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Unformatted text preview: ME163 Mechanical Vibrations (Winter 2009) HW3 Due 1.29.09 in class25% if late within 24 hours50% if later than that 1. This problem aims to give you a flavor into the process of designing cars for an adventurous roller coaster ride. We can model the car as a single degree of freedom system subjected to a forcing function (this is due to the design of the roller coaster rails). As an example assuming that the governing equation is as follows Figure 1: Roller coaster design x + 9 x + 36 x = 54cos 3 t (a) Find the steady state response (otherwise known as the asymptotic or the particular solution) of the coaster car analytically i.e x ( t ). (b) While designing such rides, one of the important parameters is the rate of acceleration i.e a = ... x the person is subjected to. This rate is called jerk . Find the steady state jerk and compute its phase with respect to the force. (a) Take x = Asin (3 t ) + Bcos (3 t ) substituting in the differential equation given ( 9 A + 27 B + 36 A ) cos (3 t ) + ( 9 B 27 A + 36 B ) sin (3 t ) = 54( cos (3 t )) or ( 9 A + 27 B + 36 A ) cos (3 t ) = 54 cos (3 t ) ( 9 B 27 A + 36 B ) sin (3 t ) = 0 Hence A = 1 and B = 1,Thus x = ( cos (3 t ) + sin (3 t )) Expressing it as Asin ( t + ), we get x = 2 sin (3 t + / 4) (b) Calculate the jerk by differenciating x three times x = 3 2 cos (3 t + / 4) x = 9 2 sin (3 t + / 4) ... x = 27 2 cos (3 t + / 4) ME163 Mechanical Vibrations 1 HW3 Now cos (  ) = cos ( ) and cos ( ) = cos ( ) or ... x = 27 2 cos (3 t 3 / 4) Thus Jerk LAGS the force by 3 / 4 2. Consider a disk of mass m and radius r connected to a linear spring and to an arrangement of three dashpots (shown in Figure 2). The stiffness of the spring is k , its unstretched length is L and the damping coefficient of each damper is C . Further assume that the disk rolls without slipping i.e the relative velocity of the contact point P of the disk with respect to the ground is always zero....
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 Winter '08
 Mezic,I

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