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Unformatted text preview: solution to quiz5 1. A solenoid 4.00 cm in diameter and 20.0 cm long has 250 turns and carries a current of 15.0 A. Calculate the magnetic flux through the circular cross-sectional area of the solenoid. Answer: 2 . 96 10- 5 Tm 2 hint: The magnetic field inside the solenoid is B = NI/L N is the number of turns and L the length. The flux is thus = BA = NId 2 4 L d is the diameter. 2. A 500-turn circular-loop coil 15.0 cm in diameter is initially aligned so that its axis is parallel to Earths magnetic field. In 2.77 ms, the coil is flipped so that its axis is perpendicular to Earths magnetic field. If an average voltage of 0.166 V is thereby induced in the coil, what is the value of Earths magnetic field at that location? Answer: 52 T hint: The magnitude of induced EMF is |E| = t = NBA t = d 2 NB 4 t so B = 4 E t Nd 2 again, d is the diameter, N the number of turns....
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This note was uploaded on 03/27/2009 for the course PHYS 1B taught by Professor Briankeating during the Winter '07 term at UCSD.
- Winter '07