BrookeECE51_08_Analog_Systems

# BrookeECE51_08_Analog_Systems - Chapter 10 Analog Systems...

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Unformatted text preview: Chapter 10 Analog Systems Microelectronic Circuit Design Richard C. Jaeger Travis N. Blalock Chap10 - 1 Chapter Goals Develop understanding of linear amplification concepts such as: Voltage gain, current gain, and power gain Gain conversion to decibel representation Input and output resistances Transfer functions and Bode plots Cutoff frequencies and bandwidth Low-pass, high-pass, band-pass, and band-reject amplifiers Biasing for linear amplification Distortion in amplifiers Two-port representations of amplifiers Use of transfer function analysis in SPICE Chap10 - 2 Example of Analog Electronic System: FM Stereo Receiver Linear functions: Radio and audio frequency amplification, frequency selection (tuning), impedance matching (75- input, tailoring audio frequency response, local oscillator Nonlinear functions: DC power supply(rectification), frequency conversion (mixing), detection/demodulation Chap10 - 3 Amplification: Introduction A complex periodic signal can be represented as the sum of many individual sine waves. We consider only one component with amplitude V s = 1 mV and frequency s with 0 phase (signal is used as reference): Amplifier output is sinusoidal with same frequency but different amplitude V O and phase : v s = V s sin s t v o = V o (sin s t + ) Chap10 - 4 Non-inverting Amplifier: Configuration Input signal is applied to the non-inverting input terminal. Portion of the output signal is fed back to the negative input terminal. Analysis is done by relating voltage at v 1 to input voltage v s and output voltage v o . Chap 11-5 Non-inverting Amplifier:Voltage Gain, Input Resistance and Output Resistance Since i- = and But v id = Since i + = 2 1 1 o v 1 v R R R + = 1 v id v s v =- 1 v s v = 1 2 1 1 2 1 s v o v 1 2 1 s v o v R R R R R v A R R R + = + = = + = = + = i s v in R R out is found by applying a test current source to amplifier output and setting v s = 0 and is identical to the output resistance of inverting amplifier i.e. R out =0 Chap 11-6 Non-inverting Amplifier: Example Problem :Determine the characteristics of given non-inverting amplifier Given Data : R 1 = 3k , R 2 =43k , v s =+0.1 V Assumptions: Ideal op amp Analysis : Since i- = 0, V 53 . 1 ) V 1 . )( 3 . 15 ( s v o v k 3 k 43 1 1 2 1 = = = + = + = v A R R v A A 3 . 33 k 3 k 43 V 53 . 1 1 2 o v o i = + = + = R R Chap 11-7 Amplification: Introduction (cont.) Amplifier output power is: Here, P O = 100 W and R L = 8 Output power also requires output current which is: Input current is given by phase is zero because circuit is purely resistive....
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## BrookeECE51_08_Analog_Systems - Chapter 10 Analog Systems...

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