hw 6 answers - Iype Shelby Homework 6 Due Oct 9 2007...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Iype, Shelby – Homework 6 – Due: Oct 9 2007, midnight – Inst: Vandenbout 1 This print-out should have 23 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Here are more questions finishing up Chap- ter 13 and starting Chapter 14. Remember, the HWS could be overloaded with the actual due time arrives Tuesday night. 001 (part 1 of 1) 10 points Consider a 3-atom molecule A B A for which B has a total of only four valence elec- trons – enough to make two bonds. Predict the A-B-A bond angle. 1. 180 correct 2. 109.5 3. 90 4. 60 5. 120 Explanation: 002 (part 1 of 1) 10 points Consider the compound peroxyacetylni- trate, an eye irritant in smog. O N C O O O O CH 3 Predict the indicated bond angle. 1. 109.5 2. 30 3. 120 correct 4. 90 5. 60 Explanation: 003 (part 1 of 2) 10 points Draw the Lewis structure for NO - 2 . How many single bonds, double bonds, triple bonds, and unshared pairs of electrons are on the central atom, in that order? 1. 4; 0; 0; 0 2. None of these 3. 0; 0; 1; 1 4. 1; 0; 1; 0 5. 2; 0; 0; 2 6. 3; 0; 0; 1 7. 2; 1; 0; 0 8. 1; 1; 0; 1 correct 9. 0; 1; 1; 0 10. 0; 2; 0; 0 Explanation: N has 5 valence electrons and O has 6 va- lence electron. The total number of valence electrons in the ion (plus one to account for the ion’s negative charge) is 5 + (2 × 6) + 1 = 18 The Lewis structure for NO - 2 can be found by connecting the oxygen atoms to nitrogen and placing eight electrons around each atom: O N O - and the central atom has one single bond, one double bond, and one unshared pair of electrons. 004 (part 2 of 2) 10 points Determine the molecular geometry of the ion NO - 2 .
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Iype, Shelby – Homework 6 – Due: Oct 9 2007, midnight – Inst: Vandenbout 2 1. bent or angular correct 2. None of these 3. trigonal-pyramidal 4. linear 5. trigonal-bipyramidal 6. trigonal-planar 7. tetrahedral 8. octahedral Explanation: The central atom N has 2 bonding regions and 1 lone pair of electrons. The three areas of high electron density make the electronic geometry trigonal planar and the molecular geometry bent or angular: N O O 005 (part 1 of 1) 10 points Which of the following molecules has the largest dipole moment?
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern