Chp9_PExp9pt12

Chp9_PExp9pt12 - 3 2 1 3 10 04 . 2 1 2 10 02 . 1 H mol e...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Practice Example 9.12 For what time (min) should a 2.56 amp current be run to produce 25 mL of H 2 from the reduction of water at 1.0 atm of pressure and 298K? The reaction is: 1 2 1 2 2 ) ( 2 2 OH g H e O H (1) We need the number of mols of H 2 required from the reaction: 3 1 1 10 02 . 1 ) 298 ( ) 0821 . 0 ( ) 025 . 0 ( ) 00 . 1 ( K K mol atm L L atm RT PV n mol H 2 . (2) Now use reaction stoichiometry to convert to mols of electrons
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3 2 1 3 10 04 . 2 1 2 10 02 . 1 H mol e mol mol electrons (3) Find the amount of charge on this number of electrons and relate to the current: s i n t . 77 56 . 2 ) 96485 ( ) 10 04 . 2 ( 3 note that the unit of time (SI) are seconds. (4) 77.0 seconds = 1.28 minutes....
View Full Document

Ask a homework question - tutors are online