{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

q9 - PHYSICS 2B(a QUIZ 9 SPRING QUARTER 2001 PROF SCHULLER...

Info iconThis preview shows pages 1–11. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 10
Background image of page 11
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PHYSICS 2B(a) QUIZ 9 SPRING QUARTER 2001 PROF. SCHULLER JUNE 1, 2001 USEFUL FORMULAS: a 1 A _ Coulomb' 3 Law F = Q1212 r For a capacxtor 471780 r CV = 8Q Gauss’ 8 Law éE-d (i=8 —J p dV C: d A(Parallel Plate) P_. — . , Definition of Potential V: JE- dl U = 1 l qqu Electrostatic Energ)l 47180 2 ”q rij 80:8.9X10711 C7 Rsz R=m Nm* A qB E: W V = R1 RC Circuits , Charging , D15Chdf§lllg_ W F = qv X B F = iL x B rzyxB a — « _ , ,uoi ~ 0 .dlx? :fiB-dl zpdlds Ampereslaw B(r)=— dB=—— 1 g x 2m 47r r = jB - (IA 8 = N d¢B dt 1. A rectangular loop of wire of dimensions 1 and (d-2a) lies in the plane of two very long. parallel wires, which comprise part of a circuit (see figure below). Calculate the mutual inductance between the loops. PHYSICS 2B(a) QUIZ 9 SPRING QUARTER 2001 PROF. SCHULLER JUNE 1, 2001 2. In the circuit shown in the figure below, 8 = 10 V, R1 = 5.0 9, R2 = 10 Q, and L = 5.0 H. For the two separate conditions (I) switch S just closed and (II) switch S closed for a long time, calculate (a) the current il through R1, (b) the current i2 through R2, (0) the current 1' through the switch, ((1) the potential difference across R2, (6) the potential difference across L, and (f) the rate of change diz/dt. 3. In the figure below, a conducting rod of mass m and length L slides without friction on two long horizontal rails. A uniform magnetic field B fills the region in which the rod is free to move. The generator G supplies a constant current i directed as shown. (a) Find the velocity of the rod as a function of time, assuming it to be at rest at t = 0. The generator is now replaced by a battery that supplies a constant emf 8. (b) Show that the velocity of the rod now approaches a constant terminal value V and give its magnitude and direction. (c) What is the current in the rod when this terminal velocity is reached? (d) Analyze this situation and that with the generator from the point of View of energy transfers. 4. (BONUS) The Germans, English and French contributed greatly to the development of electricity and magnetism. Name for two of these nationalities: (a) a famous physicist (b) a good dish 6’) genus ‘ NVIHuO“ QuylL‘nhi" here nse‘cs \[av SP+5 /C0‘ll/1 3S “ne 2 lomfi wires. Beg‘m by fawn“ <15“ 4 ab“ :. 840M 2 4x 3 : Moi J40 i +o+0~| ‘* g“ T ZWCQ‘HA ZWCJ-q-X) (15m) (we we mm m m l necesury +0 Khaw 4kg) «~1ch : Mobe [I —+ ‘ LU 1w aux 44px 0Q) V1 : E} °~+ +20 (no curreu4 fiowg +L\¢0U%\A "Hae Coll) E] oclr *iOQ (no vOH‘U39 Okra? across "er C0;‘B Q) VLII «Jr +10 (no :1 So “0 V1) : [0:] ah} 420$ (CM‘ «0+5 “K6 & W‘H‘GB . \OV , ' ereu" 35M if : —‘£:— : SH : IZA/g! 0;“ 4:0 (‘ O °~+ +;oo~: S+euly Shh-1) £3 0k> root EXPErltemCéS ‘H'm HMS (me +0 +ke IeH (we): F: ma: ‘IIQB a: 1118 M V: VD+Q+3 0+ (£B+ (‘OP1L>) 19) AS ’Hne fiemem‘lor fusked 4ke Pool +0 ’Haé ‘60.” \ LEI/\Z Law CVeog¥eol OM Coum+er EL awouvwk ”HA6 loop: ’._0\ a- 13;: L ‘ iédmxy —BM* =~BLV Tbs ELKncremsgol wHL‘ 4‘\w\e laecquSe v ol‘wl (V:V(4\) N we sUAAele refine we Semevdor wHk a luad+ery 4m mfoses M 2 WW; 4m no? €._ will only Conwe 40 page aux—‘1‘ H exuds E '. a 4m Pom E Lance‘s EL ) CUTT€M+ LHL‘+S ) «no! ‘Ha‘e ‘tixg «Force 0“\$o\f{)e°«f3) ‘eqv‘w‘os “HA9 roe-x wx‘Ho‘ 0; cons-‘AA‘L Ve\oc|\4\/ ’Haerek'C‘\~er Lemxuse I‘Q‘B+ ' CLW _. _ . : -_- i : - ©¢®~a tom :— PHYSICS 2B(b) QUIZ 9 SPRING QUARTER 2001 PROF. SCHULLER JUNE 1, 2001 USEFUL Fg IRMIJLAS: a 1 A . Coulomb's Law F = (11:12 r For a capac1tor 47:80 r CV=Q , ~ ~ 1 80A Gauss 5 Law §E - dA = —— f p dV c = —d— (Parallel Plate) S 80 V . . . . P ~ -’ 1 1 qiq j . Deflnltlon of Potentlal V :1 E ~ d1 U —— —— Electrostatlc Energy °° 471's0 2 ”.1- r1] 2 e(,=23.9><10—12 C, R=p£ R 3‘1 Nm A qB RC Circuits Charging Discharging F = qv X B (e/R)e“"RC) - (Q0 /RC)e(“/RC) r = [J x B §Edl=pOII~d§ Ampere'slaw B(r)=& dlfl3=fl°—idl:<r s 2m 47: r 61¢ = BdA ts=N——B «a. I dt 1. A metal rod is forced to move with constant velocity V along two parallel metal rails, connected with a strip of metal at one end, as shown in the figure below. A magnetic field B = 0.350 T points out of the page. (a) If the rails are separated by 25.0 cm and the speed of the rod is 55.0 cm/s, what emf is generated? (b) If the rod has a resistance of 18.0 (2 and the rails and connector have negligible resistance, what is the current in the rod? (c) At what rate is energy being transferred to thermal energy? 2. In the figure below, 8 = 100 V, R1 = 10.0 9., R2 = 20.0 Q, R3 = 30.0 (2 and L = 2.00 H. Find the values of i1 and i2 (a) immediately after the closing of the switch S, (b) a long time later, (c) immediately after the reopening of switch S, and (d) a long time after the reopening. PHYSICS 2B (b) QUIZ 9 SPRING QUARTER 2001 PROF. SCHULLER JUNE 1, 2001 3. A large, closely packed coil of N2 turns completely surrounds a very long, ideal solenoid of length l, radius a, and N, turns, as in the figure below. Calculate the mutual inductance M between the coils. 4. (BONUS) The Germans, English and French contributed greatly to the development of electricity and magnetism. Name for two of these nationalities: (a) a famous physicist (b) a good dish Q7 : 0.357— L= <2.st v2 O‘SSM/S R= |3_rL g .5 if: M Lx ELI; m V = (osSXOJSXoss) “ _€__ 0,04%! _‘ -3 I (a) ‘- R T“ 2.Q7xtoA (SP—M.) .1 'Z “4 C) P: ‘K= (2.cqx(ds)(\%3= (S Ids) [I f“ K3 2 -. (00V 5/ K‘1 (0.09. K1 L RZ=2<DJL K3= 3040. L : 2,00H sz. +:GQ ‘ ‘J 17%.: ”M V3 («Ikey‘re \HA Pk¢k“€ ‘3 : V55 $0 FHA 'H’W‘ “CNS—E ‘mS‘hn'k 4““? 60:1 L Mkhx'hflms ‘Hae Currem+ ‘13 ‘Hurougk ‘I+Se\'€ 4Ld Ft (AKA Ju$+ lee-Core S was Opened, TLxIS l3 now courses ‘Harouglq R1 i$ We” 1 \ l("Z 3 4.€Sr— 2.113 : (LYZAZ _ ' 3 ((3-5 W 9+3 (0Q\‘5 g 943 @ Here ‘l‘l wakes MO$+ Seuss +0 comp/"H: MI'L ra-Hmr .H‘M‘ M,“ Because (“bu retvh-es B wLicL is easy 40 (“ml I $0L€thh (tn : 81A. “3 BlAl because 8?. I O Ou+S‘ul€ ‘er Qolevxo‘ui :flo‘H/‘A’l - N ‘Mol— ,Q Q Ml‘L: NG (blz : NZNM°\Q l® \ : MONZNQ @ WV‘\‘+;K3 Qfly‘kL‘IMi Mere 056+S You SP+S Amfi€\3 Owwl vvxlm‘ts'kevg o‘c firuce Aefluol US l .. (HAm\e+ Ac." I sceueE> ...
View Full Document

{[ snackBarMessage ]}