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Unformatted text preview: Valencia (drv252) – assignment 2 – luecke – (58600) 1 This printout should have 15 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Locate the points given in polar coordinates by P parenleftBig 2 , 1 4 π parenrightBig , Q parenleftBig 1 , 1 2 π parenrightBig R parenleftBig 4 , 3 4 π parenrightBig , among 2 4 2 4 2 4 2 4 b u b c r u t r s 1. b u t b c P : Q : R : 2. b u t b c P : Q : R : 3. b u t b c P : Q : R : correct 4. b u t b c P : Q : R : 5. b u t b c P : Q : R : 6. b u t b c P : Q : R : Explanation: To convert from polar coordinates to Carte sian coordinates we use x = r cos θ , y = r sin θ . For then the points P parenleftBig 2 , 1 4 π parenrightBig , Q parenleftBig 1 , 1 2 π parenrightBig R parenleftBig 4 , 3 4 π parenrightBig , correspond to b u t b c P : Q : R : in Cartesian coordinates. keywords: polar coordinates, Cartesian coor dinates, change of coordinates, 002 10.0 points Which, if any, of A. (4 , π/ 3) , B. (4 , 7 π/ 3) , C. ( 4 , 4 π/ 3) , are polar coordinates for the point given in Cartesian coordinates by P (2 , 2 √ 3)? 1. B and C only 2. C only 3. none of them 4. A only 5. A and B only 6. A and C only 7. all of them correct 8. B only Explanation: To convert from Cartesian coordinates to polar coordinates we use the relations: x = r cos θ , y = r sin θ , so that r 2 = x 2 + y 2 , tan θ = y x . For the point P (2 , 2 √ 3) in Cartesian co ordinates, therefore, one choice of r and θ is Valencia (drv252) – assignment 2 – luecke – (58600) 2 r = 4 and θ = π/ 3, but there are equivalent solutions for r < 0 as well as values of θ dif fering by integer multiples of π . For the given choices we thus see that A. TRUE: solution noted already. B. TRUE: differs from π/ 3 by 2 π . C. TRUE: 4 cos(4 π/ 3) = 2 , 4 sin(4 π/ 3) = 2 √ 3 . 003 10.0 points A point P is given in Cartesian coordinates by P (1 , 1). Find polar coordinates ( r, θ ) of this point with r < 0 and 0 ≤ θ < 2 π . 1. parenleftBig √ 2 , 5 π 4 parenrightBig 2. parenleftBig √ 3 , 5 π 4 parenrightBig 3. parenleftBig √ 2 , 3 π 4 parenrightBig correct 4. parenleftBig √ 3 , 3 π 4 parenrightBig 5. parenleftBig √ 3 , 7 π 4 parenrightBig 6. parenleftBig √ 2 , 7 π 4 parenrightBig Explanation: Since the relationship between Cartesian coordinates and polar coordinates is x = r cos θ , y = r sin θ , the point P (1 , 1) in Cartesian coordinates can be given in polar coordinates as P parenleftBig √ 2 , 3 π 4 parenrightBig , 004 10.0 points Find a Cartesian equation for the curve given by the polar equation r + 6 cos θ = 0 . 1. x 2 + ( y 3) 2 + 9 = 0 2. x 2 + ( y + 3) 2 + 9 = 0 3. ( x + 3) 2 + y 2 + 9 = 0 4. ( x + 3) 2 + y 2 = 9 correct 5. ( x 3) 2 + y 2 + 9 = 0 6. x 2 + ( y + 3) 2 = 9 7. x 2 + ( y 3) 2 = 9 8. ( x 3) 2 + y 2 = 9 Explanation: We have to replace r and θ in the polar equation r + 6 cos θ = 0 using the relations...
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This note was uploaded on 03/26/2009 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas at Austin.
 Spring '07
 Holcombe
 Chemistry

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