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Beer’s Law Problem
See problem 2.40, page 56 of text for a statement of the problem.
In this problem, we have an example of the solute AND the solvent both absorbing the
520nm light.
In this case, Beer’s Law becomes:
solvent
solvent
solute
so
A
C
A
A
A
+
=
+
=
ε
ln
Thus, for solution #1: we have:
0.449 = A
solute
+ 0.012 or that A
solute
= 0.437
.
Likewise for solution #2, we have
A
solute
= 0.356
.
In the lecture overheads, I called these “corrected” values of absorbance.
We now use A
solute
=
ε
lC to answer the questions posed by the problem.
(a) Calculate the molar absorbtivity assuming a 1cm path length.
(b) Determine C for the second solution
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This note was uploaded on 03/29/2009 for the course CH 201 taught by Professor Warren during the Fall '07 term at N.C. State.
 Fall '07
 Warren
 Chemistry

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