Questions4answers - III.4 1/[NO 2 ] t = kt + 1/[NO 2 ]...

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Name: Answers Chemistry 008, Spring 2008 Cornell University Dr. Pontrello Due 2/24/08 Questions #4 (Prelim 1 Review) I.1 -8.17 o C I.2 m = 2.70 g; Δ H = 816 J; work = -172 J II.1 6.8 x 10 5 kg III.1 slope = 0.256 M -1 s -1 III.2 Rate = -d[NO 2 ]/dt = k[NO 2 ] 2 ; products do not affect rate (not in rate law) III.3 1.12 x 10 -5 M/s
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Unformatted text preview: III.4 1/[NO 2 ] t = kt + 1/[NO 2 ] III.5 7420 s IV.1 565 M-1 s-1 IV.2 145 kJ/mol IV.3 2 nd order, k units are M-1 s-1 V.1 step 1) forward: Rate = k 1 [O 3 ] step 1) reverse: Rate = k-1 [O 2 ][O] step 2) forward: Rate = k 2 [O 3 ][O] V.2 contains an intermediate V.3 Rate = k[O 3 ] 2 [O 2 ]-1 ; k = k 1 k 2 /k-1...
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