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quiz2_solution

quiz2_solution - solution to quiz2 1 Four capacitors are...

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solution to quiz2 1. Four capacitors are connected as shown in Fig 1. (a) Find the equivalent capacitance, C eq , between point a and b . (b) Calculate the charge Q on the 20 μF capacitor if a U = 15 V battery is connected across a and b Fig 1 Answer: C eq = 5 . 96 μF ; Q = 89 . 5 μC hint: The equivalent capacitance of C 1 and C 2 is C 12 = 1 1 /C 1 + 1 /C 2 so total equivalent capacitance is C eq = 1 1 /C 4 + 1 / ( C 12 + C 3 ) Charge on C 4 is simply the charge on C eq since it’s connected in serial with the rectangular block, and serially connected capactors share the same amount of charge, which is also the charge of their equivalent capacitor. Another way to see this is that the right end of C 4 is the rightmost end of the whole system, its left end together with the rectangular block being the “left end” of the system. Thus Q = C eq U 2. A uniform electric field of magnitude 250 V/m is directed in the positive x -direction. A 12 μC charge moves from the origin to the point ( x, y )=(20 cm, 50 cm ). What was the change in the potential energy of this charge?
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