:00 pm...

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