quiz5_solution

quiz5_solution - solution to quiz5 1 A solenoid 4.00 cm in...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: solution to quiz5 1. A solenoid 4.00 cm in diameter and 20.0 cm long has 250 turns and carries a current of 15.0 A. Calculate the magnetic flux through the circular cross-sectional area of the solenoid. Answer: 2 . 96 10- 5 Tm 2 hint: The magnetic field inside the solenoid is B = NI/L N is the number of turns and L the length. The flux is thus = BA = NId 2 4 L d is the diameter. 2. A 500-turn circular-loop coil 15.0 cm in diameter is initially aligned so that its axis is parallel to Earths magnetic field. In 2.77 ms, the coil is flipped so that its axis is perpendicular to Earths magnetic field. If an average voltage of 0.166 V is thereby induced in the coil, what is the value of Earths magnetic field at that location? Answer: 52 T hint: The magnitude of induced EMF is |E| = t = NBA t = d 2 NB 4 t so B = 4 E t Nd 2 again, d is the diameter, N the number of turns....
View Full Document

This note was uploaded on 03/27/2009 for the course PHYS 1B taught by Professor Briankeating during the Winter '07 term at UCSD.

Page1 / 3

quiz5_solution - solution to quiz5 1 A solenoid 4.00 cm in...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online