ans_key_exam 3 - + HA [A-]eq = (36.22*0.333)/(100+36.22) =...

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File: C:\Documents and Settings\Roy Lacey\Desktop\Chem\Data\Che132_Fall2004\Prac cticeExam\3rdExam\ans_key.txt 11/16/2004, 11:27:35 AM 1. a 2. a 3. b 4. b 5. e 6. a 7. a 8. c 9. d 10. c 11. a 12. e 13. d 14. c 15. na 16. na 17. Mno4- + 5Fe2+ + 8H+ -> Mn2+ + 5Fe3+ 4H2O 18. anode Mg -> Mg2+ + 2e cathode Sn2+ + 2e -> Sn E=(-0.14V)-(-2.36)=2.22V 19. A- + H20 <-> OH-(x)
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Unformatted text preview: + HA [A-]eq = (36.22*0.333)/(100+36.22) = 0.089 M x*x/0.089 = kb = kw/ka x = 1.7 * 10(-6) pOH = 5.7 pH = 8.3 20. pH = pka + log[A-]/[HA] [A-]/[HA] = 1.78 [A-] = 1.78 M n(CH3COONa) = 1.78 mol m = 1.78 * 82 = 145.96 g 21. Pb (left) + Pb2+ (right) -&gt; Pb2+ (left) + Pb (right) E = ERTln([Pb2+](left)/[Pb2+](right))/(nF) [Pb2+](left) = 0.002 M Page: 1...
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