chapter23 - 3/14/2009 Mirrors and Lenses Second mid-term:...

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3/14/2009 1 Mirrors and Lenses Second mid-term: 8:00am, Sat., March 21 (2 hours) Room assignment (based on your last name): A - F : Knox 20 G - I : NSC 215 J - K : NSC 220 L - N : Knox 110 O - Q: NSC 210 R - U: Knox 109 V - Z: Hochstetter 114 In-class review section: Fri. March 20 Students with Organic Chemistry exam conflict - Contact your Organic Chemistry instructor at the earliest to work out the make-up exam schedule. - You ARE NOT allowed to take the physics make-up exam.
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3/14/2009 2 Virtual images: form at the point where rays of appear to originate (diverge from) - cannot be display on screen Real image : form at the point where rays of light intersect (actually pass through) - can be displayed on screen Virtual image Real image Law of reflection, Triangles PQR and P’QR are identical: - object distance = image distance - Lateral magnification M ' ' O I | | q p 1 ' heigh object height image h h M
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3/14/2009 3 The image is virtual ; upright (same orientation as the object) The image is behind the mirror: p = |q| The image is unmagnified (h ’ = h and M = 1) There is an apparent left-right reversal in the image Ambulances have “AMBULANCE” written backwards Minimum height of a mirror to see your full height. Positions: - Top of the head: F - Eye: C - Foot: A (a) To see top of your head: E must be mid-point between top of your head and your eyes (b) To see your feet: B must be mid point between your eyes and your feed h
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3/14/2009 4 Therefore, Since h DC AD 2 / 2 / ) ( CF DC AD d 2 / CF DC BE d 2 / 2 / ) ( h CF DC AD You are standing in front of a short flat mirror . You can you your head but can’t see your shoes. To see your shoes, you may (1) move closer to the mirror. (2) move further from the mirror. (3) lower the mirror
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3/14/2009 5 Moving closer does not help! To see feet, bottom of mirror must extend at least as low as midpoint between eyes and feet independent on how far you are from the mirror. A spherical mirror: segment of a sphere Concave spherical mirror Convex spherical mirror
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3/14/2009 6 R: radius of curvature C: center of curvature V: center of the spherical segment Principle axis : A line drawn from C to V V Consider two rays from the object - one passes through C - the other hits point V, reflected back onto itself - The intersect of the reflected rays gives the image point Geometry: q h p h ' ) tan( ) 1 ( R p h ) tan( ) 2 ( q R h ' ) tan( ) 3 (
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This note was uploaded on 03/30/2009 for the course PHY 102 taught by Professor Luo during the Spring '08 term at SUNY Buffalo.

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chapter23 - 3/14/2009 Mirrors and Lenses Second mid-term:...

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