class_15(E_boundary_value)

class_15(E_boundary_value) - Resistor and Capacity s...

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Resistor and Capacity s E dl V R I E dS = = σ ⋅ ∫∫ r r r r Ò Resistor: (-) (+) s E s E dS Q C V E dl ε ⋅ = = ∫∫ r r r r Ò Capacitance (2) (1) s E Energy of Cap: 2 2 1 1 Q W C V V Q 2 2 2C = = =
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Calculate capacitance Let two conductor carry charge +Q and –Q, respectively Determine E field using Gaussian’s law or Coulomb's law Find voltage (potential difference) from E field using: Calculate cap using C=Q/V V E dl = r r
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Parallel plate cap Dielectric ε +Q -Q s Q /S ρ = Calculate E-field: Surface charge density: E-field: s E / = ρ ε E S ε
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Parallel plate cap Dielectric ε +Q -Q s Q /S ρ = E-field: Surface charge density: E-field: s E / = ρ ε Potential difference E b a V E dl E d = = r r Cap: S C Q / V d ε = = E-field energy: 2 S W Q 2d ε = S ε
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Coaxial Cap Calculate E-field: Gauss’s law: Q / L E e 2 ρ = π⋅ε⋅ρ r r Dielectric ε Q -Q a L b
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Calculate E-field: Gauss’s law: Q / L E e 2 ρ = π⋅ε⋅ρ
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This note was uploaded on 03/30/2009 for the course ECE 335 taught by Professor Yifeili during the Fall '08 term at UMass Dartmouth.

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class_15(E_boundary_value) - Resistor and Capacity s...

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