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solution_pdf HW 1 - rahman(pr5989 Homework 1 owers(53880...

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rahman (pr5989) – Homework 1 – flowers – (53880) 1 This print-out should have 26 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points What is responsible for the abnormally high melting and boiling points of water? 1. ionic bonding 2. hydrogen bonding correct 3. covalent bonding 4. dispersion bonding Explanation: H-bonds are a special case of very strong dipole-dipole interactions. They only occur when H is bonded to small, highly electroneg- ative atoms – F, O or N only. 002 10.0 points Based on the types and strengths of in- termolecular forces present, place the com- pounds C 6 H 14 , C 3 H 8 , C 5 H 11 OH , C 5 H 11 Cl , CaBr 2 in order from lowest to highest boiling point (lowest on the left, highest on the right). 1. CaBr 2 , C 5 H 11 OH , C 5 H 11 Cl , C 6 H 14 , C 3 H 8 2. C 3 H 8 , C 6 H 14 , C 5 H 11 OH , C 5 H 11 Cl , CaBr 2 3. C 6 H 14 , C 3 H 8 , C 5 H 11 OH , C 5 H 11 Cl , CaBr 2 4. CaBr 2 , C 5 H 11 Cl , C 6 H 14 , C 5 H 11 OH , C 3 H 8 5. C 3 H 8 , C 6 H 14 , C 5 H 11 Cl , C 5 H 11 OH , CaBr 2 correct 6. C 3 H 8 , C 5 H 11 OH , C 6 H 14 , C 5 H 11 Cl , CaBr 2 Explanation: C 3 H 8 and C 6 H 14 have only dispersion forces, the weakest type of intermolecular forces. C 6 H 14 has a higher molecular weight and will therefore have stronger dispersion forces. C 4 H 11 Cl and C 5 H 11 OH are both approx- imately the same size as C 6 H 14 and would therefore have about the same strength of dis- persion forces. C 4 H 11 Cl also has dipole-dipole interactions, stronger than dispersion forces. C 5 H 11 OH also has H - bonding, stronger than dipole-dipole interactions. CaBr 2 is ionic and has interionic forces, the strongest type of intermolecular forces. The stronger the intermolecular forces, the higher the boiling point. 003 10.0 points The temperature of a sample increases at its boiling point until all the liquid has been va- porized. 1. True 2. False correct Explanation: At its boiling point, if heat is applied to a sample of liquid, it will undergo a liquid gas phase change with no change in temperature until all of the liquid has evaporated. 004 10.0 points Order NaCl C 6 H 6 (benzene) CH 4 (methane) MgO H 2 O O 3 (ozone) by increasing evaporation rate. 1. NaCl < CH 4 < O 3 < MgO < H 2 O < C 6 H 6 2. C 6 H 6 < MgO < CH 4 < NaCl < H 2 O < O 3 3. H 2 O < C 6 H 6 < NaCl < O 3 < MgO < CH 4 4. CH 4 < C 6 H 6 < O 3 < NaCl < H 2 O < MgO 5. C 6 H 6 < CH 4 < O 3 < H 2 O < MgO < NaCl
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rahman (pr5989) – Homework 1 – flowers – (53880) 2 6. MgO < NaCl < H 2 O < O 3 < C 6 H 6 < CH 4 correct 7. H 2 O < O 3 < MgO < C 6 H 6 < CH 4 < NaCl Explanation: 005 10.0 points Predict which of the following liquids has the LOWEST enthalpy of vaporization. 1. H 2 Se 2. H 2 S correct 3. H 2 O 4. H 2 Te 5. H 2 Po Explanation: 006 10.0 points Benzene is a hydrocarbon that is commonly used as a commercial solvent. However, it is carcinogenic; i.e. , accumulations in the body can cause cancer. What is the vapor pressure of benzene at 27 C (about room tempera- ture)? The normal boiling point of benzene is 80 C and its molar heat of vaporization is 30.8 kJ/mol.
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