quiz3[1] - PHYSICS 2D PROF HIRSCH QUIZ 3 WINTER QUARTER...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
PHYSICS 2D QUIZ 3 WINTER QUARTER 2009 PROF. HIRSCH FEBRUARY 6, 2009 Formulas: Time dilation; Length contraction: Δ t = γ Δ t ' γ Δ t p ; L = L p / γ ; c = 3 × 10 8 m / s 1 Lorentz transformation: x ' = γ ( x vt ) ; y '= y ; z '= z ; t ' = γ ( t vx / c 2 ) ; inverse : v - v Spacetime interval: ( Δ s ) 2 = ( c Δ t ) 2 -[ Δ x 2 + Δ y 2 + Δ z 2 ] Velocity transformation: u x ' = u x v 1 u x v / c 2 ; u y ' = u y γ (1 u x v / c 2 ) ; inverse : v - v Relativistic Doppler shift : f obs = f source 1 + v / c / 1 v / c (approaching) Momentum, energy (total, kinetic, rest) : p = γ m u ; E = γ mc 2 ; K = ( γ 1) mc 2 ; E 0 = mc 2 ; E = p 2 c 2 + m 2 c 4 Electron : m e = 0.511 MeV / c 2 Proton : m p = 938.26 MeV / c 2 Neutron : m n = 939.55 MeV / c 2 Atomic mass unit : 1 u = 931.5 MeV / c 2 ; electron volt : 1eV =1.6 × 10 -19 J Stefan's law : e tot = σ T 4 , e tot = power/unit area ; σ = 5.67 × 10 8 W / m 2 K 4 e tot = cU /4 , U = energy density = u ( λ , T ) d λ 0 ; Wien's law : λ m T = hc 4.96 k B Planck : E n = nhf ; probability P ( E n ) e E n / k B T ; E ( λ , T ) = E n n P ( E n )/ P ( E n ) n Planck's law : u ( λ , T ) = N ( λ ) × E ( λ , T ) = 8 π λ 4 × hc / λ e hc / λ k B T 1
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern