homework 13

# homework 13 - Homework 13 Problem 1 Constants R = 1.987...

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Homework 13 Vera Lee ChE 210 - 9 am 12.3.08 Problem 1 Constants: Data: Temperature, K 1/T Reaction Rate, mol/s ln(rate) 253 0.00395 0.12 -2.12026 258 0.00388 0.17 -1.77196 263 0.00380 0.24 -1.42712 268 0.00373 0.34 -1.07881 273 0.00366 0.48 -0.73397 278 0.00360 0.66 -0.41552 283 0.00353 0.91 -0.09431 288 0.00347 1.22 0.19885 293 0.00341 1.64 0.49470 298 0.00336 2.17 0.77473 303 0.00330 2.84 1.04380 308 0.00325 3.70 1.30833 equation of linear trendline: y = -4887.2x + 17.171 Calculations: slope = -E/R R = 1.987 cal/(g mol K)  ln( rate ) = ln - ( E / R )(1/ T ) y-intercept = ln k ln k  = 17.171 k  = e^17.171 k  = 28659627.99  - E / R  = -4887.2  - E /1.987 = -4887.2 E  = -9710.87

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Vera Lee ChE 210 - 9 am 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 0.0038 0.0039 0.0040 -2.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 f(x) = -4887.23x + 17.17 Oxygenation Reaction Rate vs. 1/Temperature 1/Temperature ln(rate)
Vera Lee ChE 210 - 9 am 0.0032 0.0033 0.0034

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## This note was uploaded on 03/31/2009 for the course CHE 210 taught by Professor Swinnea during the Spring '08 term at University of Texas.

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homework 13 - Homework 13 Problem 1 Constants R = 1.987...

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