Midterm1 sol(exam1) - WHITE Chem 102(2009 MT—I—A M...

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Unformatted text preview: WHITE Chem 102 (2009) MT—I—A M. Klobukowski 2 1. (9 marks) For a reaction in which A and B react to form C: 2A+B —> C the following data were obtained: W3. RM?“ 5.33“ Chem 102 (2009) MT—I—A M. Klobukowski 2. (7 marks) In the study of kinetics of a first-order reaction for the decomposition of A to form products, A —-> Products, the following data were obtained: [A] (M) 1.00 0.80 0.60 0.35 0.15 Time(s) 0 110 255 525 950 (A) (2 marks) What must you graph in order to ShOW that this reaction follows first—order kinetics? Place correct labels on the axes below and draw suitable line (qualitatively!) MA] J9/5 (B) (2 marks itable plot is made using the above data and a straight line with slope of valuQP/EES obtained, what is the value (and units) of the rate constant k for this reaction. ., 3, .. l "‘ k :1 —- Q . 0 7k ‘ O 5 fl :5 9.0 342045” (C) (3 marks) What is the half—life of this reaction when [A] = 0.60 M? Fm {70¢ «9ng t r. cm m it, , 1C n MM my iflfii’pfiimti {TM .4610. mwAAI-zllm 3443;“ “Lt :: (9'qu ; WO'VQBW A a mama”: 7: 34"] 5 Chem 102 (2009) MT-I-A M. Klobukowski 4 3. (13 marks) The thermal decomposition of nitryl chloride, NOZCI, 2 N02C1(g) —> 2 N02(g) + C12(g) may have the following mechanism: (1) NOZCI —"‘-9 N02+ C1 (slow step) (2) N02C1+ C1 #9 N02 + Cl2 (fast step) (A) (1 mark) Which steps are bimolecular? 6’0; p (2) (B) (2 marks) Is this an acceptable mechanism? Ex lain WW (C) (2 marks) What rate law 18 predicted by this mechanism? (D) (6 marks) Sketch energy profile for this reaction assuming that the first step is bnzdothermic, the second step isexothermic, and the entire reaction ismfliothermic. On the graph, label the axes, and mark clearly transition states (T81 and T82) and intermediates (I). M% K W,wmm,,mmmwm,fim”WWWMMM2W> Q! PL, W3 (E) (2 marks) Sketch the structure of the activated complexes at both transition states. 0\ o O O / . / TS . N TS : \ 9 1 - \ t L 0? QWW “W fl‘w‘watmfiacflfim W Chem 102 (2009) MT—I—A M. Klobukowski 5 4. (7 marks) Rate constants for the first-order reaction N205(g) —> 2 N02(g) + 1/2 02(g) were determined at a series of temperatures. The data are given below: T(°K) 298 308 318 328 _ 338 k(s‘1) 3.46x10’5 13.5x10‘5 49.8x10-5 150x10'° 487x105 (A) (2 marks) What would you graph to determine the activation_g for this reaction? Place correct labels on the axes below and draw suitable line qualitativel I . ijk l K "' 3 /TC ‘ (B) (3 marks) The slope for the graph as plotted in part (A) is :i—l .25 @alculate the €14; m activation energy Ea for this reaction. E a w __ M - 1.25W0q K = " K ' 58.3w 3W”'K"' (C) (2 marks) Rate constant k may be increased either by adding a catalyst or by increasing temperature. A catalyst halves the activation energy and increases reaction rate. How would you change the temperature to get the same rate increase? [Assume that the pre—exponential factor A E /RT __, “a; does not change] ' l “E __,. “’2, 61 F: l A i RA&W,W=€; "3 A e; / 4: Ra‘emffl: A a ...
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