HW3_solutions_ - Note: Additional problem (solving for T )...

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Note: Additional problem (solving for T θ± ) to 14.86 is 14.85 on 5 th edition text book.
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[solution] Using polar coordinates, F r = T + f = ma r = m ± r ² − r θ ³ 2 ´ F θ = N H = ma θ = m ± r θ ² + 2r ³θ ³ ´ Considering vertical direction (through the paper) for gravity (g) and the normal force ( N g ) F vert = mg + N g = ma vert = 0 Hence, N g = mg From given angular acceleration, θ ² = 6 θ ³ = 6t θ = 3t 2 for initial string length r 0 = 0.4m , and the radius of the fixed cylinder R = 0.05m , similarly to Problem 14.86, r can be expressed
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This note was uploaded on 03/29/2009 for the course MECHENG 240 taught by Professor Perkins during the Spring '09 term at University of Michigan.

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HW3_solutions_ - Note: Additional problem (solving for T )...

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