Solutions14

# Solutions14 - Chapter 14 Hints and Selected Solutions...

This preview shows pages 1–4. Sign up to view the full content.

Chapter 14: Hints and Selected Solutions Section 14.1 (page 371) 14.1 One way to do the You Try It is shown in the two worlds below. You should submit different looking worlds. 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
14.2 1. There is exactly one tove. 4. All toves are identical (=). 14.3 1. x y ( Dodec ( x ) Dodec ( y ) x 6 = y ) 4. x y z [ x 6 = y x 6 = z y 6 = z ∧ ¬ Small ( x ) ∧ ¬ Small ( y ) ∧ ¬ Small ( z ) v ( ¬ Small ( z ) ( v = x v = y v = z ))] 14.6 1. x y ( Tet ( x ) Tet ( y ) x 6 = y ) 4. x y z [ x 6 = y x 6 = z y 6 = z Dodec ( x ) Dodec ( y ) Dodec ( z )] 7. x ( Tet ( x ) → ∃ yBackOf ( x , y )) 10. x ( Dodec ( x ) ( Small ( x ) Medium ( x ) Large ( x )) Section 14.2 (page 377) 14.10 Hint (fill in the justifications if you use this proof): 14.14 Hint: The argument is not valid. 14.15 Hint: This argument is valid. 2
14.17 Correction: This problem has an extra negation in its statement. It should be stated as follows: ¬∃ n + 1 x S ( x ) ↔ ∃ n x S ( x ) 14.22 We want to give an informal proof of ! x [ x 2 - 2x + 1 = 0 ].

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern